When i uploading .csv file Load data infile query is not working.
My php code is:
include "../../connection.php";
if ($_FILES["file"]["error"] > 0) {
echo "Error: " . $_FILES["file"]["error"] . "<br>";
} else {
echo "Upload: " . $_FILES["file"]["name"] . "<br>";
echo "Type: " . $_FILES["file"]["type"] . "<br>";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br>";
echo "Stored in: " . $_FILES["file"]["tmp_name"];
echo '<br>';
$a = $_FILES["file"]["tmp_name"];
$csv_file = str_replace("\\", "/", "$a");
echo $csv_file;
echo '<br>';
$query = "LOAD DATA INFILE '$csv_file' INTO TABLE `competency_questions` FIELDS TERMINATED BY ',' ENCLOSED BY '\"' ESCAPED BY '\\' LINES TERMINATED BY '\r\n'";
$s = mysql_query($query);
if ($s) {
echo "<script>alert('Record successfully uploaded.');window.location.href='../../view all test.php?id=$cid';</script>";
} else {
echo 'Failed';
}
}
And It shows Failed Error.
Image
Anyone Help me to resolve this issue?
Related
I am having an issue with undefined error in my php. After research I know I know I should use isset but I'm not sure how to implement it. Here is the peice of code that causes the issue:
if (($_FILES["file"]["type"] == "video/mp4") && ($_FILES["file"]["size"] < 20000))
{
Should I put the isset inside the if function before each $_FILES or where should it go ?
Here is the full piece of code, as you will probably notice I am quite new to PHP:
$ivalid_file='0';
if (($_FILES["file"]["type"] == "video/mp4") && ($_FILES["file"]["size"] < 20000))
{
if ($_FILES["file"]["error"] > 0)
{
echo "Return Code: " . $_FILES["file"]["error"] . "<br />";
}
else
{
echo "Upload: " . $_FILES["file"]["name"] . "<br />";
echo "Type: " . $_FILES["file"]["type"] . "<br />";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />";
echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />";
if (file_exists("uploads/" . $_FILES["file"]["name"]))
{
echo $_FILES["file"]["name"] . " already exists. ";
}
else
{
move_uploaded_file($_FILES["file"]["tmp_name"],
"uploads/" . $_FILES["file"]["name"]);
echo "Stored in: " . "uploads/" . $_FILES["file"]["name"];
}
}
}
else
{
echo "invalid_file";
}
As far as I understand, you want to know how to check if the file was ever uploaded and how to implement it in code. All you gotta do is, wrap you entire code in an if block which checks if $_FILES['files'] is set like so:
//Check if "file" exists here:
if(isset($_FILES["file"])) {
$ivalid_file='0';
if (($_FILES["file"]["type"] == "video/mp4") && ($_FILES["file"]["size"] < 20000))
{
if ($_FILES["file"]["error"] > 0)
{
echo "Return Code: " . $_FILES["file"]["error"] . "<br />";
}
else
{
echo "Upload: " . $_FILES["file"]["name"] . "<br />";
echo "Type: " . $_FILES["file"]["type"] . "<br />";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />";
echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />";
if (file_exists("uploads/" . $_FILES["file"]["name"]))
{
echo $_FILES["file"]["name"] . " already exists. ";
}
else
{
move_uploaded_file($_FILES["file"]["tmp_name"],
"uploads/" . $_FILES["file"]["name"]);
echo "Stored in: " . "uploads/" . $_FILES["file"]["name"];
}
}
}
else
{
echo "invalid_file";
}
} else {
// Display appropriate error
}
I have made a php code to upload a file....It uploads it sucessfully...but how do i phsicaly go and check where it is...?
NOTE : i am getting fail as output from the move_uploaded_file ()
here's my code :
<?php
$allowedExts = array("c", "cpp", "py", "java");
$temp = explode(".", $_FILES["file"]["name"]);
$extension = end($temp);
if ( ($_FILES["file"]["size"] < 100000) && in_array($extension, $allowedExts))
{
if ($_FILES["file"]["error"] > 0)
{
echo "Return Code: " . $_FILES["file"]["error"] . "<br>";
}
else
{
echo "Upload: " . $_FILES["file"]["name"] . "<br>";
echo "Type: " . $_FILES["file"]["type"] . "<br>";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " kB<br>";
echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br>";
if (file_exists("upload/" . $_FILES["file"]["name"])) {
echo $_FILES["file"]["name"] . " already exists. ";
}
else
{
mkdir ("./upload");
if (move_uploaded_file($_FILES["file"]["tmp_name"],"./upload/" . $_FILES["file"]["name"]))
{
echo "sucess";
}
else
{
echo "fail";
}
}
}
}
else
{
echo "Invalid file";
}
?>
you first check if move_uploaded_file actually able to move file or not as the directory you are moving must have write permissions otherwise move_uploaded_file fails
http://php.net/manual/en/function.move-uploaded-file.php
so must check like
if(move_uploaded_file($_FILES["file"]["tmp_name"],"./upload/" . $_FILES["file"]["name"])
//file moved
else
//error
I am trying to combined these two script (a file upload) and (a mysql update) so that the image file is both uploaded to the correct folder and the file path is then updated in the mysql database. I know the $sql update query is wrong and thats where my trouble is. Any help would be great.
//db connection
require "connect.db.php";
if ((($_FILES["file"]["type"] == "image/gif")
|| ($_FILES["file"]["type"] == "image/jpeg")
|| ($_FILES["file"]["type"] == "image/pjpeg"))
&& ($_FILES["file"]["size"] < 20000))
{
if ($_FILES["file"]["error"] > 0)
{
echo "Return Code: " . $_FILES["file"]["error"] . "<br />";
}
else
{
echo "Upload: " . $_FILES["file"]["name"] . "<br />";
echo "Type: " . $_FILES["file"]["type"] . "<br />";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />";
echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />";
if (file_exists("upload/" . $_FILES["file"]["name"]))
{
echo $_FILES["file"]["name"] . " already exists. ";
}
else
{
move_uploaded_file($_FILES["file"]["tmp_name"],
"upload/" . $_FILES["file"]["name"]);
echo "Stored in: " . "upload/" . $_FILES["file"]["name"];
}
}
}
else
{
echo "Invalid file";
}
// update data in mysql database
$sql="UPDATE `characters` SET ch_image='/upload/$_FILES["file"]["name"]' WHERE ID='$id'";
$result=mysql_query($sql);
// if successfully updated.
if($result){
echo "Successful";
echo "<BR>";
echo "<a href='test.html'>View result</a>";
touch('../file.html');
clearstatcache();
}
else {
echo "Whoops: " . mysql_error(); ;
}
mysql_close();
?>
change $sql to this
$sql="UPDATE `characters` SET ch_image='/upload/" . $_FILES['file']['name'] . "' WHERE ID='$id'";
Uploading an image into a directory, it seems to always try upload "" which is nothing. Rather then an actual image. What am I doing below. I know the value is "" because of what it inserts into the database.
<li class="formProductImage">
<span>Image:</span>
<input type="file" name="productImage" />
</li>
and the php:
if ($_FILES["productImage"]["error"] > 0)
{
echo "Return Code: " . $_FILES["productImage"]["error"] . "<br />";
}
else
{
echo "Upload: " . $_FILES["productImage"]["name"] . "<br />";
echo "Type: " . $_FILES["productImage"]["type"] . "<br />";
echo "Size: " . ($_FILES["productImage"]["size"] / 1024) . " Kb<br />";
echo "Temp file: " . $_FILES["productImage"]["tmp_name"] . "<br />";
$filename = mysql_real_escape_string($_FILES['productImage']['name']);
$query = "UPDATE products SET image = '$filename' WHERE name = '$name'";
$result = mysql_query($query);
if (mysql_affected_rows() == 1) {
// Show thank you message
echo '<span style="color:green;">Your image was added to database correctly.</span>';
if (file_exists("uploaded/" . $_FILES["productImage"]["name"]))
{
echo $_FILES["productImage"]["name"] . " already exists. ";
}
else
{
move_uploaded_file($_FILES["productImage"]["tmp_name"],
"uploaded/" . $_FILES["productImage"]["name"]);
echo "Stored in: " . "uploaded/" . $_FILES["productImage"]["name"];
}
} else {
echo '<font color="red">Image note inserted into database.</font>';
echo mysql_error();
}
}
}
}
Make sure you have enctype="multipart/form-data" in the <form> tag.
change this line:
$filename = mysql_real_escape_string($_FILES['file']['name']);
to :
$filename = mysql_real_escape_string($_FILES['productImage']['name']);
I'm a raw PHP beginner. Check out this sample upload script:
<?php
if ($_FILES["file"]["error"] > 0)
{
echo "Error: " . $_FILES["file"]["error"] . "<br />";
}
else
{
echo "Upload: " . $_FILES["file"]["name"] . "<br />";
echo "Type: " . $_FILES["file"]["type"] . "<br />";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />";
echo "Stored in: " . $_FILES["file"]["tmp_name"];
}
?>
Now, how to see exactly what values this built-in array contain? I cannot find such an info anywhere. Thanks for the time.
You mean var_dump($_FILES)? That tells you exactly what the array contains.