JSON & Array get data with PHP [duplicate] - php

Question

This question already has an answer here:
How to extract and access data from JSON with PHP?
(1 answer)
Closed 5 years ago.
I have a question about some JSON and PHP, see json below.
How can I get the number string?
{
”data”: [
{
”numbers”: [
{
”number”: "XXXX",
”type”: ””
}
]
}
]
}
Ive tried with the following but its not working:
$item['numbers'][0]->number;
Note, the $item array is ok. I just do not know what is wrong here.
EDIT:
I should point out that there was an json_decode before.
So the structure looks like this:
Array
(
[0] => Array
(
[number] => XXXX
[type] =>
)
)
print_r($item['numbers']);
This doesn't work: $item['numbers'][0]['number'];
Error: Undefined offset: 0 in
Thanks!

Answer 1

if you want to direct access then use this code
$items->data->numbers->number;
you can use php json_decode().it takes a JSON encoded string and converts it into a PHP variable.
<?php
$json_data = '{
"data": [
{
"numbers": [
{
"number": "11",
"Type": ""
}
]
}
]
}';
$array=json_decode($json_data,true);
echo "<pre>";
print_r($array);
echo $array["data"][0]["numbers"][0]["number"];
then output
Array
(
[data] => Array
(
[0] => Array
(
[numbers] => Array
(
[0] => Array
(
[number] => 11
[Type] =>
)
)
)
)
)
Number:11

Answer 2

To get the number try this :
$myJSON->data->numbers->number;

Answer 3

Hope this will help you out... You are trying to access which does not actually exists.
try this code snippet here
<?php
ini_set('display_errors', 1);
$month_options = '{
"data": [
{
"numbers": [
{
"number": "10",
"Type": ""
}
]
}
]
}';
$array=json_decode($month_options,true);
echo $array["data"][0]["numbers"][0]["number"];

Answer 4

Use the json_decode() function of PHP.
$array = json_decode('{
”data”: [
{
”numbers”: [
{
”number”: "",
”Type”: ””
}
]
}
]
}', true);
Then you could access it as $array["data"]["numbers"]["number"];