PHP password_verify not working against database - php

I'm trying to me a page more secure and I started with the password encrypting part of it. I'm trying to implement password_hash + password verify, but so far I've been unsuccessful to make the whole thing work. So, here it is in my login area:
$username = mysqli_real_escape_string($connection, $_POST['username']);
$password = mysqli_real_escape_string($connection, $_POST['password']);
$query = "SELECT username, password FROM `users` WHERE username='$username' and user_enabled='1'";
$result = mysqli_query($connection, $query) or die(mysqli_error($connection));
if($row = mysqli_fetch_assoc($result)) { $dbpassword = $row['password']; }
if(password_verify($password, $dbpassword)) {
echo "Successful login";
}else{
echo "Invalid Login Credentials.";
}
I always get Invalid Login Credentials.
When I modify the new password for the user, I am doing the following:
$pass = mysqli_real_escape_string($connection, $_POST['password']);
$options = [ 'cost' => 10,
'salt' => mcrypt_create_iv(22, MCRYPT_DEV_URANDOM),
];
$password = password_hash($pass, PASSWORD_BCRYPT, $options)."\n";
$query = "UPDATE users
SET `password` = '".$password."'
WHERE id = ".$_POST['user_id']."
";
$result = mysqli_query($connection, $query) or die(mysqli_error($connection));
password in database is VARCHAR(255), and it is storing something like:
$2y$10$Y5HIyAsLMfkXIFSJONPsfO3Gxx3b46H.8/WFdLVH3Fqk2XNfy2Uaq
What am I doing wrong here?

The \n in the following line, is embedding a linebreak, (Edit: one that cannot be included in the user inputted password).
$password = password_hash($pass, PASSWORD_BCRYPT, $options)."\n";
and you need to delete it and start over with a new hash.
Jay Blanchard, a member here on Stack submitted a note about it not too long also in the password_hash() manual, which is something that he and I actually talked about.
Be care when using the example from the documentation which concatenates a newline character \n to the end of the hash, i.e.:
echo password_hash("rasmuslerdorf", PASSWORD_DEFAULT)."\n";
People are storing the hash with the concatenated newline and consequently password_verify() will fail.
Another option would be to use trim(); that also works (at the moment of hashing).
$password = password_hash($pass, PASSWORD_BCRYPT, $options)."\n";
$password = trim($password);
// Store in db after
Yet you still need to start over by clearing the old hash(es) and creating new ones.
Do keep in mind though, that you shouldn't escape passwords.
One such as 123'\abc (being perfectly valid) will be modified to 123\'\abc by real_escape_string(); it's not needed. password_verify() takes care of that, security-wise.

Related

md5 doesn't work when decrypting and validating login details

I have encrypted and store password. Once user login I want to decrypt and validate .But following code is not able to do that. Can any body help with this?
<?php
include("config.php");
if($_SERVER["REQUEST_METHOD"] == "POST") {
$myusername = mysqli_real_escape_string($con,$_POST['username']);
$mypassword =md5(mysqli_real_escape_string($con,$_POST['password']));
$sql = "SELECT id FROM services WHERE user_name = '$myusername' and password = '$mypassword'";
$result = mysqli_query($con,$sql);
$row = mysqli_fetch_array($result,MYSQLI_ASSOC);
$count = mysqli_num_rows($result);
if($count == 1) {
echo "success";
}else {
echo "fail";
}
}
?>
It isn't necessary to escape value, that will be md5-hashed. You even could change the password (and md5 hash) if it contains some special char. For example, lets see at password's test' hashes:
echo md5(mysqli_real_escape_string($con,$_POST['password']));
echo md5($_POST['password']);
Output is:
e1e7975d4f1958297ede35ea4fc13a27
5c28a8c6d799d302f3ef53afefdfc81b
You shouldn't do:
$row = mysqli_fetch_array($result,MYSQLI_ASSOC);
because you don't use it later and you don't check if num_rows > 0 and it'll give an error if there are 0 records.
md5 should never ever be used for storing passwords.
First off it's been known to be broken for decades already, but that's not the worst of it in this case.
Secondly you're using it without a random salt, which makes it vulnerable to rainbow table attacks.
Finally, and most crucially, it's a fast algorithm, and hence completely unsuitable for password hashing. Any hacker worth their "salt" that gets a hold of your user's hashed passwords will make short work of finding >90% of the passwords in a matter of hours as your users will use predictable passwords instead of truly random ones.
You really need to use something like password_hash().
I found other method and this was success.Thank for your help
<?php
include('config.php');
session_start();
if($_SERVER['REQUEST_METHOD'] == "POST")
{
//Username and Password sent from Form
$username = mysqli_real_escape_string($con, $_POST['username']);
$password = mysqli_real_escape_string($con, $_POST['password']);
$password = md5($password);
$sql = "SELECT * FROM services WHERE user_name='$username' AND '$password'";
$query = mysqli_query($con, $sql);
$res=mysqli_num_rows($query);
//If result match $username and $password Table row must be 1 row
if($res == 1)
{
//header("Location: welcome.php");
echo "did";
}
else
{
echo "Invalid Username or Password";
}
}
?>

About hashing passwords with argon2i

I set up a dev server and I installed nginx with php-fpm and 7.2 php (I installed all the necessary php packages).
The time has come to upgrade the security of all logins, using the argon2i algo.
So, I tried this (test code in dev enviroment. The security in the code, will come later):
require('connector.php');
$usr_u = $_POST['username'];
$psw_u = $_POST['password'];
$usr = mysqli_real_escape_string($conn, $usr_u);
$psw = mysqli_real_escape_string($conn, $psw_u);
$f_pass = password_hash($psw, PASSWORD_ARGON2I);
$result = "SELECT `username` FROM `users` WHERE username = '$usr'";
$tbl = mysqli_query($conn, $result);
$table = $tbl->fetch_assoc();
$m_user = $table['username'];
if ($m_user == $usr)
{
//correct username
echo 'Correct username!<br>';
$result = "SELECT `password` FROM `users` WHERE username = '$m_user'";
$tbl = mysqli_query($conn, $result);
$table = $tbl->fetch_assoc();
$m_pass = $table['password'];
if (password_verify($m_pass,$f_pass)) //always returns false
{
echo 'Password correct!<br>';
}
else
{
echo 'Wrong password!<br>';
}
}
else
{
echo 'Wrong username!<br>';
}
//close connection
mysqli_close($conn);
I always get "Correct username!" and "Wrong password!". I used echo on hashed password from the DB and from the input and I see that every time the hashed password is different. I assume that the hashing process, include using random salt and there is my issue.
As far as I understand, the random salt is necessary in order to retain the security of the hashing.
Can you please point me to the right direction, on how to solve this? I have the hashed password in my DB and I can't figure out a way to check the input password against the one in my DB (using password_verify and hash_equals).
Thank everyone in advance for the help.
Look at the documentation for password_verify:
bool password_verify ( string $password , string $hash )
The first argument is the password but you are passing it the hash you want to compare it to.
The second argument is the hash you want to compare it to but you are passing it a new hash created from user input.
password_verify($_POST['password'], $m_pass)

password_verify not returning true/false

I have a problem with trying to login using the saved hash from my database, I save my password the following way, which works fine:
adduser($conn, '3', $username, $password);
This calls the following function:
function adduser ($conn, $level, $username, $password)
{
$password = mysqli_real_escape_string($conn, $password);
$password = mysqli_real_escape_string($conn, $username);
$password = password_hash($password, PASSWORD_BCRYPT);
$user = "INSERT INTO users (level, username, password)
VALUES ('$level', '$username', '$password')";
mysqli_query($conn, $user) or die (mysqli_error($conn));
}
My password field is a CHAR(60) so the stored password hash should be the right size.
When I try to login I call this function:
if (login($conn, $username, $password) === true){
}
Which exists here:
function login ($conn, $username, $password)
{
$password = mysqli_real_escape_string($conn, $password);
$username = mysqli_real_escape_string($conn, $username);
$query = "SELECT password FROM `users` WHERE username='$username'";
$result = mysqli_query($conn, $query) or die(mysqli_error($conn));
$row = mysqli_fetch_array($result, MYSQLI_ASSOC);
$hash = $row["password"];
$verify = password_verify($password, $hash);
if ($verify)
{
return true;
}
else
{
return false;
}
}
My issue is that it never returns true or false, which makes it impossible for me to login...
Extra:
It succesfully post to database
I also tried running this, which succesfully posted the data from my database
$query = "SELECT password FROM `users` WHERE username='$username'";
$result = mysqli_query($conn, $query) or die(mysqli_error($conn));
$row = mysqli_fetch_array($result, MYSQLI_ASSOC);
echo $row["password"];
Update
Doing this:
echo '<br/>';
echo $hash;
echo '<br/>';
echo $password;
Gives me the following output:
$2y$10$OfJhVve4GMZRfjfelb8sNOJ7EN5NAAGOmsN6OS/SC7PZGU5mDNOou
hej
Which matches the password in my database
$2y$10$OfJhVve4GMZRfjfelb8sNOJ7EN5NAAGOmsN6OS/SC7PZGU5mDNOou
After testing your entire code, I have come to the following conclusion.
The problem here is that you are escaping the password while inserting it into your database, which is something I did raise in comments from the beginning.
"side note: you shouldn't escape a password/hash function, passwords such as 123'\abc< are perfectly valid and will be modified on insertion."
$password = mysqli_real_escape_string($conn, $username);
Side note for ^ - Consult Edit #2 below, near "However...":
Simply don't use it, just keep/use the assignment normally.
Both password_hash() and password_verify() do their job, so there's no need to escape passwords.
You will need to remove it from the code that you used to insert it into the database with, and start over again with a new set of hashes.
That escaping function is most likely adding a character during insertion.
Side note: Just for the record, my password column is VARCHAR, yet that shoulnd't be a difference from your CHAR (Edit: consult footnote). If it is then ALTER your column to be VARCHAR.
The manual on password_hash() though, suggests using 255 for a length, being a good bet.
http://php.net/manual/en/function.password-hash.php
Edit footnote:
As per a comment I posted beneath my answer.
It looks to have a difference. This Q&A What's the difference between VARCHAR and CHAR? shows it, as per the accepted answer
VARCHAR is variable-length.
CHAR is fixed length.
https://stackoverflow.com/a/1885635/1415724
Edit #2:
After further testing to see if it made a difference by ALTER'ing the password column from VARCHAR(255) to CHAR(60) made a difference; it did not.
Tests performed:
Inserted a new hash without the escaping function and verifying: TRUE.
Inserted a new hash with the escaping function and verifying: FALSE.
Therefore and as I stated originally; the fault lies with the use of mysqli_real_escape_string().
However and going over your code again, this line:
$password = mysqli_real_escape_string($conn, $username);
You were using the $username variable here which also accounts for the wrong value being inserted in the database. All of these put together were the problems from the get go.

pass in password_hash field with pdo [duplicate]

This question already has answers here:
Using PHP 5.5's password_hash and password_verify function
(4 answers)
Closed 3 years ago.
I am trying to process a password as md5 into the database, this is the concerned code:
include_once("config.php");
session_start();
if(isset($_POST['signup'])){
$name = $_POST['name'];
$email = $_POST['email'];
$pass = $_POST['pass'];
$insert = $pdo->prepare("INSERT INTO users (name,email,pass)
values(:name,:email,:pass) ");
$insert->bindParam(':name',$name);
$insert->bindParam(':email',$email);
$insert->bindParam(':pass',$pass);
$insert->execute();
}elseif(isset($_POST['signin'])){
$email = $_POST['email'];
$pass = $_POST['pass'];
$select = $pdo->prepare("SELECT * FROM users WHERE email='$email' and pass='$pass'");
$select->setFetchMode();
$select->execute();
$data=$select->fetch();
if($data['email']!=$email and $data['pass']!=$pass) {
echo "invalid email or pass";
}
elseif($data['email']==$email and $data['pass']==$pass) {
$_SESSION['email']=$data['email'];
$_SESSION['name']=$data['name'];
header("location:profile.php");
}
}
What length in the db would be appropriate to store this hashed password?
And how do I use this:
$hashed_password = password_hash($pass, PASSWORD_DEFAULT);
var_dump($hashed_password);
and the if statement if the password was ok?
Its really quite simple once you read the manual or see an example in a tutorial. See comments in the code for details
<?php
include_once("config.php");
session_start();
if(isset($_POST['signup'])){
$name = $_POST['name'];
$email = $_POST['email'];
// at signup you hash the user provided password
$pass = password_hash($_POST['pass'], PASSWORD_DEFAULT);
$insert = $pdo->prepare("INSERT INTO users (name,email,pass)
values(:name,:email,:pass) ");
$insert->bindParam(':name',$name);
$insert->bindParam(':email',$email);
$insert->bindParam(':pass',$pass); // this stores the hashed password
$insert->execute();
}elseif(isset($_POST['signin'])){
$email = $_POST['email'];
$pass = $_POST['pass'];
// as the password on the DB is hashed you cannot use the
// plain text password in the SELECT here as it wont match
$select = $pdo->prepare("SELECT * FROM users WHERE email=:email");
// no idea what this was doing
//$select->setFetchMode();
$select->bindParam(':email',$email);
$select->execute();
$row = $select->fetch(PDO::FETCH_ASSOC);
// verify the plain text password against the
// hashed value from DB in $row['pass']
if( password_verify($pass, $row['pass']) ){
$_SESSION['email'] = $data['email'];
$_SESSION['name'] = $data['name'];
header("location:profile.php");
exit;
} else {
echo "invalid email or pass";
}
}
And as to the length of the column in the database that you need to hold this hashed value, it is documented in the manual
The following algorithms are currently supported:
PASSWORD_DEFAULT - Use the bcrypt algorithm (default as of PHP 5.5.0). Note that this constant is designed to change over time as new and stronger algorithms are added to PHP. For that reason, the length of the result from using this identifier can change over time. Therefore, it is recommended to store the result in a database column that can expand beyond 60 characters (255 characters would be a good choice).
PASSWORD_BCRYPT - Use the CRYPT_BLOWFISH algorithm to create the hash. This will produce a standard crypt() compatible hash using the "$2y$" identifier. The result will always be a 60 character string, or FALSE on failure.

Password is not verified using function password_verify

I think i have hashed password using function PASSWORD directly from mysql database(am i doing wrong here?). And i am trying to verify that password with this code:
if($submit)
{
$first=$_POST['first'];
$password=$_POST['password'];
$hash="*85955899FF0A8CDC2CC36745267ABA38EAD1D28"; //this is the hashed password i got by using function PASSWORD in database
$password=password_verify($password,$hash);
$db = new mysqli("localhost", "root","","learndb");
$sql = "select * from admin where username = '" . $first . "' and password = '". $password . "'";
$result = $db->query($sql);
$result=mysqli_num_rows($result);
if($result>0)
{
session_start();
$_SESSION['logged_in'] = true;
session_regenerate_id(true);
header("Location:loginhome.php");
}
}
But the password is not matching. What am i missing here?
UPDATE:
After all the suggestions i have used password_hash from php code to store into database.
$db = new mysqli("localhost", "root","","learndb");
$password=password_hash('ChRisJoRdAn123',PASSWORD_DEFAULT);
$sql="INSERT INTO admin (username,password)values('ChrisJordan','$password')";
$db->query($sql);
still the password is not matching.
One cannot search for a salted password hash in a database. To calculate the hash you need the password_hash() function as you already did correctly in your insert statement.
// Hash a new password for storing in the database.
// The function automatically generates a cryptographically safe salt.
$hashToStoreInDb = password_hash($password, PASSWORD_DEFAULT);
To check a password, you first need to search by username only (used a prepared query to avoid sql injection):
$sql = 'select * from admin where username = ?';
$db->prepare($sql);
$db->bind_param('s', $first);
When you finally got the stored hash from the database, it can be checked like this:
// Check if the hash of the entered login password, matches the stored hash.
// The salt and the cost factor will be extracted from $existingHashFromDb.
$isPasswordCorrect = password_verify($password, $existingHashFromDb);
password_verify is a boolean function which return either true or false. In your code, after getting value of password from Post param, you doing this operation
$password=password_verify($password,$hash);
which changes the $password value to true or false and that boolean value stored in $password you are using in mysql select statement
$sql = "select * from admin where username = '" . $first . "' and password = '". $password . "'";
Another thing is it might be possible that the hashed/salted password you are using is not the correct hashed value of the password you are using.
Update: Try this
$cost = [
'cost' => 15,
];
$hash_password = password_hash('ChRisJoRdAn123', PASSWORD_BCRYPT, $cost);
before any db operation, change your password field varchar length to >=64
$sql = "INSERT INTO admin (username,password)values('ChrisJordan','".$hash_password."')";
After insert operation, execute the select statement with the user
$sql = "select * from admin where username = 'ChrisJordan'";
after this fetching hased password and password from the post parameter, you will need to verify both passwords using password_verify
if (password_verify(validate($_POST['password']), $hash_password_from_db)) {
echo "Valid Password";
}else{
echo "Invalid Password";
}
You must use password_hash to encode passwords verified with password_verify.
The MySQL function PASSWORD is something entirely different. It is used for encoding passwords specific to MySQL authentication. (MySQL specifically recommends against using PASSWORD for anything other than MySQL authentication.)
The two use different hashing algorithms, present their output in different formats, and are generally not compatible with each other.
The typical way to use password_hash and password_verify is:
$hash = password_hash($password, PASSWORD_DEFAULT);
//Store $hash in your database as the user's password
//To verify:
//Retrieve $hash from the database, given a username
$valid = password_validate($password, $hash);
The problem in your code is that you're doing this:
$password=password_verify($password,$hash);
$sql = "select * from admin where username = '" . $first . "' and password = '". $password . "'";
password_verify returns a boolean (whether the password and hash matched). Instead, you need to retrieve the hash from the database and match the entered password with that hash.
This is too long for a comment.
Seeing that this question has yet to contain a green tick next to any of the answers, am submitting the following in order to point out probable issues.
I noticed that you are trying to move over from MD5 to password_hash() - password_verify().
Your other question Switching from md5 to password_hash
What you need to know is that MD5 produces a 32 character length string, as opposed to password_hash() being a 60 length.
Use varchar(255).
If you kept your password column's length to 32, then you will need to clear out your existing hashes from that column, then ALTER your column to be 60, or 255 as the manual suggests you do.
You will need to clear out all your existing passwords, ALTER your column, create a new hash, then try your login code again.
I see this in your code:
"*85955899FF0A8CDC2CC36745267ABA38EAD1D28"; //this is the hashed password i got by using function PASSWORD in database
This string *85955899FF0A8CDC2CC36745267ABA38EAD1D28 is 40 long, which is too short and has been cut off.
This tells me that your column's length is 40, instead of 60, or again as the manual suggests, 255.
MD5 reference:
http://php.net/manual/en/function.md5.php
Returns the hash as a 32-character hexadecimal number.
Reference for password_hash():
http://php.net/manual/en/function.password-hash.php
The result will always be a 60 character string, or FALSE on failure.
To ALTER your column, here is a reference link:
http://dev.mysql.com/doc/refman/5.7/en/alter-table.html
Also make sure that your form contains a POST method and that the inputs bear the matching name attributes and that no whitespace gets introduced.
You can use trim() to get rid of those.
Add error reporting to the top of your file(s) which will help find errors.
<?php
error_reporting(E_ALL);
ini_set('display_errors', 1);
// Then the rest of your code
Sidenote: Displaying errors should only be done in staging, and never production.
as well as or die(mysqli_error($db)) to mysqli_query().
Edit:
What you need to do is fetch an array and get the match on that.
$sql = "select * from admin where username = '".$first."' and password = '".$password."' ";
$result = $db->query($sql);
if ($result->num_rows === 1) {
$row = $result->fetch_array(MYSQLI_ASSOC);
if (password_verify($password, $row['password'])) {
//Password matches, so create the session
// $_SESSION['user']['user_id'] = $row['user_id'];
// header("Location:/members");
echo "Match";
}else{
echo "The username or password do not match";
}
}
Another possible solution:
$query = "SELECT * from admin WHERE username='$first'";
$result = $db->query($query);
if($result->num_rows ===1){
$row = $result->fetch_array(MYSQLI_ASSOC);
if (password_verify($password, $row['password'])){
echo "match";
} else {
$error = "email or Password is invalid";
echo $error;
}
}
mysqli_close($db); // Closing Connection

Categories