Laravel api route class to found error - php

Question

I'm currently working on api jwt based authentication off a boiler plate on SitePoint. So far I've gotten everything working but I'm stuck on this point.
My Controller looks like this:
namespace App\Api\V1\Controllers;
use Illuminate\Http\Request;
use Dingo\Api\Routing\Helpers;
use Symfony\Component\HttpKernel\Exception\HttpException;
use JWTAuth;
use App\Http\Controllers\Controller;
use App\Order;
// use App\Api\V1\Requests\LoginRequest;
use Tymon\JWTAuth\Exceptions\JWTException;
use Symfony\Component\HttpKernel\Exception\AccessDeniedHttpException;
in the body I have this function:
public function checkThis()
{
$currentUser = JWTAuth::parseToken()->authenticate();
$orders = App\Order::first();
echo $orders;
function() {
echo "stll here";
};
}
Under my api route I have this in a middleware:
$api->get('orderlist', 'App\\Api\\V1\\Controllers\\OrderController#checkThis');
When I run this in postman I get the following error: "message": "Class 'App\Api\V1\Controllers\App\Order' not found",
I've tried everything I can think of and it still keeps happening. When I take it out of the controller and run it directly in the routes it works. I'm a newbie to Laravel and PHP so I'm kinda of stuck.

Answer 1

All thing below assusing that you want to invoke the App\Order::first();
In function checkThis , you can replace App\Order::first() by
Order::first() //aliasing version
or replace App\Order::first() by
\App\Order::first(); //fully qualified Name version
By php manual
Example #1 importing/aliasing with the use operator
<?php
namespace foo;
use My\Full\Classname as Another;
// this is the same as use My\Full\NSname as NSname <-- very important
use My\Full\NSname;
Notice that
// this is the same as use My\Full\NSname as NSname <-- very important
use My\Full\NSname;
another php manual
and Inside a namespace, when PHP encounters an unqualified Name in a
class name, function or constant context, it resolves these with
different priorities. Class names always resolve to the current
namespace name. Thus to access internal or non-namespaced user
classes, one must refer to them with their fully qualified Name
php manual : fully qualified Name
Fully qualified name
This is an identifier with a namespace separator that begins with a namespace separator, such as \Foo\Bar. The namespace \Foo is also a
fully qualified name.
So if you want to invoke the function App\Order::first ,just Order::first,for the reason that
use App\Order;
equal
use App\Order as Order ;
the aliasing is Order instead of App\Order . And the Fully qualified name is \App\Order instead of App\Order.
On the other hand , when you invoke App\Order::first();
it means that you are invoking
App\Api\V1\Controllers\App\Order::first();
So it can't not find the class;
Here is my demo
file1.php
<?php
namespace App;
class Order{
public static function first(){
echo "i am first";
}
}
file2.php
<?php
namespace App\Api\V1\Controllers;
include 'file1.php';
use App\Order ;
\App\Order::first();
// and you can do it by
// Order::first(); they are equal in this place
when i run command php file2.php
it echo i am first