PHP DATA Fetch Issue - php

Question

I am very new to PHP and HTML. I am trying to fetch the row value from input form data, but i am unable to fetch the data.
Below is my code.
HTML:
<form id="main" action="test.php" method="post" enctype="multipart/form-data" >
<div class="row">
<div class="col-md-12">
<label for="model" style="font-size: 15px"> Model </label><br>
<input type="text" id="tags" name="model" placeholder="Type Your Model Number" >
</div>
</div>
<div class="row">
<div class="col-md-12">
<button type="submit" id="button" name="submit1" />SUBMIT</button>
</div>
</div>
</form>
</html>
PHP CODE:
<?php
if(isset($_POST['submit']))
{
// id to search
$model = $_POST['model'];
// connect to mysql
$connect = mysqli_connect("localhost", "root", "","test");
// mysql search query
$query = "SELECT `offer`, `amount` FROM `offer`";
$result = mysqli_query($connect, $query);
// if id exist
// show data in inputs
if(mysqli_num_rows($result) > 0)
{
while ($row = mysqli_fetch_array($result))
{
$offer = $row['offer'];
$amount = $row['amount'];
}}
if($model){
echo "
<form method='post' action=''>
<div class='col-md-5'>
$offer
</div>
<div class='col-md-5'>
INR $amount/-
</div>
</div></form>";
else {
$offer = "";
$amount = "";
$offer2 = "";
$amount2 = "";
}
mysqli_free_result($result);
mysqli_close($connect);}
else{
$offer = "";
$amount = "";
$offer2 = "";
$amount2 = "";
}
?>
Also, please note that the model is alphanumeric. Offer would be Headset and amount would be 100. I request to help me on this.

Answer 1

First of all we don't know what your error is and second you haven't included all your code. However, for PHP use following code
<?php
$mysqli = new mysqli("localhost", "root", "", "test") or die($mysqli->error);
$select = $mysqli->query("SELECT * from offer") or die($mysqli->error);
if($select->num_rows){
while($row = $select->fetch_array(MYSQLI_ASSOC)){
$amount = $row['amount'];
$offer= $row['offer'];
}
}
?>
You have used input and button but i don't see any form tags in HTML

Answer 2

You have to pass the $model in your query and do that to show the results:
echo "<form method='post' action=''>";
while ($row = mysqli_fetch_array($result))
{
echo " <div class='col-md-5'>
".$row['offer']."
</div>
<div class='col-md-5'>
INR ".$row['amount']."-
</div> ";
}
echo "</form>";