I'm confused or been to much in the sun, I have the following situation
when editing a product
http://app.dev/shops/1/products/2/edit
I added the /shops/1 in the URL because I need to know for what Shop I'm editing the Product.
Now in the Controller I need to know what Shop and Product we're talking about here.
I'm using the following hidden input field to send the product_id to the update Controller
<input type="hidden" name="product" value="{{ $product->id }}">
But how do I get the shop_id to the Update Controller. What's the best way to go about this?
Thank you!
route file
Route::get('/shops/{shopid}/products/{productid}' , 'testController#gettest');
In controller
Input::get('shops');
Input::get('products');
and also check this
Route::get('/', function(){
echo Input::get('shops');
echo Input::get('products');
});
laravel way
{{ Request::segment(3) }}
will give you the id and you can pass it either in hidden input or as you want
PHP way
$actual_link = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";
$shop = explode('/', $actual_link);
$shop_id = $shop[1/2/3 or 4];
//depending in which position the shop id is coming, you can check it by printing $shop
So you have a route similar to this
Route::post('/shops/{shop_id}/products/{product_id}/edit' , 'TestController#edit');
And in your controller you can simply use. Now you have both ids and can do what you want.
public function edit($shop_id, $product_id) {
//do what you want
}
Related
I am working on a laravel project, where I get data from an API then I want to display it on pages. I want the return to be spread out across 4 pages, each page with 10 results each. What I have so far, seems like it should work, but I am missing one piece, so any advice and help would be appreciated. So this is how it is suppose to work with code:
1) The users types in a book title in a search box.
<form method=POST action='/search'>
#csrf
<input type="text" name="search_term"/>
<input type="submit" value="Search"/>
</form>
2) there input is then sent to my controller, which queries the google books api.
class search extends Controller {
public function search(){
$current_page = LengthAwarePaginator::resolveCurrentPage();
echo $current_page;
$term = request('search_term');
$term = str_replace(' ', '_', $term);
$client = new \Google_Client();
$service = new \Google_Service_Books($client);
$params = array('maxResults'=>40);
$results = $service->volumes->listVolumes($term,$params);
$book_collection = collect($results);
$current_book_page = $book_collection->slice(($current_page-1)*10,10)->all();
$books_to_show = new LengthAwarePaginator($current_book_page,count($book_collection),10,$current_page);
return view('library.search')->with(compact('books_to_show'));
}
}
3) the results are then displayed on my blade
#extends('home')
#section('content')
#foreach($books_to_show as $entries)
<div class="row">
<div class="col-sm-auto">
<img class="w-50 img-thumbnail" src={{$entries['volumeInfo']['imageLinks']['smallThumbnail']}}/>
</div>
<div class="col-sm">
{{$entries['volumeInfo']['title']}}<br/>
#if($entries['volumeInfo']['authors']!=null)
by:
#foreach($entries['volumeInfo']['authors'] as $authors)
{{$authors}}
#endforeach
#endif
</div>
</div>
#endforeach
{{$books_to_show->links()}}
#endsection
This all works fine and as expected. I get 10 results on the view, and then I have a bar at the bottom which give shows me 4 different pages to choose from.
When I first type in a search term such as "William Shakespeare" My page url is:
localhost:8000/search
But, when I click on any of the pages my url becomes:
http://localhost:8000/?page=2
I understand that the ?page=* is how the pagination determines which page you are viewing, and that should be sent back to the controller. But, I am missing something on sending it back to the controller I think.
Still kind of fresh to this, so any advice is more then greatly appreciated.
LengthAwarePaginator accepts a 5th parameter in its constructor: an array of options.
the path option
$books_to_show = new LengthAwarePaginator($current_book_page, count($book_collection), 10, $current_page, [
// This will fix the path of the pagination links
'path' => LengthAwarePaginator::resolveCurrentPath()
]);
By the way, on a totally different matter, Laravel makes your life easier by slicing the collection for you, check it out:
$current_book_page = $book_collection->forPage($current_page, 10);
Hope it helps :)
in my show method in laravel i have a form that i want to submit and show the result on the same page so here is my show method first of all :
public function show(Property $property)
{
$property = Property::with('propertycalendars')->where('id', $property->id)->first();
foreach ($property->propertycalendars as $prop) {
$end_reserve = $prop->reserve_end;
}
// HERE NEW RELATION
$pdate = Property::with('dates')->get();
return view('users.properties.show', compact('property','pdate','end_reserve'));
}
and in the view of my show which for example is the url of a uniq property like below just as an example :
http://localhost:8000/properties/1
now i have a form to submit to search the Date table and bring me the dates so here is what i have wrote for the search function :
public function search (Request $request,$property_id){
//Send an empty variable to the view, unless the if logic below changes, then it'll send a proper variable to the view.
$results = null;
//Runs only if the search has something in it.
if (!empty($request->property_id)) {
$start_date = $request->start_date;
$search_date = Date::all()->where('date',$start_date);
}
return view('admin.properties.show')->with('search_date', $search_date);
}
and
thats my route :
Route::get('/properties/{{property_id}}','PropertyController#search');
and finally my form to submit the search :
<form action="/properties/search" method="get">
{{csrf_field()}}
<div class="row">
<div class="col-lg-5">
<input type="hidden" value="{{$property->id}}" name="property_id">
<input name="start_date" class="form-control m-input start_date" autocomplete="off"> </div>
<div class="col-lg-5">
<input name="finish_date" class="form-control m-input start_date" autocomplete="off"> </div>
<div class="col-lg-2">
<input type="submit" value="seach" class="btn btn-primary btn-block" autocomplete="off">
</div>
</div>
</form>
but now when i submit the form it returns a 404 not found with a link like below :
http://localhost:8000/properties/search?_token=R8ncSBjeZANMHlWMcbC6o5mYJZfwWgdfTwuviFo1&property_id=1&start_date=1398%2F1%2F12&title=
In your controller, change to the following:
public function search (Request $request){
//Send an empty variable to the view, unless the if logic below changes, then it'll send a proper variable to the view.
$results = null;
//Runs only if the search has something in it.
if (!empty($request->title)) {
$results = Property::all()->where('some search here')->get();
}
return view('admin.article.index')->with('results', $results);
}
This will send any (and all) results that your query finds to the view. Now in your view, you'll need to ensure there are actual results, or you'll get an error, so for example:
#if ($results)
//There are results, loop through them
#foeach($results as $item)
{{$item->title}}
#endforeach
#else
//There are no results, show the form maybe?
#endif
Without knowing your table structure, I can't give the exact way to loop through your results, but this should get you started.
Edit: Since OP's question nature changed a fair bit from the original question:
In order to achieve the new flow, you'd need to pass in a URL param in the route, and change it to be a get, since you're no longer posting it from a form:
Route::get('/properties/{search}','PropertyController#search');
This tells Laravel you've got something coming from a website.com/properties/xxxxx request - the xxxxx would contain the search key you'd then pass to your controller to lookup. The {search} portion in the route can be whatever name you want, just ensure the controller's second param matches it.
If you wanted to allow for a posting from your search form, you can (in addition) add the following to your routes:
Route::post('/properties','PropertyController#search');
Then in your controller, fetch whatever came from the form via the Request facade.
Then in your controller, you'd check if this is valid:
public function search (Request $request, $search){
//Send an empty variable to the view, unless the if logic below changes, then it'll send a proper variable to the view.
$results = null;
//Runs only if the second URL param has a value
if (!empty($search)) {
$results = Property::all()->where('some search here')->get();
}
return view('admin.article.index')->with('results', $results);
}
I have a form on my page
<form method="post" action="{{url('/vpage')}}">
<input type="hidden" name="_token" value="{{ csrf_token() }}">
<div class="w100">
<button name="hostel1" class="submitBTN addnowBtn" type="submit" value="The Venetian"> Add Now</button>
</div><!--w100-->
</form>
I getting the request printed in my controller like
public function vegaspage(Request $request){
dd($request);
die;
}
I have also have many fields on my page , when the request params comes to browser the submit button value is not coming in request
Any ideas ?
Inside your controller function try this:
Input::get('hostel1', 'NA');
// It will return its value ie `The Venetian` otherwise `NA`
Note: The second parameter of Input::get() is the default value.
This Follow link
only one input value get following
$name = $request->input('name');
Retrieving All Input Data
$input = $request->all();
Note: The easiest way to debug this, is via the Network tab in google chrome. You can see the header response data.
But the reason this is not working is probably because you are doing a POST Request . If you do a GET request you will get the value of the button.
An other reason could be that you are doing the submit trough javascript and doing an e.preventDefault() in that case you are not really sending the request. so PHP doesn't get the value.
Do
$request->hostel1
When you want to dd() your input params, do
dd($request->all());
I realized that anytime I try to set a name and value to a "submit" button, laravel doesn't retrieve the values in the request. So you might want to use a hidden field like this:
<input type="hidden" name="hostel1" value="hostel1">
and retrieve it on the server side like this:
$request->hostel1;
Change button code to:
<input name="hostel1" value="The Venetian" type="hidden">
<button class="submitBTN addnowBtn" type="submit"> Add Now</button>
In the controller, use this to get the value:
$request->hostel1
By using request namespace you can get value of any input parameters and also same for the submit button.
For this you have to include Request in controller like:
namespace App\Http\Controllers;
use Illuminate\Http\Request;
class UserController extends Controller
{
/**
* Store a new user.
*
* #param Request $request
* #return Response
*/
public function store(Request $request)
{
$name = $request->input('name');
//IN your problem you can submit button value as
$submit_button = $request->input('hostel1');
}
}
For more details about the request you can follow:
https://laravel.com/docs/5.3/requests
Thanks
I want to get the url data into my input value.
Example:
the url is http://example.com/user?username=example
and my html input code is as below
<input value="{{ request()->input('username') or old('username') }}">
but the result always return "1" and not "example"
It seems like the "or" blade helper acts as conditional operator.
How can I get the username value from url into that input and still get the default value as old('username')?
Try with
<input value="{{ request()->input('username', old('username')) }}">
It will retrieve username as an input if it exists or default to the old value. You can also give a default value to the old helper.
Simpler this way:
<input value="{{ (old('username')?old('username'):'') }}">
Very Simple way.
<input value="{{ request()->input('username') ?? old('username') }}">
As per official documentation 8.x
We use the helper request
The request function returns the current request instance or obtains
an input field's value from the current request:
$request = request();
$value = request('key', $default);
the value of request is an array you can simply retrieve your input using the input key as follow
$username = request()->username; //for http://example.com/user?username=example
I got value from database and then i need to set those value to textbox. I have created a controller file with the method name of edit look like below
userdata.blade.php:
public function edit($id)
{
echo "You have clicked edit link".$name;
$editdata = DB::table('newuser')->where('Id','=',$id)->get();
return View::make('editdata',array('list' => $editdata));
}
I have passed array of value as parameter to the view file.now i need to diaplay the value of name to textbox.how to do that in html page using laravel. My html page look like below
editdata.blade.php:
<html>
<head></head>
<body>
<div>
{{Form::open(array('url' => 'login', 'method' => 'post'))}}
{{Form::label('name','Name',array('id'=>'label-name'))}}
{{Form::text('name',{{$list->Name}}}}
{{ Form::close() }}
</div>
</body>
</html>
can anyone tell me that what mistake i did.Thanks in advance
Just remove the curly brackets, you are already "inside" PHP code and don't need them:
{{ Form::text('name',$list->Name) }}
Also you get a collection from your controller you probably want to do:
$editdata = DB::table('newuser')->where('Id','=',$id)->first();
Or even:
$editdata = DB::table('newuser')->find($id);
get() returns a collection (multiple rows) and not the model itself. You can use User::find($id) which gives you direct access to the model with the specified Id.
When not using eloquent just replace get() with first()