I have jobs and countries table
Table - Jobs
Column name = pickup_region1
Table - Countries
Column name = id
I am using find query on job table..
How to associate country table on job model so that when I run select query on job it automatically bind this relation
jobs.country_id = Countries.id
class Job extends AppModel {
public $belongsTo = array(
'country' => array(
'className' => 'country',
'primaryKey' => 'id',
'foreignKey' => 'country_id',
'dependent' => true,
'conditions' => '',
'fields' => '',
'order' => '',
'limit' => '',
'offset' => '',
'exclusive' => '',
'finderQuery' => '',
'counterQuery' => ''
) );
}
Model for countries should be: Country.php for table countries,
when you stick to convention, this statment is enought:
public $belongsTo = array('Country');
If you have $recursive set to -1, you need to tell cake which association should use when, like that:
(more about $recursive)
$this->Job->contain(array('Country'));
And next query on Job will arrive with Country
You can also contain inside find query:
$this->Job->find('all', array(
...
'contain' => array('Country')
));
more info
Related
hello I have three tables in my database. Country, State,and City. In state table there is a country_id as foreign key and in city table there is state_id as foreign key. The problem is I want to get the country name when I am querying in the city table. I'll share the code so you can fully understand
Country.php
class Country extends AppModel{
public $useTable = 'countries';
}
State.php
class City extends AppModel{
public $useTable = 'cities';
public $belongsTo = array(
'State' => array(
'className' => 'State',
'foreignKey' => 'state_id',
'fields' => array('state.id','state.name')
)
);
}
City
class State extends AppModel{
public $useTable = 'states';
public $belongsTo = array(
'Country' => array(
'className' => 'Country',
'foreignKey' => 'country_id',
'fields' => array('Country.id','Country.name','Country.short_name')
)
);
okay here is the code. If I use this query
$this->State->find('all', array(
'conditions' => array(
'state.country_id' => $country_id
),
I can get the country name from country table. same is the case If I do this in city table like this
$this->City->find('all', array(
'conditions' => array(
'city.state_id' => $state_id
),
I can get all the state names city names here. So Now in this same table in one query how I can get the country name as well ?
Try using the recursive property.
Setting $this->City->recursive = 2 gets associated data for the table and associated data on the associated tables.
$this->City->recursive = 2;
$this->City->find('all', array(
'conditions' => array(
'city.state_id' => $state_id
),
//other stuff you use in this find
));
You can also using the "joins" flag.
$this->City->find('all', array(
'conditions' => array(
'City.state_id' => $state_id
),
'joins' => array(
array(
'table' => 'states',
'alias' => 'State',
'type' => 'left',
'conditions' => 'State.id = City.state_id'
),
array(
'table' => 'countries',
'alias' => 'Country',
'type' => 'left',
'conditions' => 'Country.id = State.country_id'
)
),
'fields' => array('City.id', 'State.name', 'Country.name',
//include all the fields you need
)
));
See: http://book.cakephp.org/2.0/en/models/model-attributes.html#recursive
In addition to the first answer, make sure to contain the foreign key for the Country.
class City extends AppModel{
public $belongsTo = array(
'State' => array(
'className' => 'State',
'foreignKey' => 'state_id',
'fields' => array('State.id','State.name', 'State.country_id'), // Make sure to contain the foreign key for the `Country`.
)
);
}
For your information, you can also use ContainableBehavior instead of recursive.
http://book.cakephp.org/2.0/en/core-libraries/behaviors/containable.html
I am new to cake php . Please be cool with me . I am trying to fetch the data from the two table ce_actionitems and ce_projects.
i want to fetch the data from action items . my model is
public $hasOne = array(
'Project' => array(
'className' => 'Project',
'foreignKey' => 'id',
'joinTable' => 'actionitems',
'unique' => 'keepExisting',
'associatedKey' => 'project_id',
'conditions' => '',
'fields' => '',
'order' => '',
'limit' => '',
'offset' => '',
'finderQuery' => '',
'deleteQuery' => '',
'insertQuery' => ''
)
);
but is is returning the null data because it is matching id in projects with id in action items. this is the generated query
LEFT JOIN EB.ce_projects AS Project ON (Project.id =
Actionitems.id)
but i want this to be
LEFT JOIN EB.ce_projects AS Project ON (Project.id =
Actionitems.project_id)
i got this working if i mention public $primaryKey = 'project_id'; in my Actionitems but then it stop inserting the action items.
any help will be appriciated.
mention 'project_id' as foreign key in Actionitems
I'm a newbie to cakePHP and I've taken on creating a very small "status reporting" project, that would allow a user to report their current status on a project that they were assigned on.
I'm currently using the acl, auth, and session components to allow for multiple tier users to manage one another with an admin creating users, projects, and assigning them to one another. I have also fixed it so that when a user is logged in and goes to add a "status" that their login session automatically takes care of the "user_id" for the status:
$this->data['Status']['user_id'] = $this->Auth->user('id');
What I need help doing now is filter the options for the project that the user can pick to add a "status" to.
I currently have a setup with a table that holds the relationships between users and projects named *projects_users* with *id, project_id, user_id* as fields. But, after baking this setup, when the user is adding a "status" the drop down menu provides all projects rather than strictly the ones they are "assigned to."
I would like to filter the user's options to the projects that they are assigned to. Is there considerable more relationships I should be setting up or is this a pretty easy little function to write? Any help would be greatly appreciated and if I have left out information, I'd be glad to post anything else.
Here is the Status Model setup:
class Status extends AppModel {
var $name = 'Status';
//The Associations below have been created with all possible keys, those that are not needed can be removed
var $belongsTo = array(
'User' => array(
'className' => 'User',
'foreignKey' => 'user_id',
'conditions' => '',
'fields' => '',
'order' => ''
),
'Project' => array(
'className' => 'Project',
'foreignKey' => 'project_id',
'conditions' => '',
'fields' => '',
'order' => ''
)
);
}
My User Model looks like this:
var $belongsTo = array(
'Group' => array(
'className' => 'Group',
'foreignKey' => 'group_id',
'conditions' => '',
'fields' => '',
'order' => ''
)
);
var $hasMany = array(
'Status' => array(
'className' => 'Status',
'foreignKey' => 'user_id',
'dependent' => false,
'conditions' => '',
'fields' => '',
'order' => '',
'limit' => '',
'offset' => '',
'exclusive' => '',
'finderQuery' => '',
'counterQuery' => ''
)
);
var $hasAndBelongsToMany = array(
'Project' => array(
'className' => 'Project',
'joinTable' => 'projects_users',
'foreignKey' => 'user_id',
'associationForeignKey' => 'project_id',
'unique' => true,
'conditions' => '',
'fields' => '',
'order' => '',
'limit' => '',
'offset' => '',
'finderQuery' => '',
'deleteQuery' => '',
'insertQuery' => ''
)
);
In the database, You should have a column called project_id in the user table that is associated with the project table's id column.
Then, in your User model, you should create a hasMany relationship with the Project model.
class User extends AppModel {
var $name = 'User';
var $hasMany = 'Project';
}
Now, when you fetch a particular user, you will get all projects that the user is associated with.
I'm trying to search based on a field in a related model. I can do so with the belongsTo model, but not the hasMany model. I'm sure this is something simple I'm overlooking but I can't see it. Could someone point me in the right direction (or even the cakebook page I need - searched, but didn't find anything that looked like this). Thanks
In groups controller: (this doesn't work)
$group = $this->Group->find('all', array('conditions' => array('Voucher.id' => '55')));
This does:
$group = $this->Group->find('all', array('conditions' => array('TourOperator.id' => '3')));
Background file snippets:
Group model:
var $belongsTo = array(
'TourOperator' => array(
'className' => 'TourOperator',
'foreignKey' => 'tour_operator_id',
'conditions' => '',
'fields' => '',
'order' => ''
)
);
var $hasMany = array(
'Voucher' => array(
'className' => 'Voucher',
'foreignKey' => 'group_id',
'dependent' => true,
'conditions' => '',
'fields' => '',
'order' => 'Voucher.date, Voucher.meal_type_id'
)
);
Voucher model:
var $belongsTo = array(
'Group' => array(
'className' => 'Group',
'foreignKey' => 'group_id',
'conditions' => '',
'fields' => '',
'order' => ''
)
);
Tour Operator model:
var $hasMany = array(
'Group' => array(
'className' => 'Group',
'foreignKey' => 'tour_operator_id',
'dependent' => false,
'conditions' => '',
'fields' => '',
'order' => '',
'limit' => '',
'offset' => '',
'exclusive' => '',
'finderQuery' => '',
'counterQuery' => ''
)
);
Update (as posted in comment below, but clearer to read here)
I've ended up using this.
$groups = $this->Group->Voucher->find('all', array('fields' => 'DISTINCT group_id', 'conditions' => array('Voucher.status' => 'pending')));
$group_ids = Set::extract($groups, '/Voucher/group_id');
$data = $this->Group->find('all', array('conditions' => array('Group.id' => $group_ids)));
I get a distinct list of group IDs matching my criteria, create an array of just the IDs and then use that to pull the groups so that the arrays are ordered as I expect them in my view.
Can you recast your query to $this->Voucher->find, and then use the associated Group data returned from that query? As you say, there's no problem finding groups by their TourOperator id, and the Groups/Voucher relationship looks like it's the inverse of that.
With CakePHP's Containable behaviour you can't use conditions on related data in hasMany and hasAndBelongsToMany associations. This is because it uses seperate queries to get those associations.
With the Linkable behaviour, however, you can use data from hasMany associations to filter records. The behaviour can be downloaded here: https://github.com/Terr/linkable
Linkable uses standard JOINs to, well, join related data. This means it doesn't pull in all the related data (ie, all the Vouchers related to your Group(s)), just like a normal SELECT. However, it can work together with Containable to do both.
You can find examples of how Linkable works in the README.
(disclaimer: I currently maintain Linkable, but that is not the reason I point to it)
I'm working on a CakePHP 1.2 application. I have a model "User" defined with a few HABTM relationships with other tables through a join table.
I'm now tasked with finding User information based on the data stored in one of these HABTM tables. Unfortunately, when the query executes, my condition is rejected with an error about a missing table. Upon inspection it seems that CakePHP is not including any of the HABTM tables in the select statement.
My User HABTM relationship is as follows:
var $hasAndBelongsToMany = array(
'Course' => array(
'className' => 'Course',
'joinTable' => 'course_members',
'foreignKey' => 'user_id',
'associationForeignKey' => 'course_id',
'conditions' => '',
'order' => '',
'limit' => '',
'uniq' => false,
'finderQuery' => '',
'deleteQuery' => '',
'insertQuery' => ''
),
'School' => array(
'className' => 'School',
'joinTable' => 'school_members',
'foreignKey' => 'user_id',
'associationForeignKey' => 'school_id',
'conditions' => '',
'order' => '',
'limit' => '',
'uniq' => false,
'finderQuery' => '',
'deleteQuery' => '',
'insertQuery' => ''
),
'Team' => array(
'className' => 'Team',
'joinTable' => 'team_members',
'foreignKey' => 'user_id',
'associationForeignKey' => 'team_id',
'conditions' => '',
'order' => '',
'limit' => '',
'uniq' => false,
'finderQuery' => '',
'deleteQuery' => '',
'insertQuery' => ''
)
);
The error is:
SQL Error: 1054: Unknown column
'School.name' in 'where clause'
And finally, the query it is trying to execute
SELECT
`User`.`id`, `User`.`username`, `User`.`password`, `User`.`firstName`, `User`.`lastName`, `User`.`email
`, `User`.`phone`, `User`.`streetAddress`, `User`.`city`, `User`.`province`, `User`.`country`, `User
`.`postal`, `User`.`userlevel`, `User`.`modified`, `User`.`created`, `User`.`deleted`, `User`.`deleted_date
` FROM `users` AS `User` WHERE `User`.`id` = 6 AND `School`.`name` LIKE '%Test%' LIMIT 1
Turn your debug level up to 2 and look at the SQL output. Find the query that your code is generating and you'll notice there are several. The ORM layer in CakePHP doesn't join HABTM related tables in the first query. It gets the results from the first select, then separately fetches the HABTM data for each item. Because the join table is not in the first query, your condition, which is intended for use on a joined table, results in the error you are seeing.
The cook book has a section on HABTM associations and fetching data based on conditions in the HABTM table that will fit your requirements.
From the Cookbook: http://book.cakephp.org/view/83/hasAndBelongsToMany-HABTM
One option is to search the Tag model (instead of Recipe), which will also give us all of the associated Recipes.
$this->Recipe->Tag->find('all', array(
'conditions' => array('Tag.name' => 'Dessert')));
We could also use the join table model (which CakePHP provides for us), to search for a given ID.
$this->Recipe->bindModel(array('hasOne' => array('RecipesTag')));
$this->Recipe->find('all', array(
'fields' => array('Recipe.*'),
'conditions' => array('RecipesTag.tag_id' => 124) // id of Dessert
));
It's also possible to create an exotic association for the purpose of creating as many joins as necessary to allow filtering, for example:
$this->Recipe->bindModel(array('hasOne' => array('RecipesTag',
'FilterTag' => array(
'className' => 'Tag',
'foreignKey' => false,
'conditions' => array('FilterTag.id = RecipesTag.tag_id')
))));
$this->Recipe->find('all', array(
'fields' => array('Recipe.*'),
'conditions' => array('FilterTag.name' => 'Dessert')
));
Your table should be called "schools_users" and not "school_members" because it's many-to-many, thus using the plural form in the table name on both sides is appropiate.
You also set the Model ClassName "School" as Alias for the HABTM. You should change that to something more generic like "Schools" as in "User is in and has many SchoolS" to avoid conflicts.
And another hint: Try to find the user "via" the School Model rather than the User Model.
$this->User->Schools->find()
Hope this helps.
FWIW, your join tables do appear to be "oddly named" insofar as they don't follow the convention described here:
http://book.cakephp.org/view/83/hasAndBelongsToMany-HABTM
In any case, good luck, I remember HABTM being a butt-pain in CakePHP.