Not able to get desired result in SELECT - php

Question

I'm new to PHP. I'm trying to display search result based on user query. My issue is that I'm not getting all other similar search results (only the exact results are showing). Is it the right method I'm implementing from security point of view? Thanks in advance.
define('HOST','localhost');
define('USER','root');
define('PASSWORD_HOST','');
define('DATABASE','test');
if(defined('HOST') && defined('USER') && defined('PASSWORD_HOST') && defined('DATABASE')){
$conn = mysqli_connect(HOST, USER, PASSWORD_HOST, DATABASE);
}else{
die(connection_failed.mysqli_connection_error());
}
Here is HTML
<div class="container">
<div class="row">
<div class="col-sm-12">
<form action="" method="POST">
<h4>Search By</h4>
<input type="text" name="delName"/>
<button type="submit" name="submit">search</button>
</form>
</div>
</div>
</div>
Here is PHP
if(isset($_POST['submit'])){
$delName = "%{$_POST['delName']}%";
$stmt =$conn->prepare("SELECT id, delName, medName, contact1, contact2, address, pin, creditLimitDealer FROM dealerentrytable WHERE delName LIKE ?");
$stmt->bind_param("s", $delName);
$stmt->execute();
$stmt->bind_result($id, $delName, $medName, $contact1, $contact2,$address,$pin,$creditLimitDealer);
while ($stmt->fetch()) {
echo "<table>";
echo "<tr><td>ID: $id</td>";
echo "<td>delName: $delName</td>";
echo "<td>medName: $medName</td>";
echo "<td>contact1: $contact1</td>";
echo "<td>contact2: $contact2</td>";
echo "<td>address: $address</td>";
echo "<td>pin: $pin</td>";
echo "<td>creditLimitDealer: $creditLimitDealer</td></tr>";
echo "</table>";
}
$stmt->close();
}
?>