How can I make radical function in php? - php

I was trying to make function that gives two value. First value was the respite in the radical and the second value is the number that we want to put it in radical.
It's my code:
function radical($respite = 2, $num)
{
$numbers = array();
for ($i = 1; $i < 10; $i++) {
$numbers[] = '0.' . "$i";
}
for ($i = 1; $i < 10; $i++) {
$numbers[] = '1.' . "$i";
}
// I wanted do these loop until to creat numbers from 0.1 to 100,
// but i under stand it's silly work and wrong.
for ($i = 0; $i < sizeof($numbers); $i++) {
if ($respite == 2) {
$hesan = $number["$i"] * $number["$i"];
if ($hesab == $num) {
return $hesab;
}
} elseif ($respite == 3) {
$hesan = $number["$i"] * $number["$i"] * $number["$i"];
if ($hesab == $num) {
return $hesab;
}
}
}
}
I tried to create numbers from 0.1 to 100. and I wanted write if $number[$i] * $number[$i] = $num return the $number, but I saw it's silly work and wrong my means create numbers from 0.1 to 100 by this way.
For radical(2, 9) the output should be 4, because 3 * 3 = 9.
If the first value is 3 radical(3, 8) the output should be 2, because 2 * 2 * 2= 8
Can someone make function to do radical with respite ? or improve my code ?

If you want to do this not as an exercise but for productive use, I suggest this:
function radical($num, $respite = 2)
{
return $num ** (1 / $respite);
}
echo radical(27, 3) . "\n" .
radical(8, 3) . "\n" .
radical(36, 2) . "\n" .
radical(16, 2);
Output:
3
2
6
4
You can see it here
The reason I changed the argument order is that you can't have a required parameter after an optional one.

Hope this is what you are looking for..
Try this code snippet here
function radical($respite = 2, $num)
{
for($x=0;$x<=10;$x+=0.1)
{
$numbers[]=$x;
}
for ($i = 0; $i < sizeof($numbers); $i++)
{
if ($respite == 2)
{
if ((string)($numbers[$i] * $numbers[$i]) == (string)$num)
{
return $numbers[$i];;
}
}
elseif ($respite == 3)
{
if ((string)($numbers[$i] * $numbers[$i]* $numbers[$i]) == (string)$num)
{
return $numbers[$i];
}
}
}
}
print_r(radical(3, 27));//3
print_r(radical(3, 8));//2
print_r(radical(2, 36));//6
print_r(radical(2, 16));//4

I'm not sure what you're going for exactly, but I think this cleans up what you have now at least:
function radical($num, $respite = 2) {
$numbers = array();
for ($i = 1; $i <= 1000; $i++) {
$numbers[] = $i * 0.1;
}
foreach($numbers as $i) {
if ($respite == 2) {
$hesab = $i * $i;
if ($hesab == $num) {
return $i;
}
}
elseif($respite == 3) {
$hesab = $i * $i * $i;
if ($hesab == $num) {
return $i;
}
}
}
return 0;
}

Related

print prime number [duplicate]

I need to find prime numbers with for loop or while loop
I wrote this but this is wrong
<?php
$i = 1;
while($i<5)
{
for($j=1; $j<=$i; $j++)
{
if ($j != 1 && $j != $i)
{
echo $i . "/" . $j . "=" . $i%$j . "<br />";
if ($i%$j != 0)
{
echo $i . "<br />";
}
}
}
echo "<br />";
$i += 1;
}
?>
Is there a way to divide a number with an array to find the remaining?
Here's a little function that I found: (http://icdif.com/computing/2011/09/15/check-number-prime-number/) Seemed to work for me!
function isPrime($num) {
//1 is not prime. See: http://en.wikipedia.org/wiki/Prime_number#Primality_of_one
if($num == 1)
return false;
//2 is prime (the only even number that is prime)
if($num == 2)
return true;
/**
* if the number is divisible by two, then it's not prime and it's no longer
* needed to check other even numbers
*/
if($num % 2 == 0) {
return false;
}
/**
* Checks the odd numbers. If any of them is a factor, then it returns false.
* The sqrt can be an aproximation, hence just for the sake of
* security, one rounds it to the next highest integer value.
*/
$ceil = ceil(sqrt($num));
for($i = 3; $i <= $ceil; $i = $i + 2) {
if($num % $i == 0)
return false;
}
return true;
}
You can use this PHP function gmp_nextprime()
Here is a one-liner I found a while back to check for primes. It uses tally marks (unary math) to determine:
function is_prime_via_preg_expanded($number) {
return !preg_match('/^1?$|^(11+?)\1+$/x', str_repeat('1', $number));
}
Check all numbers sequentially for primes:
$i=2; // start here (2 is the first prime)
while (1) { // neverending loop
if (is_prime_via_preg_expanded($i)) echo $i." <br />\n";
$i++;
}
To check only a range of numbers for primes like in the provided example:
$start = 2; // start here (2 is the first prime)
$end = 100;
$i=$start;
while ($i<=$end) {
if (is_prime_via_preg_expanded($i)) echo $i." <br />\n";
$i++;
}
This a basic implementation :
function prima($n){
for($i=1;$i<=$n;$i++){ //numbers to be checked as prime
$counter = 0;
for($j=1;$j<=$i;$j++){ //all divisible factors
if($i % $j==0){
$counter++;
}
}
//prime requires 2 rules ( divisible by 1 and divisible by itself)
if($counter==2){
print $i." is Prime <br/>";
}
}
}
prima(20); //find prime numbers from 1-20
This will output
2 is Prime
3 is Prime
5 is Prime
7 is Prime
11 is Prime
13 is Prime
17 is Prime
19 is Prime
Complete Logic step-by-step and visual analogy here : Here
Without math function:
function isPrimeNumber($i) {
$n = 2;
while ($n < $i) {
if ($i % $n) {
$n++;
continue;
}
return false;
}
return true;
}
I know it is too late, but I found that this solution is more elegant.
function isPrime($num)
{
if ($num < 2) {
return false;
}
for ($i = 2; $i <= $num / 2; $i++) {
if ($num % $i == 0) {
return false;
}
}
return true;
}
Anything who's sqrt() is false or any float value is prime number
This, I believe, is a quite efficient routine, which lists all the primes up to 1000.
It tests each number ($x) in order to see if it has any factors (other than itself and 1, of course).
Mathematically it is not necessary to test all lower numbers as possible factors, only lower primes up to the square root of $x. This is enabled by storing primes as they are found in an array (which I think is the strategy the OP was referring to).
As soon as the first prime factor is found, we know that $x is not prime, and so no further testing of that value of $x is needed and we can break out of the foreach loop.
$primes = array();
for ($x = 2; $x <= 1000; $x++) {
$xIsPrime = TRUE;
$sqrtX = sqrt($x);
foreach ($primes as $prime) if ($prime > $sqrtX || ((!($x % $prime)) && (!$xIsPrime = FALSE))) break;
if ($xIsPrime) echo ($primes[] = $x) . "<br>";
}
Sieve_of_Eratosthenes is simple and faster algorithm to find prime numbers.
function getPrimes($finish)
{
$number = 2;
$range = range($number,$finish);
$primes = array_combine($range,$range);
while($number*$number < $finish){
for($i=$number; $i<=$finish; $i+=$number){
if($i==$number){
continue;
}
unset($primes[$i]);
}
$number = next($primes);
}
return $primes;
}
<?php
$n = 11;
$o = $_POST["maxprime"];
echo 'The script calculated the next primenumbers:</br>';
echo '2, 3, 5, 7, ';
while (true) {
$t = 6;
while (true) {
if ($n % ($t - 1) == 0) {
break;
}
if ($n % ($t + 1) == 0) {
break;
}
if ($t > sqrt($n)) {
echo("$n, ");
break;
}
$t += 6;
}
if (($n + 1) % 6 == 0) {
$n += 2;
} else {
$n += 4;
}
if ($n > $o) {
break;
}
}
?>
http://www.primenumbergenerator.com/
Below programs is simple with two for loops and ignores 1 and self values in iteration. It will print the prime numbers,
function get_primenumbers($length) {
//Ignore 1
for($i = 2; $i <= $length; $i++){
$prime = true;
for($j = 2; $j <= $i; $j++){
//Ignore same number
if(($i != $j) && ($i % $j == 0)){
$prime = false;
break;
}
}
if(!$prime){
echo "$i is not prime <br />";
}else{
echo "$i is prime <br />";
}
}
}
$num = 25;
echo "Value Hardcored ".$num."<br>";
for($i=2; $i<$num; $i++)
{
if($num%$i==0)
{
$Loop = true;
echo "This is Composite Number";
break;
}
$Loop = false;
}
if($Loop == false)
{
echo "Prime Number";
}
i know this is coming kind of late, but hope it helps someone.
function prime_number_finder($range)
{
$total_count=0;//intitialize the range keeper
$i=1;//initialize the numbers to check
while ($total_count<=$range)
{
$count=0;//initialize prime number inner count
$k=$i;
while ($k!=0)
{
if(($i%$k)==0)
{
$count++;
}
$k--;
}
//condition to check if a number is prime
if($count==2 || $count==1)
{
echo $i."</br>";//output the prime number;
$total_count++;
$i++;
}
//number is not prime
if($count>2)
{
//$total_count++;
$i++;
}
}
}
//example
prime_number_finder(200);
$n = 7;
if ($n == 1) {
echo 'Not a Prime or Composite No.';
}
$set = 0;
for ($index = 2; $index <= $n/2; $index++) {
if ($n % $index === 0) {
$set = 1;
break;
}
}
if ($set) {
echo 'Composite';
} else {
echo 'Prime';
}
Find prime numbers between 1 and 10000, using a closure in array_filter():
$start = 2;
$step = 10000;
$stop = $start + $step;
$candidates = range($start, $stop);
for($num = 2; $num <= sqrt($stop); ++$num){
$candidates = array_filter($candidates,
function ($v) use (&$num){
return ($v % $num) != 0 || $v == $num ;
}
);
}
print_r($candidates);
Edit: 1 is not a prime number
The best way to check if a number is prime is to see if it is divisible by any prime number before it. Pi(x) is the one I keep seeing everywhere... You can see a bit more information on Prime Counting on wikipedia.
So the most efficient way I can think of at the moment is as follow:
class prime
{
public $primes = [ 2, 3, 5, 7 ];
public $not_prime = [ 1, 4, 6, 8, 9 ];
public function is_prime( int $n )
{
if ( $n <= 1 ) return false;
if ( in_array( $n, $this->primes ) ) return true;
if ( in_array( $n, $this->not_prime ) ) return false;
for( $i = 0; $i < count( array_slice( $this->primes, 0, $this->prime_count( $n ) ) ) || $i == $n; $i++ )
{
if ( $n % $this->primes[ $i ] == 0 ) return false;
}
return true;
}
public function build_primes_to( int $n )
{
for ( $i = end( $this->primes ) + 1; $i <= $n; $i++ )
{
if ( $this->is_prime( $i ) )
{
$this->primes[] = $i;
}
else
{
$this->not_prime[] = $i;
}
}
}
public function prime_count( $n )
{
$ln = log( $n );
if ( $ln == 0 ) return 1;
return intval( ceil( $n / $ln ) );
}
}
Which isn't actually very efficient, well, not when it comes to building the list of prime numbers... I've been working on a better way of building the list here, though it would be just as easy and far more efficient to find a list online and use that.
Usage of the above would be along the lines of:
$find_to = 1000;
$prime = new prime();
$prime->build_primes_to( $find_to );
print "<pre>";
for ( $i = 1; $i < $find_to; $i++ )
{
print "$i is " . ( !$prime->is_prime( $i ) ? "not " : "" ) . "prime\n";
}
I know this is coming a bit late, but here's a simple program to help you do just what you're asking for...
<?php
//Prime Function
function fn_prime($number) {
$i = 2; $result = TRUE;
while($i < $number) {
if(!($number%$i)) {
$result = FALSE;
}
$i++;
}
return $result;
}
//Declare integer variable...
$k = 0;
//Start Loop up to any number of your choice for e.g. 200
while($k < 200) {
if(fn_prime($k)) {
echo "$k is a prime number<br/>";
} else {
echo "$k is not a prime number!<br/>";
}
$k++;
}
?>
<?php
function prime_number($num){
for( $j = 2; $j <= $num; $j++ )
{
for( $k = 2; $k < $j; $k++ )
{
if( $j % $k == 0 )
{
break;
}
}
if( $k == $j )
echo "Prime Number : ".$j."<br>";
}
}
prime_number(23);
?>
Enchanced version of #Farkie answer made especially for checking primes in loops.
function isPrime_v2($num) {
static $knownPrimes=[3]; // array to save known primes
if($num == 1)
return false;
if($num == 2 || $num == 3) //added '3'
return true;
if($num % 2 == 0)
return false;
$ceil = ceil(sqrt($num)); //same purpose, good point from Farkie
// Check against known primes to shorten operations
// There is no sense to check agains numbers in between
foreach($knownPrimesas $prime){
if ($prime>$ceil)
break;
if($num===$prime)
return true;
if($num % $prime == 0)
return false;
}
/**
* end($knownPrimes) % 2 !==0 - mathematically guaranteed
* start with latest known prime
*/
for($i = end($knownPrimes)+2; $i <= $ceil; $i = $i + 2) {
if($num % $i == 0)
return false;
}
$knownPrimes[]=$num;
return true;
}
Benchmark with phpfiddle.org. V1 - Farkie answer, V2 - Enchanced version
V1 (1 to 5,000,000): divisions=330 929 171; primes=348 513; time=21.243s
V2 (1 to 5,000,000): divisions=114 291 299; primes=348 513; time=10.357s
NOTE! isPrime_v2 function is applicable ONLY in case of looping from 3. Otherwise saved $knownPrimes array will have insufficient history.
Here's another very simple but quiet effective approach:
function primes($n){
$prime = range(2 , $n);
foreach ($prime as $key => $value) {
for ($i=2; $i < $value ; $i++) {
if (is_int($value / $i)) {
unset($prime[$key]);
break;
}
}
}
foreach ($prime as $value) {
echo $value.'<br>';
}
}
primes(1000);
<?php
$limit=100;
$i=1;
outer:while($i<=$limit){
$j=2;
while($j<$i){
if($i%$j==0){
$i++;
goto outer;
}
$j++;
}
echo $i;
echo "<br/>";
$i++;
}
?>
<form method="post" action="">
<input type="number" name="demo" placeholder="Enter Any Number">
<button type="submit" name="aqeela" > Prime or composite </button>
</form>
<br>
<?php
if(isset($_POST['aqeela']))
{
$nu=$_POST['demo'];
if($nu==2)
{
echo "The Only Even Prime Number";
}
else
{
for($i=2; $i<$nu; $i++)
{
if($nu%$i==0)
{
echo "This is Composite Number";
break;
}
else
{
if($i==($nu-1))
{
echo "Prime number";
}
}
}
}
}

Looking for opposite of pow() in PHP

I am working on mathematical problem where the formula is: A[i] * (-2) power of i
where i=0,1,2,3,...
A is an array having values 0 or 1
Input array: [0,1,1,0,0,1,0,1,1,1,0,1,0,1,1]
Output is: 5730
Code
$totalA = 0;
foreach ($A as $i => $a) {
$totalA += $a * pow(-2, $i);
}
This is correct. Now I am looking for its opposite like:
Input is: 5730
Output will be: [0,1,1,0,0,1,0,1,1,1,0,1,0,1,1]
I am not asking for the exact code but looking for some logic from where I should start. I tried to use log() method but that did not return the desired output.
You were not looking for exact code, but I found this problem too interesting. This works:
function sign($n) {
return ($n > 0) - ($n < 0);
}
$target = -2396;
$i = 0;
$currentSum = 0;
// Look for max $i
while (true) {
$val = pow(-2, $i);
$candidate = $currentSum + $val;
if (abs($target) <= abs($candidate)) {
// Found max $i
break;
}
if (abs($target - $candidate) < abs($target - $currentSum)) {
// We are getting closer
$currentSum = $candidate;
}
$i++;
}
$result = [];
for ($j = $i; 0 <= $j; $j--) {
$val = pow(-2, $j);
$border = $val / 4;
if (sign($val) == sign($target) && abs($border) < abs($target)) {
array_unshift($result, 1);
$target -= $val;
} else {
array_unshift($result, 0);
}
}
echo json_encode($result);
First I look for the $i that gets me on or slightly above the $target. When found, I walk down and decide for each bit if it should be in the result.

PHP letter looping number to chr

I am trying to turn numbers into letters to create references for rows.
I have:
public static function references($idx) {
$str = '';
$i = ceil($idx/25);
if(65+$idx > 90) {
} else {
$str = chr(65+$idx);
}
return $chr;
}
But I don't know where to go from here.
Valid outputs would be:
first item: A
28th item: AB
...
Input is an index that comes in from a loop, i.e. 0, 1, 2, 3 etc
I figured it out:
public static function references($n)
{
$r = '';
for ($i = 1; $n >= 0 && $i < 10; $i++) {
$r = chr(0x41 + ($n % pow(26, $i) / pow(26, $i - 1))) . $r;
$n -= pow(26, $i);
}
return $r;
}

I need to find all amicable numbers up to a certain number

Here is my code:
$n = 300;
$set = 0;
$set2 = 0;
for($i = 1; $i<$n; $i++)
{
for($j = 1; $j <$i; $j++)
{
$qol = $i % $j;
if($qol == 0)
{
$set += $j;
}
}
for($s=1; $s<$set; $s++)
{
$qol2 = $set % $s;
if($s == 0)
{
$set2 += $s;
}
}
if($set2 == $i)
{
echo "$set and $i are amicable numbers</br>";
}
}
I do not know what the heck the problem is!
FYI: 220 and 284 are an example of amicable numbers. The sum of the proper divisors of one number are equal to other number and vice versa (wiki).
I am having troubles following your logic. In your code how would $set2 == $i ever be true? Seems to me that $i would always be greater.
I would do it the following way:
First make a separate function that finds the sums of the proper divisors:
// Function to output sum of proper divisors of $num
function sumDiv($num) {
// Return 0 if $num is 1 or less
if ($num <= 1) {
return 0;
}
$result = 1; // All nums divide by 1
$sqrt = sqrt($num);
// Add divisors to result
for ($i = 2; $i < $sqrt; $i++) {
if ($num % $i == 0) {
$result += $i + $num / $i;
}
}
// If perfect square add squareroot to result
if (floor($sqrt) == $sqrt) {
$result += $sqrt;
}
return $result;
}
Next check each iteration for a match:
$n = 1500;
for ($i = 1; $i < $n; $i++) {
// Get sum of proper devisors of $i, and sum of div. of result.
$currentDivs = sumDiv($i);
$resultDivs = sumDiv($currentDivs);
// Check for a match with sums not equal to each other.
if ($i == $resultDivs && $currentDivs != $resultDivs) {
echo "$i and $currentDivs are amicable numbers<br>";
}
}
Here a functioning phpfiddle.
Warning: Large numbers will take very long to process!

A formula to find prime numbers in a loop

I need to find prime numbers with for loop or while loop
I wrote this but this is wrong
<?php
$i = 1;
while($i<5)
{
for($j=1; $j<=$i; $j++)
{
if ($j != 1 && $j != $i)
{
echo $i . "/" . $j . "=" . $i%$j . "<br />";
if ($i%$j != 0)
{
echo $i . "<br />";
}
}
}
echo "<br />";
$i += 1;
}
?>
Is there a way to divide a number with an array to find the remaining?
Here's a little function that I found: (http://icdif.com/computing/2011/09/15/check-number-prime-number/) Seemed to work for me!
function isPrime($num) {
//1 is not prime. See: http://en.wikipedia.org/wiki/Prime_number#Primality_of_one
if($num == 1)
return false;
//2 is prime (the only even number that is prime)
if($num == 2)
return true;
/**
* if the number is divisible by two, then it's not prime and it's no longer
* needed to check other even numbers
*/
if($num % 2 == 0) {
return false;
}
/**
* Checks the odd numbers. If any of them is a factor, then it returns false.
* The sqrt can be an aproximation, hence just for the sake of
* security, one rounds it to the next highest integer value.
*/
$ceil = ceil(sqrt($num));
for($i = 3; $i <= $ceil; $i = $i + 2) {
if($num % $i == 0)
return false;
}
return true;
}
You can use this PHP function gmp_nextprime()
Here is a one-liner I found a while back to check for primes. It uses tally marks (unary math) to determine:
function is_prime_via_preg_expanded($number) {
return !preg_match('/^1?$|^(11+?)\1+$/x', str_repeat('1', $number));
}
Check all numbers sequentially for primes:
$i=2; // start here (2 is the first prime)
while (1) { // neverending loop
if (is_prime_via_preg_expanded($i)) echo $i." <br />\n";
$i++;
}
To check only a range of numbers for primes like in the provided example:
$start = 2; // start here (2 is the first prime)
$end = 100;
$i=$start;
while ($i<=$end) {
if (is_prime_via_preg_expanded($i)) echo $i." <br />\n";
$i++;
}
This a basic implementation :
function prima($n){
for($i=1;$i<=$n;$i++){ //numbers to be checked as prime
$counter = 0;
for($j=1;$j<=$i;$j++){ //all divisible factors
if($i % $j==0){
$counter++;
}
}
//prime requires 2 rules ( divisible by 1 and divisible by itself)
if($counter==2){
print $i." is Prime <br/>";
}
}
}
prima(20); //find prime numbers from 1-20
This will output
2 is Prime
3 is Prime
5 is Prime
7 is Prime
11 is Prime
13 is Prime
17 is Prime
19 is Prime
Complete Logic step-by-step and visual analogy here : Here
Without math function:
function isPrimeNumber($i) {
$n = 2;
while ($n < $i) {
if ($i % $n) {
$n++;
continue;
}
return false;
}
return true;
}
I know it is too late, but I found that this solution is more elegant.
function isPrime($num)
{
if ($num < 2) {
return false;
}
for ($i = 2; $i <= $num / 2; $i++) {
if ($num % $i == 0) {
return false;
}
}
return true;
}
Anything who's sqrt() is false or any float value is prime number
This, I believe, is a quite efficient routine, which lists all the primes up to 1000.
It tests each number ($x) in order to see if it has any factors (other than itself and 1, of course).
Mathematically it is not necessary to test all lower numbers as possible factors, only lower primes up to the square root of $x. This is enabled by storing primes as they are found in an array (which I think is the strategy the OP was referring to).
As soon as the first prime factor is found, we know that $x is not prime, and so no further testing of that value of $x is needed and we can break out of the foreach loop.
$primes = array();
for ($x = 2; $x <= 1000; $x++) {
$xIsPrime = TRUE;
$sqrtX = sqrt($x);
foreach ($primes as $prime) if ($prime > $sqrtX || ((!($x % $prime)) && (!$xIsPrime = FALSE))) break;
if ($xIsPrime) echo ($primes[] = $x) . "<br>";
}
Sieve_of_Eratosthenes is simple and faster algorithm to find prime numbers.
function getPrimes($finish)
{
$number = 2;
$range = range($number,$finish);
$primes = array_combine($range,$range);
while($number*$number < $finish){
for($i=$number; $i<=$finish; $i+=$number){
if($i==$number){
continue;
}
unset($primes[$i]);
}
$number = next($primes);
}
return $primes;
}
<?php
$n = 11;
$o = $_POST["maxprime"];
echo 'The script calculated the next primenumbers:</br>';
echo '2, 3, 5, 7, ';
while (true) {
$t = 6;
while (true) {
if ($n % ($t - 1) == 0) {
break;
}
if ($n % ($t + 1) == 0) {
break;
}
if ($t > sqrt($n)) {
echo("$n, ");
break;
}
$t += 6;
}
if (($n + 1) % 6 == 0) {
$n += 2;
} else {
$n += 4;
}
if ($n > $o) {
break;
}
}
?>
http://www.primenumbergenerator.com/
Below programs is simple with two for loops and ignores 1 and self values in iteration. It will print the prime numbers,
function get_primenumbers($length) {
//Ignore 1
for($i = 2; $i <= $length; $i++){
$prime = true;
for($j = 2; $j <= $i; $j++){
//Ignore same number
if(($i != $j) && ($i % $j == 0)){
$prime = false;
break;
}
}
if(!$prime){
echo "$i is not prime <br />";
}else{
echo "$i is prime <br />";
}
}
}
$num = 25;
echo "Value Hardcored ".$num."<br>";
for($i=2; $i<$num; $i++)
{
if($num%$i==0)
{
$Loop = true;
echo "This is Composite Number";
break;
}
$Loop = false;
}
if($Loop == false)
{
echo "Prime Number";
}
i know this is coming kind of late, but hope it helps someone.
function prime_number_finder($range)
{
$total_count=0;//intitialize the range keeper
$i=1;//initialize the numbers to check
while ($total_count<=$range)
{
$count=0;//initialize prime number inner count
$k=$i;
while ($k!=0)
{
if(($i%$k)==0)
{
$count++;
}
$k--;
}
//condition to check if a number is prime
if($count==2 || $count==1)
{
echo $i."</br>";//output the prime number;
$total_count++;
$i++;
}
//number is not prime
if($count>2)
{
//$total_count++;
$i++;
}
}
}
//example
prime_number_finder(200);
$n = 7;
if ($n == 1) {
echo 'Not a Prime or Composite No.';
}
$set = 0;
for ($index = 2; $index <= $n/2; $index++) {
if ($n % $index === 0) {
$set = 1;
break;
}
}
if ($set) {
echo 'Composite';
} else {
echo 'Prime';
}
Find prime numbers between 1 and 10000, using a closure in array_filter():
$start = 2;
$step = 10000;
$stop = $start + $step;
$candidates = range($start, $stop);
for($num = 2; $num <= sqrt($stop); ++$num){
$candidates = array_filter($candidates,
function ($v) use (&$num){
return ($v % $num) != 0 || $v == $num ;
}
);
}
print_r($candidates);
Edit: 1 is not a prime number
The best way to check if a number is prime is to see if it is divisible by any prime number before it. Pi(x) is the one I keep seeing everywhere... You can see a bit more information on Prime Counting on wikipedia.
So the most efficient way I can think of at the moment is as follow:
class prime
{
public $primes = [ 2, 3, 5, 7 ];
public $not_prime = [ 1, 4, 6, 8, 9 ];
public function is_prime( int $n )
{
if ( $n <= 1 ) return false;
if ( in_array( $n, $this->primes ) ) return true;
if ( in_array( $n, $this->not_prime ) ) return false;
for( $i = 0; $i < count( array_slice( $this->primes, 0, $this->prime_count( $n ) ) ) || $i == $n; $i++ )
{
if ( $n % $this->primes[ $i ] == 0 ) return false;
}
return true;
}
public function build_primes_to( int $n )
{
for ( $i = end( $this->primes ) + 1; $i <= $n; $i++ )
{
if ( $this->is_prime( $i ) )
{
$this->primes[] = $i;
}
else
{
$this->not_prime[] = $i;
}
}
}
public function prime_count( $n )
{
$ln = log( $n );
if ( $ln == 0 ) return 1;
return intval( ceil( $n / $ln ) );
}
}
Which isn't actually very efficient, well, not when it comes to building the list of prime numbers... I've been working on a better way of building the list here, though it would be just as easy and far more efficient to find a list online and use that.
Usage of the above would be along the lines of:
$find_to = 1000;
$prime = new prime();
$prime->build_primes_to( $find_to );
print "<pre>";
for ( $i = 1; $i < $find_to; $i++ )
{
print "$i is " . ( !$prime->is_prime( $i ) ? "not " : "" ) . "prime\n";
}
I know this is coming a bit late, but here's a simple program to help you do just what you're asking for...
<?php
//Prime Function
function fn_prime($number) {
$i = 2; $result = TRUE;
while($i < $number) {
if(!($number%$i)) {
$result = FALSE;
}
$i++;
}
return $result;
}
//Declare integer variable...
$k = 0;
//Start Loop up to any number of your choice for e.g. 200
while($k < 200) {
if(fn_prime($k)) {
echo "$k is a prime number<br/>";
} else {
echo "$k is not a prime number!<br/>";
}
$k++;
}
?>
<?php
function prime_number($num){
for( $j = 2; $j <= $num; $j++ )
{
for( $k = 2; $k < $j; $k++ )
{
if( $j % $k == 0 )
{
break;
}
}
if( $k == $j )
echo "Prime Number : ".$j."<br>";
}
}
prime_number(23);
?>
Enchanced version of #Farkie answer made especially for checking primes in loops.
function isPrime_v2($num) {
static $knownPrimes=[3]; // array to save known primes
if($num == 1)
return false;
if($num == 2 || $num == 3) //added '3'
return true;
if($num % 2 == 0)
return false;
$ceil = ceil(sqrt($num)); //same purpose, good point from Farkie
// Check against known primes to shorten operations
// There is no sense to check agains numbers in between
foreach($knownPrimesas $prime){
if ($prime>$ceil)
break;
if($num===$prime)
return true;
if($num % $prime == 0)
return false;
}
/**
* end($knownPrimes) % 2 !==0 - mathematically guaranteed
* start with latest known prime
*/
for($i = end($knownPrimes)+2; $i <= $ceil; $i = $i + 2) {
if($num % $i == 0)
return false;
}
$knownPrimes[]=$num;
return true;
}
Benchmark with phpfiddle.org. V1 - Farkie answer, V2 - Enchanced version
V1 (1 to 5,000,000): divisions=330 929 171; primes=348 513; time=21.243s
V2 (1 to 5,000,000): divisions=114 291 299; primes=348 513; time=10.357s
NOTE! isPrime_v2 function is applicable ONLY in case of looping from 3. Otherwise saved $knownPrimes array will have insufficient history.
Here's another very simple but quiet effective approach:
function primes($n){
$prime = range(2 , $n);
foreach ($prime as $key => $value) {
for ($i=2; $i < $value ; $i++) {
if (is_int($value / $i)) {
unset($prime[$key]);
break;
}
}
}
foreach ($prime as $value) {
echo $value.'<br>';
}
}
primes(1000);
<?php
$limit=100;
$i=1;
outer:while($i<=$limit){
$j=2;
while($j<$i){
if($i%$j==0){
$i++;
goto outer;
}
$j++;
}
echo $i;
echo "<br/>";
$i++;
}
?>
<form method="post" action="">
<input type="number" name="demo" placeholder="Enter Any Number">
<button type="submit" name="aqeela" > Prime or composite </button>
</form>
<br>
<?php
if(isset($_POST['aqeela']))
{
$nu=$_POST['demo'];
if($nu==2)
{
echo "The Only Even Prime Number";
}
else
{
for($i=2; $i<$nu; $i++)
{
if($nu%$i==0)
{
echo "This is Composite Number";
break;
}
else
{
if($i==($nu-1))
{
echo "Prime number";
}
}
}
}
}

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