PHP timestamp hours to days - php

Question

I have a timestamp which I need to return as:
When it's under 1 hour I need it to say "30 minutes ago".
When it's under 24 hours I need it to say "6 hours ago".
When it gets to 24 hours I need it to say "1 day ago".
When it gets to 48 hours I need it to say "2 days ago".
Would this be done with a conditional statement?
So far I can return the number of days:
$post_timestamp = strtotime($post_timestamp);
$current_date = strtotime(time());
$datediff = $current_date - $post_timestamp;
$days = floor($datediff/(60*60*24));

Answer 1

I guess you can use DateTime, DateInterval and DatePeriod:
$date1 = new DateTime();
$date2 = DateTime::createFromFormat('U', $post_timestamp); # I assume a unix timestamp here
//determine what interval should be used - 1 minute
$interval = new \DateInterval('PT1M');
//create periods every minute between the two dates
$periods = new \DatePeriod($date2, $interval, $date1);
//count the number of objects within the periods
$mins = iterator_count($periods);
if ($mins < 60)
{
$say = "30 minutes ago";
} elseif ( $mins >= 60 and $mins < 60 * 24)
{
$say = "6 hours ago";
} elseif ( $mins >= 60 * 24 and $mins < 60 * 48)
{
$say = "1 day ago";
} elseif ( $mins >= 60 * 48)
{
$say = "2 days ago";
}
print $say;

Answer 2

You can use code like following :
date_default_timezone_set('Asia/Calcutta');
$post_timestamp="2017-05-21 5:00 pm";
$post_timestamp = strtotime($post_timestamp);
$current_date = strtotime(date('Y-m-d h:i a'));
$datediff = $current_date - $post_timestamp;
$mins = ($datediff) / 60;
$hours = $datediff / ( 60 * 60 );
You will get minutes and hours using this, put your condition accordingly