Add 3 days to date fetched from DB expecting weekends - php

Question

I have a table with a status column and date column. I need to add 3 days to my date from the DB expecting weekends if status is 2 or 6. Here is my code:
$selectall = sqlsrv_query($conn, "select * from Table where and Status = 2 or status = 6", $params, $options);
while($fetchall = sqlsrv_fetch_array($selectall))
{
$id = $fetchall['DATAID'];
$dates = $fetchall['DATE'];
if( 3 DAYS PAST )
{
sqlsrv_query($conn, "UPDATE TABLE SET STATUS=5 WHERE DATAID=$ID")
}
}

Answer 1

I don't see how is this a JS question, but anyhow, you need to calculate date range in your php code and put that date range into your SQL query. AKA you take the start date, check which weekday it currently is and do respective mathematical calculations to add additional days.

Answer 2

I would use something like this around my date variable
select
DATEADD(d,
case when datepart(dw,'2017-05-17')=6 then 6
when datepart(dw,'2017-05-17')=7 then 5
when datepart(dw,'2017-05-17')=1 then 4
when datepart(dw,dateadd(d,3,'2017-05-17'))=7 then 5
when datepart(dw,dateadd(d,3,'2017-05-17'))=1 then 4
else 3
end
,'2017-05-17')

Answer 3

$selectall = sqlsrv_query($conn, "select * from Table where and Status = 2 or status = 6", $params, $options);
while($fetchall = sqlsrv_fetch_array($selectall))
{
$DATAID= $fetchall['DATAID'];
$dates = $fetchall['DATE'];
$p = date("l");
switch ($p)
{
case "Wednesday" || "Thursday" || "Friday":
$day = '-5 days';
break;
default:
$day = '-3 days';
}
$s = date($dates);
$today = date('Y-m-d');
$totalday = date('Y-m-d', strtotime($day));
if($totalday <= $s)
{
sqlsrv_query($conn, "UPDATE table SET STATUS = 5 WHERE DATAID=$dataid");
}
}