Get php checkbox data from multiple tables - php

Question

First I will tell what I want to achieve, and then I will explain how I was trying to do it.
I have two tables, one stores type of vessels with a description and their own Id. Then I have another table in wich the vessel type has been stored as text. My goal is to select each one (both records in both tables) with a checkbox in both and store in the table 2 the Id from the table 1.
I will introduce data, to help.
Table 1
1|Balandra|Some description
2|Bergantin|Some description
3|Whatever |Whatever.....
Table2
Balandra
Bergantin
Whatever
Then, I have created a php page that shows both tables with the checkbox I mentioned above. Checkboxes store the Table1 Id and Table2 vesseltypename.
<table class="table table-striped table-bordered table-list">
<thead>
<tr>
<th><em class="fa fa-cog"></em></th>
<th class="hidden-xs">idtiponavio</th>
<th>Tipo de Navío</th>
<th>Descripción</th>
<th>Agrupar</th>
</tr>
</thead>
<tbody>
<?php foreach ($naviosdyncoop as $key => $navio) { ?>
<tr>
<td align="center">
<a href=<?php echo '../vista/modificar.php?id=' .
$navio['idtiponavio']; ?> class="btn btn-default"><em class="fa fa-
pencil"></em></a>
<a href=<?php echo '../datos/borrar.php?id=' .
$navio['idtiponavio']; ?> class="btn btn-default"><em class="fa fa-
trash"></em></a>
</td>
<td class="hidden-xs"><?php echo
$navio['idtiponavio']; ?></td>
<td><?php echo $navio['tiponavio']; ?></td>
<td><?php echo $navio['descripcion']; ?></td>
<td><input type="checkbox" name="agruparid" value=<?
php echo $navio['idtiponavio']; ?> /></td>
</tr>
<?php } ?>
</tbody>
</table>
</div>
</div>
<div class="col-md-6">
<div class="panel-body paneltodo">
<table class="table table-striped table-bordered table-list">
<thead>
<tr>
<th><em class="fa fa-cog"></em></th>
<th>Tipo de Navío</th>
<th>Agrupar</th>
</tr>
</thead>
<tbody>
<?php foreach ($naviosforsea as $key => $navio) { ?>
<tr>
<td align="center">
<em class="fa fa-arrow-circle-o-left"></em>
</td>
<td><?php echo $navio['typevessel']; ?></td>
<td><input type="checkbox" name="agruparvessel" value=<?php echo $navio['typevessel']; ?> /></td>
</tr>
<?php } ?>
</tbody>
</table>
So, I want to check both table records and store the table1 Id in the table2 idtypevessel field.
I thought that a php file could store both items and call the update function with those parameters, like this:
<?php
require './modelo.php';
$idnavio = $_GET['agruparid'];
$vessel = $_GET['agruparvessel'];
Any suggestions, because I think I have to do a button to submit this parameters, but it must be working on both tables, and I don't know how to access both foreach loop at the same time.
Thanks in advance.

Answer 1

E. Salas
review bellow reference code to submit multi selected checkbox values
for multi selected checkbox submission you must use [] operator after name attribute in html
index.php
<form action="/checkbox.php" method="post">
<strong>Cars:</strong><br>
<?php
$cars = array("Volvo", "BMW", "Toyota");
$colors = array("Red", "Green", "Black");
foreach($cars as $single){
?>
<input type="checkbox" name="cars[]" value="<?php echo $single; ?>">
<?php
}
<br>
<strong>colors:</strong><br>
foreach($colors as $single){
?>
<input type="checkbox" name="colors[]" value="<?php echo $single; ?>">
<?php
}
?>
<br>
<input type="submit" value="Submit!">
</form>
checkbox.php
<?php
echo "<pre>";
var_dump($_POST);
exit;
In your case:
<form action="/checkbox.php" method="post">
<div class="col-md-6">
<div class="panel-body">
<table class="table table-striped table-bordered table-list">
<thead>
<tr>
<th><em class="fa fa-cog"></em></th>
<th class="hidden-xs">idtiponavio</th>
<th>Tipo de Navío</th>
<th>Descripción</th>
<th>Agrupar</th>
</tr>
</thead>
<tbody>
<?php foreach ($naviosdyncoop as $key => $navio) { ?>
<tr>
<td align="center">
<em class="fa fa-pencil"></em>
<em class="fa fa-trash"></em>
</td>
<td class="hidden-xs"><?php echo $navio['idtiponavio']; ?></td>
<td><?php echo $navio['tiponavio']; ?></td>
<td><?php echo $navio['descripcion']; ?></td>
<td><input type="checkbox" name="agruparid[]" value=<?php echo $navio['idtiponavio']; ?> /></td>
</tr>
<?php } ?>
</tbody>
</table>
</div>
</div>
<div class="col-md-6">
<div class="panel-body">
<table class="table table-striped table-bordered table-list">
<thead>
<tr>
<th><em class="fa fa-cog"></em></th>
<th>Tipo de Navío</th>
<th>Agrupar</th>
</tr>
</thead>
<tbody>
<?php foreach ($naviosforsea as $key => $navio) { ?>
<tr>
<td align="center">
<em class="fa fa-arrow-circle-o-left"></em>
</td>
<td><?php echo $navio['typevessel']; ?></td>
<td><input type="checkbox" name="agruparvessel[]" value=<?php echo $navio['typevessel']; ?> /></td>
</tr>
<?php } ?>
</tbody>
</table>
</div>
</div>
<input type="submit" value="Submit!">
</form>

Answer 2

Finally I solved this with Javascript. One of my partners helped me, I post this to help people in my situation.
I created a script, here is the code:
<script type="text/javascript">
function cogeNavioDyncoopnet(){
var checkedValueNavioD = null;
var inputElements = document.getElementsByClassName('checknaviod');
for(var i=0; inputElements[i]; ++i){
if(inputElements[i].checked){
checkedValueNavioD = inputElements[i].value;
break;
}
}//return checkedValueNavioD;
var input_nav_dyn = document.getElementById("nav_dyn");
input_nav_dyn.value = checkedValueNavioD;
}
function cogeNavioForSea(){
var checkedValueNavioFs = null;
var inputElements = document.getElementsByClassName('checknaviofs');
for(var i=0; inputElements[i]; ++i){
if(inputElements[i].checked){
checkedValueNavioFs = inputElements[i].value;
break;
}
}//return checkedValueNavioFs;
var input_nav_fs = document.getElementById("nav_fs");
input_nav_fs.value = checkedValueNavioFs;
}
</script>
Then I created a Form below, that collects values and sends them to my .php control file.
<div class="hidden-xs">
<form class="hidden-xs" method="POST"
action="../datos/actualizarnavios.php">
<input id="nav_dyn" type="text" name="idnaviodyncoop">
<input id="nav_fs" type="text" name="navioforsea" >
<input id="botonasignar" type="submit" name="enviardatosdynfs">
</form>
</div>
I hope this helps. Thanks for the feedback, as always.