json_encode for more than 2 arrays - php

Question

I have 2 tables to be retrieved from database with 2 different queries and needs to be encoded in json and send to ajax.The issue is I am not able to pass 2 json's to ajax .
I have tried with echo json_encode(array($data1,$data2)); but it is not working.
//My php code
$query = $db->query("select * from table1 where valu1='".$value1."'");
while ($row = $query->fetch_assoc()) {
$data1['value1'] = $row['value1'];
$data1['value2'] = $row['value2'];
}
$query = $db->query("select * from table2 where value2='".$value2."' ");
while ($row = $query->fetch_assoc()) {
$data2['value2'] = $row['value2'];
$data2['value3'] = $row['value3'];
}
echo json_encode(array($data1,$data2));
//My AJAX code
$(document).ready(function(){
$('#Form').submit(function(e){
e.preventDefault(); // stops the form submission
$.ajax({
url:$(this).attr('action'), // action attribute of form to send the values
type:$(this).attr('method'), // method used in the form
data:$(this).serialize(), // data to be sent to php
dataType:"json",
success:function(data){
//main
alert(data.value1);
},
error:function(err){
alert(err);
}
});
});
});
Kindly help in solving this issue.Thanks in advance

Answer 1

In PHP:
echo json_encode(array($data1, $data2));
In AJAX:
var data1 = data[0];
var data2 = data[1];
$.each(data1, function() {
console.log(this.value1 + ',' + this.value2);
});
$.each(data2, function() {
console.log(this.value2 + ',' + this.value3);
});
EDIT:
After a whole year, I just noticed that the initial PHP code was wrong, because the loop for the sql result would overwrite each time the values of the array. So, the correct one is this:
$query = $db->query("select * from table1 where valu1='".$value1."'");
while ($row = $query->fetch_assoc()) {
$data1[] = array('value1' => $row['value1'], 'value2' => $row['value2']);
}
$query = $db->query("select * from table2 where value2='".$value2."' ");
while ($row = $query->fetch_assoc()) {
$data2[] = array('value2' => $row['value2'], 'value3' => $row['value3']);
}
echo json_encode(array($data1,$data2));

Answer 2

Your code is fine, you just have to handle the two arrays within your success function:
success: function(data){
var object1 = data[0];
var object2 = data[1];
// Do whatever you like to do with them
}