How to use a Select with OR in PHP - odbc_prepare Issue - php

Question

I'm using Microsoft SQL Server for this
function novogetListagemClientes($conn, $User){
$stmt = odbc_prepare($conn, 'SELECT * FROM users WHERE id IN ( SELECT idCliente FROM ligacoes WHERE ligacoes.idGest = ? OR idSocioG = ? OR idFunc = ? OR idColab = ? OR idSub = ? )');
$success = odbc_execute($stmt, array($User));
while($myRow = odbc_fetch_array($stmt))
{
$rows = $myRow;
}
if(empty($rows))
{
return array();
}
return utf8_converter($rows);
}
That's my PHP Function and I want that all the '?' have the same number, how should I fill that array ?
Right now when I use this query in my page it returns nothing, but in Navicat using query builder, returns what I expect.
Error I get: Warning: odbc_execute(): SQL error: [Microsoft][ODBC SQL Server Driver]Syntax error or access violation, SQL state 37000 in SQLDescribeParameter
If switch the '?' by a number that exists, I get the true value.
Update:If I switch the ? by '.$User.' and take of the array part it works

Answer 1

This answer is a summary of interactions in comments on the original question.
Having checked that the ODBC connection was fine (data is returned when the relevant parameter was "hardcoded"), I surmised that the problem was that the ODBC connection wasn't coping with the "Prepare" statement. This will likely have been because the parameters to be passed were not in the outermost WHERE clause and so prior to executing the query the connection couldn't work out the overall shape of the resulting data.
To get around this, we refactored the SQL code to remove the subquery and so put the parameter in the outermost WHERE clause.
The SQL therefore changed from
SELECT *
FROM users
WHERE id IN ( SELECT idCliente
FROM ligacoes
WHERE ? in (ligacoes.idGest, idSocioG, idFunc, idColab, idSub))
to
SELECT DISTINCT u.*
FROM users u
JOIN ligacoes l ON
u.id = l.idCliente
WHERE ? in (l.idGest, l.idSocioG, l.idFunc, l.idColab, l.idSub)
And with that change the code ran without complaint.