I got this code
$a = "I love Steve Jobs.";
$targets = array('bill gates','steve jobs');
foreach($targets as $t)
{
if (preg_match_all("/\b" . $t . "\b/i", $a)) {
$b[] = $t;
}
}
This code finds ALL matches in the array, which is great
Now I got a database with a table called "tags" - in here there is around 500 keywords. I wan't to make this work together with the script above.
All I have to do in my logic, is to make an array which replaces $targets.
This code I made right here, does not work:
$result = $con->query("SELECT tag FROM tags");
$targets = $result->fetch_all(MYSQLI_ASSOC);
foreach($targets as $t)
{
if (preg_match_all("/\b" . $t . "\b/i", $a)) {
$b[] = $t;
}
}
I get this notice:
Notice: Array to string conversion
I don't know what to do - 2 hours passed by and I can't figure it out.
Thank you :)
in your code, you have:
if (preg_match_all("/\b" . $t . "\b/i", $a)) {
but $t is row in array, that is array with key tag.
you should have:
if (preg_match_all("/\b" . $t['tag'] . "\b/i", $a)) {
Same in other line, should be:
$b[] = $t['tag'];
summary
fetch_all return array of arrays that hold row from database.
You can always check value with methods print_r or var_dump
mysqli_fetch_all/mysqli_result::fetch_all returns an array of arrays representing result rows. In your example it would return a structure like this:
array(
array('tag' => 'bill gates'),
array('tag' => 'steve jobs')
)
You should be using $t['tag'] instead of $t inside the loop.
By the way, the easiest way to quickly debug situations like these, you can output the query results (or any other variable) with print_r() or var_dump(), and see how they're structured.
You can try use this code:
mysqli_fetch_assoc($result)
Related
The code below is a simple version of what I am trying to do. The code will read in two files, see if there is a matching entry and, if there is, display the difference in the numbers for that item. But it isn't working. The first echo displays the word but the second echo is never reached. Would someone please explain what I am missing?
$mainArry = array('Albert,8');
$arry = array('Albert,12');
foreach ($arry as $line) {
$kword = explode(',', $line);
echo 'kword '.$kword[0];
if (in_array($kword[0], $mainArry)) {
echo 'line '.$line. ' has count of '.$kword[1] . '<br>';
}
}
Your $mainArry contains a single element: the string 'Albert,8'. It looks like you want to use it as an array (elements 'Albert' and '8') instead of a string.
You mention the code will read from two files, so you can 'explode' it to a real array, as you do with $arry. A simpler approach would be using str_getcsv() to parse the CSV string into $mainArry.
$inputString = 'Albert,8';
$mainArry = str_getcsv($inputString); // now $mainArry is ['Albert','8']
$arry = array('Albert,12');
foreach ($arry as $line) {
$kword = explode(',', $line);
echo 'kword '.$kword[0];
if (in_array($kword[0], $mainArry)) {
echo 'line '.$line. ' has count of '.$kword[1] . '<br>';
}
}
Test it here.
You are attempting to compare the string Albert with Albert,8, so they won't match. If you want to check if the string contains the keyword, assuming your array has more than one element, you could use:
$mainArry = array('Albert,8');
$arry = array('Albert,12');
foreach ($arry as $line) {
$kword = explode(',', $line);
echo 'kword '.$kword[0];
foreach ($mainArry as $comp) {
if (strstr($comp, $kword[0])) {
echo 'line '.$line. ' has count of '.$kword[1] . '<br>';
}
}
}
example: https://eval.in/728566
I don't recommend your way of working, but this is a solution, basically the process you apply to the $arry should also apply to the $mainArry you're trying to compare it to.
$mainArry = array('Albert,8');
$arry = array('Albert,12');
/***
NEW function below takes the valus out of the main array.
and sets them in their own array so they can be properly compared.
***/
foreach ($mainArry as $arrr){
$ma = explode(",",$arrr);
$names[] = $ma[0];
$values[] = $ma[1];
}
unset($arrr,$ma);
foreach ($arry as $line) {
$kword = explode(',', $line);
echo 'kword '.$kword[0];
/// note var reference here is updated.
if (in_array($kword[0], $names)) {
echo '<br>line '.$kword[0]. ' has count of '.$kword[1] . '<br>';
}
}
Yeah, MarcM's answer above does the same thing in a neat single line, but I wanted to illustrate a little more under the hood operations of the value setting. :-/
In Drupal context, while printing checked exposed filters in a somehow standard code snippet, I can't print more than one value, and I can't find the missing logic of my foreach loop :
<?php
foreach ($exposed_filters as $filter => $value) {
if ($filter == 'foo') {
$field = field_info_field('field_foo');
$allowed_values = list_allowed_values($field);
//returns an array with 14 string values & numeric keys
//e.g array(0=>'bla', 1=>'bar', 2=>'xx', 3=>'yy')
$h = explode(',', $value);//returns checked ids of foo filter e.g array(0 => 2, 1=>3)
$exp_heb = '';
foreach ($h as $k=>$v) {
$exp_heb .= $allowed_values[$v] . ', ';
}
$exp_heb = substr($exp_heb, 0, -2);
print $exp_heb;
}
}
?>
Should return : xx, yy but I get xx,,
I checked step by step printing out my arrays, values... everything's looks fine but result is wrong. Do I need a rest ???
This is dpm($allowed_values) output
May be this line cuts your output?
$exp_heb = substr($exp_heb, 0, -2);
I got it working. I have to get the integer value of my variable, before passing it as a key :
foreach ($h as $k=>$v) {
$exp_heb .= $allowed_values[intval($v)] . ', ';
}
For a reason I would be glad to be taught, even if it's always an id, and prints out a number, first time it's passed as integer, but then not.
I am trying to learn php, and I am playing around with while loops. I was wondering how to print out a specific number in an array in php. Fx:
$a = [1,3,5,7,9,11,13];
$s = 3;
while($a == 3) {
echo $s.' is in the row';
$a++;
}
In this example I would like to run through the $a and see if 3 exist there. If it does it has to echo '3 is in the row' I tried to make a while loop, but it is not correct. Can anyone see what I am doing wrong? Just to say it, I think it is very wrong, but I don't know how to solve it, if I have to use the while loop?
Best Regards
Mads
Your while condition reads: "While the value of $a equals 3", but $a is an array, so its value can't ever be 3. The loop will never be executed. In PHP, we would write:
if (in_array($s, $a))
echo $s, ' was found in the array';
Or, if you insist on writing loops:
foreach ($a as $key => $value)
{
if ($value == $s)
{
echo $s, ' was found at offset ', $key;
break;//end terminate loop
}
}
Of course, you could also write:
for ($i=0, $j=count($a);$i<$j;++$j)
{
if ($a[$i] == $s)
{//you could move this condition to the loop itself, even
echo $s, ' found in array at offset ', $i;
break;
}
}
You can, if you want use a while loop, too, but that wouldn't be the best choice for your particular case. Just read through the manual on php.net. There are many, many array_* functions available, and there are many ways to iterate over your data.
Another worry is your using the array name as a sort-of C-style pointer: $a++; in C, an pointer can be incremented to set it to point to the next value in an array (if the new memory address is valid, and the pointer is valid, and all of the other things you have to worry about in C). PHP does not work this way. An array isn't really an array: it's a hash map. incrementing an array, therefore, is pointless and most likely to be a bug. The for loop is the closest you can get to traversing an array using the ++ operator.
You're looking for in_array. This checks if a value exists in an array, in the form of:
in_array ( mixed $needle , array $haystack )
So, in your case, you'd want to do:
$a = [1,3,5,7,9,11,13];
$s = 3;
if (in_array($s, $a)) {
echo $s.' is in the row';
}
foreach($a as $b) {
if($b == 3)
echo $b.' is in the row';
}
Modify slightly your code changing while condition:
$a = array(1,3,5,7,9,11,13);
$s = 3;
$counter = 0;
while($counter < count($a)) {
if ( $a[$counter] == $s )
echo $s.' is in the row';
$counter++;
}
Added counter to iterate through while loop until end of array.
count() method returns number of items in array.
This solution prints all occurences of your number.
To have better code, change names of variables:
$numbers = array(1,3,5,7,9,11,13);
$target = 3;
$counter = 0;
while($counter < count($numbers)) {
if ( $numbers[$counter] == $target )
echo $target.' is in the row';
$counter++;
}
There are two ways to do it,
First, you can loop through all items in the array using a foreach() loop.
That way, you can go through them all and if you have multiple conditions, it makes your code a bit more readable.
And example of that loop is like this:
foreach($array as $array_item) {
if($array_item === 3) {
echo "3 is in the array";
}
}
The alternative is to use a built in function to find if something is in the array. THis is probably much faster, though I haven't benchmarked the difference.
if(in_array(3, $array)) {
echo "3 is in the array";
}
you can use
array_search ,in_array , and forearch or for loops to itertate through the array.
For learning purposes
$a = [1,3,5,7,9,11,13];
$s = 3;
for($i=0;$i<count($a);$i++)
{
if($a[$i]==$s){
echo $s.' is in the row';
}
}
of course in real life
if (in_array(3, $a)) {
// Do something
}
would be better;
<?php
$a = [1,3,5,7,9,11,13];
$s = 3;
for($a=0;$a < 20; $a++)
{
while($a == 3) {
echo $s.' is in the row';
//$a++;
}
}
?>
I would like to reverse the order of this code's list items. Basically it's a set of years going from oldest to recent and I am trying to reverse that output.
<?php
$j=1;
foreach ( $skills_nav as $skill ) {
$a = '<li><a href="#" data-filter=".'.$skill->slug.'">';
$a .= $skill->name;
$a .= '</a></li>';
echo $a;
echo "\n";
$j++;
}
?>
Walking Backwards
If you're looking for a purely PHP solution, you can also simply count backwards through the list, access it front-to-back:
$accounts = Array(
'#jonathansampson',
'#f12devtools',
'#ieanswers'
);
$index = count($accounts);
while($index) {
echo sprintf("<li>%s</li>", $accounts[--$index]);
}
The above sets $index to the total number of elements, and then begins accessing them back-to-front, reducing the index value for the next iteration.
Reversing the Array
You could also leverage the array_reverse function to invert the values of your array, allowing you to access them in reverse order:
$accounts = Array(
'#jonathansampson',
'#f12devtools',
'#ieanswers'
);
foreach ( array_reverse($accounts) as $account ) {
echo sprintf("<li>%s</li>", $account);
}
Or you could use the array_reverse function.
array_reverse() does not alter the source array, but returns a new array. (See array_reverse().) So you either need to store the new array first or just use function within the declaration of your for loop.
<?php
$input = array('a', 'b', 'c');
foreach (array_reverse($input) as $value) {
echo $value."\n";
}
?>
The output will be:
c
b
a
So, to address to OP, the code becomes:
<?php
$j=1;
foreach ( array_reverse($skills_nav) as $skill ) {
$a = '<li><a href="#" data-filter=".'.$skill->slug.'">';
$a .= $skill->name;
$a .= '</a></li>';
echo $a;
echo "\n";
$j++;
}
Lastly, I'm going to guess that the $j was either a counter used in an initial attempt to get a reverse walk of $skills_nav, or a way to count the $skills_nav array. If the former, it should be removed now that you have the correct solution. If the latter, it can be replaced, outside of the loop, with a $j = count($skills_nav).
If you don't mind destroying the array (or a temp copy of it) you can do:
$stack = array("orange", "banana", "apple", "raspberry");
while ($fruit = array_pop($stack)){
echo $fruit . "\n<br>";
}
produces:
raspberry
apple
banana
orange
I think this solution reads cleaner than fiddling with an index and you are less likely to introduce index handling mistakes, but the problem with it is that your code will likely take slightly longer to run if you have to create a temporary copy of the array first.
Fiddling with an index is likely to run faster, and it may also come in handy if you actually need to reference the index, as in:
$stack = array("orange", "banana", "apple", "raspberry");
$index = count($stack) - 1;
while($index > -1){
echo $stack[$index] ." is in position ". $index . "\n<br>";
$index--;
}
But as you can see, you have to be very careful with the index...
You can use usort function to create own sorting rules
Assuming you just need to reverse an indexed array (not associative or multidimensional) a simple for loop would suffice:
$fruits = ['bananas', 'apples', 'pears'];
for($i = count($fruits)-1; $i >= 0; $i--) {
echo $fruits[$i] . '<br>';
}
If your array is populated through an SQL Query consider reversing the result in MySQL, ie :
SELECT * FROM model_input order by creation_date desc
If you do not have Boolean false values in your array, you could use next code based on internal pointer functions:
$array = ['banana', 'apple', 'pineapple', 'lemon'];
$value = end($array);
while ($value !== false) {
// In case you need a key
$key = key($array);
// Do something you need to
echo $key . ' => ' . $value . "\n";
// Move pointer
$value = prev($array);
}
This solution works for associative arrays with arbitrary keys and do not require altering existing or creating a new one.
<?php
$j=1;
array_reverse($skills_nav);
foreach ( $skills_nav as $skill ) {
$a = '<li><a href="#" data-filter=".'.$skill->slug.'">';
$a .= $skill->name;
$a .= '</a></li>';
echo $a;
echo "\n";
$j++;
}
?>
Edit: The aim of my method is to delete a value from a string in a database.
I cant seem to find the answer for this one anywhere. Can you concatenate inside a str_replace like this:
str_replace($pid . ",","",$boom);
$pid is a page id, eg 40
$boom is an exploded array
If i have a string: 40,56,12 i want to make it 56,12 however without the concatenator in it will produce:
,56,12
When I have the concat in the str_replace it doesnt do a thing. Is this possible?
Answering your question: yes you can. That code works as you would expect it to.
But this approach is wrong. It will not work for $pid = 12; (last element, without trailing coma) and will incorrectly replace 40, in $boom = '140,20,12';
You should keep it in array, search for unwanted value, if found unset it from the array and then implode with coma.
$boom = array_filter($boom);
$key = array_search($pid, $boom);
if($key !== false){
unset($boom[$key]);
}
$boom = implode(',',$boom);
[+] Your code does not work because $boom is an array, and str_replace operates on string.
As $boom is an array, you don't need to use array on your case.
Change this
$boom = explode(",",$ticket_array);
$boom = str_replace($pid . ",","",$boom);
$together = implode(",",$boom);
to
$together = str_replace($pid . ",","",$ticket_array);
Update: If you want still want to use array
$boom = explode(",",$ticket_array);
unset($boom[array_search($pid, $boom)]);
$together = implode(",",$boom);
After you have edited it becomes clear that you want to remove the value of $pid from the array $boom which contains one number as a value. You can use array_search to find if it is in at if in with which key. You can then unset the element from $boom:
$pid = '40';
$boom = explode(',', '40,56,12');
$r = array_search($pid, $boom, FALSE);
if ($r !== FALSE) {
unset($boom[$r]);
}
Old question:
Can you concatenate inside a str_replace like this: ... ?
Yes you can, see the example:
$pid = '40';
$boom = array('40,56,12');
print_r(str_replace($pid . ",", "", $boom));
Result:
Array
(
[0] => 56,12
)
Which is pretty much like you did so you might be looking for the problem at the wrong place. You can use any string expression for the parameter.
It might be easier for you if you're unsure to create a variable first:
$pid = '40';
$boom = array('40,56,12');
$search = sprintf("%d,", $pid);
print_r(str_replace($search, "", $boom));
You should store your "ticket array" in a separate table.
And use regular SQL queries (UPDATE, DELETE) to manipulate it.
A relational word in the name of your database is for the reason. And you are abusing this smart software with such a barbaric approach.
You could use str_split, it converts a string to an array, then with a foreach loop echo all the values except the first one.
$numbers_string="40,56,12";
$numbers_array = str_split($numbers_string);
//then, when you have the array of numbers, you could echo every number except the first separating them with a comma
foreach ($numbers_array as $key => $value) {
if ($key > 0) {
echo $value . ", ";
}
}
If you want is to skip a value not by it's position in the array, but for it's value then you could do this instead:
$unwanted_value="40";
foreach ($numbers_array as $key => $value) {
if ($value != $unwanted_value) {
echo $value . ", ";
}
else {
unset($numbers_array[$key]);
$numbers_array = array_values($numbers_array);
var_dump($numbers_array);
}
}