php post value from FOREACH to another page - php

Question

I've never asked any question here before, but after spending many hours searching for a hint I decided to ask a question.
I have a project at school where I need to create a table from DB for all records for one user, and then create an expanded view for all details for a chosen record.
So far I have:
$user = 'myuser';
$pass = 'mypassword';
$db = new PDO( 'mysql:host=localhost;dbname=mydb', $user, $pass );
$sql = "
SELECT id,login
FROM quotes_taxi
WHERE login='[usr_login]'";
$query = $db->prepare( $sql );
$query->execute();
$results
where 'id' is obviously ID for each record. Then I create a table using FOREACH
<?php foreach( $results as $row ){
echo '<tr>';
echo '<td>'; echo $row['id']; echo '</td>';
echo '<td>'; echo $row['login']; echo '</td>';
echo '<td>'; echo ' View All ';
echo '</td>';
echo "</tr>";
}
?>
the problem I am having is: how can I attached that 'id' within the link (and it needs to be a separate button for each ID), so I can pass it to the view/index.php where I am using
$quote_id = $_GET["id"];
to get all other details of a chosen ID...
I know I have an error in that line, I just cannot figure it what. I also assume it is an easy problem, but I just cannot get my head around it
any help is most appreciated.
Thank you

Answer 1

Try to separate your PHP and HTML that way it will be easier to find errors quickly. Try the following code.
<table>
<tr>
<th>Id</th>
<th>Login</th>
<th>View</th>
</tr>
<?php foreach ($results as $row) : ?>
<tr>
<td><?php echo $row['id']; ?></td>
<td><?php echo $row['login']; ?></td>
<td> View All </td>
</tr>
<?php endforeach; ?>
</table>
Output

Answer 2

I suggest this function
function AddGetParams()
{
$linkParams="";
foreach($GLOBALS["_GET"] as $key=>$value)
{
$linkParams.="$key=$value&";
}
return $linkParams;
}