My function doesn't post in the database - php

Question

So I tried coding a function that allows the user to post a mood, chosen by a slider. I succeeded in connecting the color with an ID, then I tried making a post function. However Nothing happens.
this is where i call the functions.
if (isset($_POST['ready'])) {
$mood = new Post();
$moodColor = $_POST['mood'];
$statementMood = $mood->getMood($moodColor); //connects the color with an ID
while ($row = $statementMood->fetch(PDO::FETCH_ASSOC)) {
$moodID = $row['moodID'];
}
$moodID = $_GET['moodID'];
$userID = $currentUser['userID'];
$statementPost = $mood->postMood(); //put the emotion in the database.
//header('location: home.php');
}
these are the two functions.
public function getMood($moodColor){
$conn = db::getInstance();
$statementMood = $conn->prepare("SELECT * FROM moods WHERE color = :cMood");
$statementMood->bindParam(":cMood", $moodColor);
$statementMood->execute();
return $statementMood;
}
public function postMood(){
$conn = db::getInstance();
$statementPost = $conn->prepare("INSERT INTO postsmoodi (userID, moodID) VALUES (:userID, :moodID)");
$statementPost ->bindValue(':userID', $this->userID);
$statementPost->bindValue(':moodID', $this->moodID);
return $statementPost->execute();
}
this is the form where the button to post is.
<form class="input" action="mood.php" method="get">
<input id="hiddenValue" type="hidden" class="data" name="mood" value="">
<button class="moodReady" type="submit" name="ready">Ready</button>
</form>

Answer 1

Use $_GET instead of $_POST, as your form uses method="get"
if (isset($_GET['ready'])) {
$mood = new Post();
$moodColor = $_POST['mood'];
$statementMood = $mood->getMood($moodColor); //connects the color with an ID
while ($row = $statementMood->fetch(PDO::FETCH_ASSOC)) {
$moodID = $row['moodID'];
}
$moodID = $_GET['moodID'];
$userID = $currentUser['userID'];
$statementPost = $mood->postMood(); //put the emotion in the database.
//header('location: home.php');
}