This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 5 years ago.
The highlighted line is line 24
Notice: Undefined index: action in C:\xampp\htdocs\authors.php on line 24
**if($_GET['action'] == "list") {**
$current = "members";
$list = "members";
}
else if($_GET["list"] == "authors") $current = "authors";
else $current = "members";
Check first if $_GET['action'] has been set or not
if(isset($_GET['action'])) {
if($_GET['action'] == "list") {
$current = "members";
$list = "members";
} else if($_GET["list"] == "authors") {
$current = "authors";
} else {
$current = "members";
}
}
Related
This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 1 year ago.
I found the problem on my old apps, PHP Notice: Undefined offset: 1
This is the code:
$uri = "sub.examples.com";
$pageurl = explode("/",$uri);
if($uri=='/') {
$homeurl = "https://".$_SERVER['HTTP_HOST'];
(isset($pageurl[1])) ? $pg = $pageurl[1] : $pg = '';
(isset($pageurl[2])) ? $ac = $pageurl[2] : $ac = '';
(isset($pageurl[3])) ? $id = $pageurl[3] : $id = 0;
} else {
$homeurl = "https://".$_SERVER['HTTP_HOST'].$pageurl[1];
(isset($pageurl[2])) ? $pg = $pageurl[2] : $pg = '';
(isset($pageurl[3])) ? $ac = $pageurl[3] : $ac = '';
(isset($pageurl[4])) ? $id = $pageurl[4] : $id = 0;
}
The errors in the line
$homeurl = "https://".$_SERVER['HTTP_HOST'].$pageurl[1];
Can anyone provide a solution?
Thanks,
Regards.
$homeurl = "https://".$_SERVER['HTTP_HOST'].$pageurl[0];
replace this line.
This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 5 years ago.
anyone can help me?
i used this code for managing pages
and it's get
undefined index : page
undefined index : aksi
<?php
$page = $_GET['page'];
$aksi = $_GET['aksi'];
if($page == "") {
if($aksi == "") {
include "page/dashboard.php";
}
} elseif($page == "dashboard") {
if($aksi == "") {
include "page/dashboard.php";
}
}elseif($page == "masuk") {
if($aksi == "") {
include "page/kas_masuk/masuk.php";
}
if($aksi == "hapus") {
include "page/kas_masuk/hapus.php";
}
}
?>
Use isset() function like below,
UPDATE
To get value of $_GET[] use below
$page = (isset($_GET['page'])?$_GET['page']:'');
$aksi = (isset($_GET['aksi'])?$_GET['aksi']:'');
Now we will get value if $_GET[] have value otherwise empty without returning any error or warning
This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 6 years ago.
So i've got a rather complex bit of code that i'm trying to make work (actually; it works fine on my test server but not so much my live server. so i'm trying to make it rework) -- it keeps telling me that a variable i'm asking it to check with isset is not a defined variable. I'm probably over thinking this whole method and there's probably a simplier way. but i need you guys to bash me over the head with it apparently
include('bootstra.php');
include('includes/parts/head.php');
if(!isset($_SESSION['user']['uid']))
{
echo $html;
include('includes/parts/login.php');
if(isset($_GET['mode']))
{
$file = $_GET['mode'];
$path = "includes/parts/{$file}.php";
if (file_exists($path)) {
require_once($path);
} else {
die("The Page REquested could not be found!");
}
}
else
{
include('includes/parts/frontpage.php');
}
}
else
{
if(!isset($_SESSION['x']) || !isset($_SESSION['y']))
{
if(isset($_GET['x']) && isset($_GET['y']))
{
$_SESSION['x'] = $_GET['x'];
$_SESSION['y'] = $_GET['y'];
}
else
{
$_SESSION['x'] = 0;
$_SESSION['y'] = 0;
}
header("location:index.php?x={$_SESSION['x']}&y={$_SESSION['y']}");
}
else
{
if($_SESSION['x'] != $_GET['x'] || $_SESSION['y'] != $_GET['y'] )
{
header("location:index.php?x={$_SESSION['x']}&y={$_SESSION['y']}");
}
else
{
echo $html;
echo $base->displayMap($_GET['x'], $_GET['y']);
include('includes/context_menu.php');
}
}
}
Here is the exact error:
Notice: Undefined index: x in /home/****/public_html/reddactgame/index.php on line 27
Change it
<pre>
if( !isset($_SESSION['x']) || !isset($_SESSION['y']) )
</pre>
to
<pre>
if( !( isset($_SESSION['x']) && isset($_SESSION['y']) ) )
</pre>
There is no error, that is a Warning...
It is saying that $_SESSION['x'] was never setted, so, when you do that isset it tells you that it was never declared.
Example:
This gives you the same warning
empty($x);
This does not give you warning
$x = 0;
empty($x);
EDIT
I see this is a common question, so here is a better explanation.
This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 7 years ago.
I have made this for loop to get a variable amount of columns selected from the database. As I'm running this, I get an error saying :
Notice: Undefined variable: kolom_1
Notice: Undefined variable: kolom_2
Notice: Undefined variable: kolom_3
Notice: Undefined variable: kolom_4
Notice: Undefined variable: kolom_5
Notice: Undefined variable: kolom_6
But I have it all placed in a for loop, why does he not recognize them? I am not getting what I'm doing wrong.
function lijst_ophalen($data, $from){
$totaal = count($data);
for ($i=1; $i<$totaal; $i++){
$kolom_[$i] = $this->mysqli->real_escape_string($data['kolom_' . $i . '']);
if($kolom_[$i]!="") $kolom_[$i] = "{$kolom_[$i]},"; else $kolom_[$i]="";
if($kolom_[$i]==$totaal) $kolom_[$i] = "{$kolom_[$i]}";
}
$from_table = "";
$categorie = "";
if($from == "bv"){
$from_table = "klanten_algemene_gegevens_bv";
$categorie = "";
}
if(($from == "1manszaak") || ($from == "vof")){
$from_table = "klanten_algemene_gegevens_vof_1manszaak";
if($from == "1manszaak"){
$categorie = "1manszaak";
}
if($from == "vof"){
$categorie = "vof";
}
$categorie = "WHERE soort_onderneming = '{$categorie}'";
}
if($from == "ib"){
$from_table = "klanten_ib";
$categorie = "";
}
$result = $this->mysqli->query(
<<<EOT
SELECT
{$kolom_1}
{$kolom_2}
{$kolom_3}
{$kolom_4}
{$kolom_5}
{$kolom_6}
FROM {$from_table}
{$categorie}
EOT
);
if($result){
$waardes = array();
while ($row = $result->fetch_assoc()) {
$waardes[]=$row;
}
return $waardes;
}
}
When you are initializing / filling data into the $kolom_ you are creating an' array instead of your (properly) intended series of different variables.
$kolom_[$i] <--- ARRAY
And lower down you are calling a series of variables $kolom_1, which doesn't exist because you created an' array and not a series of variables.
To avoid the error you can simply change your
$kolom_1
$kolom_2 (and so on)
calls into
$kolom_[1]
$kolom_[2] (and so on)
and you should be set to go.
This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 8 years ago.
I was trying to print the value of a variable from a function, but it is showing undefined variable value. Please help me and tell me how to solve this problem; I'm pretty new
to PHP coding. I tried the function as public, but it shows some other error.
<?php
if(isset($_POST['btn_submit']))
{
$num1 = $_POST['cards1'];
$num2 = $_POST['cards2'];
$num1=substr($num1,0,(strlen($num1)-1));
$num2=substr($num2,0,(strlen($num2)-1));
}
function get_value() {
switch ($num2) {
case 'A' :
$value = 11;
break;
case 'J':
case 'Q':
case 'K':
$value = 10;
break;
default:
$value = $num2;
break;
}
//return $value;
}
echo '<script type="text/javascript">alert("Out Put is'.$value.' ");</script>';
//$total_value = $num1+$num2;
?>
$num2 is local to your function. You need to pass it in as a parameter:
function get_value($num2) {
*** YOUR CODE
}