Insert dynamic Object property names into Database - php

Question

Alright so I have an insert query that I would like to run but the issue I am having is with getting object properties/values that I need to insert.
Say I have a query that looks like the one below.
$this->db->insert('tblitems_in', array(
'platform' => $item['Platform'],
'ram' => $item['RAM'],
'qty' => $item['qty'],
'rate' => number_format($item['rate'], 2, '.', ''),
'rel_id' => $insert_id,
'rel_type' => 'estimate',
'item_order' => $item['order'],
'unit' => $item['unit']
));
This works fine when the person chooses RAM on the webpage which sets the $item Objects property 'RAM' to the value that was picked. Now if they choose HardDrive, that properties name is now sent as 'HardDrive' with the value they chose. Is there a way that i Could replace the 'ram' and 'RAM' from the below example with a variable so I could change what the property name is that I would like to insert and insert into the corresponding db column?
EDIT:
I should have added that the options on the webpage are also dynamically created from a database so I do not know at the time of coding what the property names are. They could be RAM, HardDrive, Processor, maybe even Elephant. I was hoping I could use variables so that I could look at the DB used to create the webpage so that I know the property names and then dynamically add those names into the query.
EDIT:
Right now I am using the following code in order to get all the possible options that can be received from the webpage from a DB the webpages uses to create itself.
$plat_options = $this->db->get('tblplatform_options')->row()->name;
In the database right now it is only populated with names RAM and HardDrive to make things known for testing purposes. So this returns $plat_options = {RAM, HardDrive}. I now have to figure out how to test is $item has these(RAM and HardDrive) as properties and if $item does have them then add them into the query previously shown.

Answer 1

You can set an array of key => variable names, then loop over those values to see if they exist in the $item variable and, if so, add that value to the data to be inserted into the db:
//default array of data to insert
$data = [
'platform' => $item['Platform'],
'qty' => $item['qty'],
'rate' => number_format($item['rate'], 2, '.', ''),
'rel_id' => $insert_id,
'rel_type' => 'estimate',
'item_order' => $item['order'],
'unit' => $item['unit']
];
//Get column names from db
$plat_options = $this->db->get('tblplatform_options')->row()->name;
// $plat_options = [RAM, HardDrive]
//Check if $item[$name] exists. If it does, add that to the
// array of data to be inserted
foreach($plat_options as $key) {
if(array_key_exists($key, $item)) {
$data[$key] = $item[$key];
}
}
$this->db->insert('tblitems_in', $data);
edit
I'm not sure this will work (I don't understand the use case).
It is possible, using array_diff_key to get a list of array keys that exist in $item but not in $data. With this array of keys, you can add the missing keys.
I have altered my previous code to demonstrate this.

Answer 2

You could create the array one element at a time based on whatever field data you received. I used a switch statement, but it could be a simple if/then/else as well.
$data_array = array();
$data_array['platform'] = $item['Platform']
switch($item['Object'] {
case 'HardDrive':
$data_array['harddrive'] = $item['HardDrive'];
break;
case 'RAM':
$data_array['ram'] = $item['RAM'];
break;
}
$data_array['qty'] = $item['qty'];
$data_array['rate' = number_format($item['rate'], 2, '.', '');
$data_array['rel_id'] = $insert_id;
$data_array['rel_type' = 'estimate';
$data_array['item_order'] = $item['order'];
$data_array['unit'] = $item['unit'];
$this->db->insert('tblitems_in', $data_array);