PHP: array search when array doesn't start on zero - php

Question

I'm trying to find a key in an array that doesn't start with zero.
This is my not so elegant solution:
private $imagetypes = [
1 => [
'name' => 'banner_big',
'path' => 'campaigns/big/'
],
2 => [
'name' => 'banner_small',
'path' => 'campaigns/small/'
],
// ...
If i use $key = array_search('banner_big', array_column($this->imagetypes, 'name')); the result is 0
I came up with this solution but I feel like I needlessly complicated the code:
/**
* #param string $name
* #return int
*/
public function getImagetypeFromName($name)
{
$keys = array_keys($this->imagetypes);
$key = array_search($name, array_column($this->imagetypes, 'name'));
if ($key !== false && array_key_exists($key, $keys)) {
return $keys[$key];
}
return -1;
}
Is there a better solution then this.
I can't change the keys in.

Answer 1

Just save indexes
$key = array_search('banner_big',
array_combine(array_keys($imagetypes),
array_column($imagetypes, 'name')));
demo on eval.in

Answer 2

The problem is array_column will return a new array (without the existing indexes)
So in your example.
$key = array_search('banner_big', array_column($this->imagetypes, 'name'));
var_dump($key);
//$key is 0 as 0 is the key for the first element in the array returned by array_column.
You can mitigate against this by creating a new array with the existing keys.

Answer 3

That's because array_column() generates another array (starting at
index zero), as you may have imagined. An idea to solve this would be to
transform the array with array_map(), reducing it to key and image
name (which is what you're searching for). The keys will be the same,
and this can be achieved with a simple callback:
function($e) {
return $e['name'];
}
So, a full implementation for your case:
public function
getImagetypeFromName($name)
{
$key = array_search($name, array_map(function($e) {
return $e['name'];
}, $this->imagetypes));
return $key ?: -1;
}