Converting PDO to mysqli - php

Question

Need help in converting PDO array execution to mysqli statements. This executes for an AJAX POST call for deleting a particular id from database with SWAL function.
<?php
require_once 'connectivity.php';
$response = array();
if ($_POST['delete']) {
$pid = intval($_POST['delete']);
$query = "DELETE FROM students WHERE id=$pid";
$stmt = mysqli_query($query,$connect);
$stmt->execute(array(':pid'=>$pid));
if ($stmt) {
$response['status'] = 'success';
$response['message'] = 'Student Deleted Successfully ...';
} else {
$response['status'] = 'error';
$response['message'] = 'Unable to delete ...';
}
echo json_encode($response);
}
?>
This is the consecutive swal function which is to be executed once the delete button clicked.
<script>
$(document).ready(function(){
$(document).on('click', '#deleteid', function(e){
var productId = $(this).data('id');
SwalDelete(productId);
e.preventDefault();
});
});
function SwalDelete(productId){
swal({
title: 'Are you sure?',
text: "It will be deleted permanently!",
type: 'warning',
showCancelButton: true,
confirmButtonColor: '#3085d6',
cancelButtonColor: '#d33',
confirmButtonText: 'Yes, delete it!',
showLoaderOnConfirm: true,
preConfirm: function() {
return new Promise(function(resolve) {
$.ajax({
url: 'delete.php',
type: 'POST',
data: {'delete' : productId}
})
.done(function(response){
swal('Deleted!', response.message, response.status);
readDetails();
})
.fail(function(){
swal('Oops...', 'Something went wrong with ajax !', 'error');
window.location.reload(true);
});
});
},
allowOutsideClick: false
});
}
function readDetails(){
window.location.reload(true);
}