Inserting value in table with the click of a button - php

Question

I'm working on a file called test.php.
What I'm trying to do is, to insert a value into a table by clicking a submit button
I have two tables, tbl_1 and tbl_2
tbl_1
id | name | age
4 | john | 20
9 | tim | 25
8 | lea | 22
While tbl_2 have the same structure as tbl_1, it is empty or without any value in it... the idea is that I want to have a button, after clicking on that button, it will insert the value of tbl_1 into tbl_2 based on the id
The question is, how do I fill in tbl_2 with the value of tbl_1, through a click of a submit button?
I made a form, trying to bring the value from tbl_1 to tbl_2, but to no avail...
<form action="test.php?id" method="post">
<input type="submit" class="btn btn-info btn-xs" name="submit" value="Copy"/>
</form>
<?php
if(isset($_POST['submit']))
{
$io = $_POST['io'];
$no_kes = $_POST['no_kes'];
$SQL = "INSERT INTO tbl_2(name, age) VALUES ( '".$name."', '".$age."')";
$result = mysql_query($SQL);
}
?>
Below is how my table looks like on the web.
Below is the code for the table I constructed.
<table class="table table-striped table-bordered">
<tr>
<th>Id</th>
<th>Name</th>
<th>Age</th>
<th></th>
</tr>
<?php
// Read
$per_page = 7;
if (isset($_GET["page"]))
$page = $_GET["page"];
else
$page = 1;
$start_from = ($page-1) * $per_page;
$sql = "select * from tbl_1";
$result = $mydb->query($sql);
while ($readrow = $result->fetch_array()) {
?>
<tr>
<td><?php echo $readrow['id']; ?></td>
<td><?php echo $readrow['name']; ?></td>
<td><?php echo $readrow['age']; ?></td>
<td>

Answer 1

There are couple of things you need to change in your code, such as:
You need to change your form's action attribute in the following way,
<form action="test.php?id=<?php echo $readrow['id']; ?>" method="post">
<input type="submit" class="btn btn-info btn-xs" name="submit" value="Copy"/>
</form>
Subsequently, you have to catch a particular row's id in test.php page the following way,
$id = (int)$_GET['id'];
Finally perform your INSERT operation in the following way,
if(isset($_POST['submit'])){
$id = (int)$_GET['id'];
$SQL = "INSERT INTO tbl_2(name, age) SELECT name, age FROM tbl_1 WHERE id = {$id}";
$result = mysql_query($SQL);
}
Sidenote: Don't use mysql_* functions, they are deprecated as of PHP 5.5 and are removed altogether in PHP 7.0. Use mysqli or pdo instead. And this is why you shouldn't use mysql_* functions.

Answer 2

Since you already mentioned tbl_2 has the same structure as tbl_1, you may simply construct your DB query as:
insert into tbl_2(id, name, age) select tbl_1.id, tbl_1.name, tbl_1.age from tbl_1 left join tbl_2 on tbl_1.id = tbl_2.id;
What this does:
It scans tbl_1 and inserts any values that are missing in
tbl_2 table. It has the potential to insert duplicate values. For
that, you should have enough robust DB structure that avoids
duplicate values in a table (using unique keys etc).