Pass values from database to user uploaded HTML - php

Question

Updated with current Code*
I thought i would ask for your assistance regarding my issue.
Im wondering how i may go about replacing content that is contained in one column and take the value of another along with its own.
I have the following code and,
<table id="example1" class="table table-bordered table-striped">
<thead>
<tr>
<th>Template</th>
<th>SaleID</th>
<th>Description</th>
<th>Title</th>
<th>Price</th>
<th>Status</th>
<th>User Action</th>
</tr>
</thead>
<tbody>
<?php
$res = $MySQLiconn->query("SELECT * FROM crud WHERE uid='{$_SESSION['userSession']}' ORDER BY id DESC");
while($row=$res->fetch_array())
{
?>
<tr>
<td><!-- THIS COL WILL BE HTML CONTENT A USER UPLOADED ALREADY WHICH SHOULD HAVE THE OTHER VALUES MIXED IN (price, des, title) --></td>
<td><?php echo $row['saleid']; ?></td>
<td><?php echo $row['des']; ?></td>
<td><?php echo $row['title']; ?></td>
<td><?php echo $row['price']; ?></td>
<?php
if($row['status']=='Listed')
echo "<td><span class='label label-success'>".$row['status']."</span></td>";
else if($row['status']=='Awaiting')
echo "<td><span class='label label-warning'>".$row['status']."</span></td>";
?>
<td></i> </i> </i></td>
</tr>
<?php
}
?>
</tbody>
</table>

Answer 1

Example:
Model
public function select_data($id) {
$this->db->select(*); //or any fields
$this->db->where('id', $id);
$query = $this->db->get('table_name');
return $query->row_array();
}
Controller:
$data = $this->your_model_name->select_data($id); /id of the specified person
//pass data to the view
$this->load->view('your_view_file', $data);
View:
//display name or description where 'desc' is your filed name from DB
<? echo $data['desc'] ?>
or mix this with your static data:
<p>
My name is <? echo $data['name'] ?>.
</p>
<p>
Description of the person: <? echo $data['desc'] ?>
</p>