<?php
$id = $_GET['id'];
$getAlbumCusId = getAlbumCusId($id); //first function to get siteIds from first table from first database
foreach ($getAlbumCusId as $AlCusId) {
$proId = $AlCusId['siteid']; // got siteIds, return 2 items
$viewinv = viewinv($proId); // second function to get prices from first table from second database
foreach ($viewinv as $vinv) {
echo $vinv['price']; // but return 11 items
}
}
?>
first function return siteid from first table from first db and return two items, it's right, but now i want to get price from second function in first table in second db but it return 11 items! but i want to get price value for that two items from the first function, i know i did something wrong but i'm new in php no idea how to fix this.
GOAL: i got two items (from first function) i just want to get price for these two items.
UPDATE: problem solved;
Maybe, in second table, you have many prices of the same item (in different times), so you should order prices by date DESC and limit the result to 1 to get the last price.
make sure your query is perfect which you are using to fetch the data in second function
select price from second_table where proid = '$proid'
Make sure that you are contacting the database name to the table like (db1.tablename, db2.tablename) otherwise if the same table exists in first database ie db1 it fetch the results from db1.tablename instead of db2.tablename
Related
In Controller,
public function detail($id)
{
$item = Item::find($id);
return view('frontend.detail',compact('item'));
}
In blade,
{{$item->subcategory->items}} //question //this code print all the items//
You need to select the items manually if you don't want to fetch the id
Currently, you are fetching all the items by using $item = Item::find($id); it means that fetch all the fields of the particular table againt the given id.
you can use below query by modifying you required fields
Item::select('name','surname')->where('id', 1)->get();
You Need to make hidden id of the column in query Example
Item::find($id)->makeHidden(['id']);
return view('frontend.detail',compact('item'));
I need to make pagination in Laravel, and as I read laravel documentation here is a several way to do it. but in my cases it is a little bit complexity. So let say I've two table in my DB, table1 and table2(many to many relationship), I want to paginate table1 with specific ids. So I mean if table1 contains ids 1,2,3,4,5 ... n, I want to paginate only rows which id is 2 and 3
I have tried :
private function check_wear($type){
$products_id = array(); //here is ids which $type is set as 'ON'
$wears = DB::select("SELECT prod_id FROM wears WHERE ".$type." = 'on' "); //Select specific products ids. (in our case it is **table1**)
foreach ($wears as $wr){
array_push($products_id,$wr->prod_id);
}
return $products_id; //return array with ids which should be paginate
}
public function hat($locale){
$hat_prod_ids = $this->check_wear('coat');
$p=12;
$products = DB::table('products')->paginate($p); // 12 per page
dd($products);
my code only paginate one table with all data, is there any built-in function to somehow write a logic condition? for pagination
If you need to filter your pagination with elements which you've in $hat_prod_ids, you're able to use WhereIn() method, that one checks if your elements (in our case ids) exist in your $hat_prod_ids and returns true or false
$products = DB::table('products')
->whereIn('id',$hat_prod_ids)
->paginate($p);
add that code and now you will be able to paginate only that ids which is matched in your array
I want to get 2 result from a filter query in Laravel version 6. I want to get product table information that user can change item exist in page by a select box with name of pageitemcount and can search by a field with name of select. when user select pageitemcount and also search for an name, submit a form and below query is run . When user search anything, available filter of category must be limited to available categories. I want to show distinct product category in additional to product list.
public function productIndex(Request $request)
{
$take = 10;
$query = Product::query();
if ($request->has('pageitem')){
$take = $request->input("pageitem");
}
// Search
if ($request->has('search')){
$query = $query->where('name', $request->input("search"));
}
$availableCategoriesQuery= $query;
// Get product unique product category to show them to user
// that exist in prodcut list that show to user
$availableCategories = $availableCategoriesQuery->select("category_id")->distinct()->get();
// Get product list by pagination
$productList = $query->paginate($take);
return view('admin.manage_product', ['productList' => $productList, 'availableCategories' => $availableCategories]);
}
but when $availableCategories is executed, affected $query variable, and i cant get right result from next line, i get result of $availableCategories in $productList variable. i do'nt want to repeat my code again, how can i deal with?
the result of $availableCategories is completely true, but result of productList is $availableCategories that is paginated.
OK, I think I see the problem. You are trying to reuse the $query variable. You probably want something like this:
I assume that product_categories is the table for your product categories. You can also use the model if you want.
Also, Since the DB has no intrinsic order, you should specify an OrderBy() as well.
$take = $request->input("pageitem", 10);
$productList = Product::paginate($take)->get();
$availableCategories = DB::table('product_categories')->distinct()->get("category_id");
I'm trying to retrieve single column from my table grades.
For that I have used following code in my controller:
public function verify($id,$sid)
{
$grade=Grade::all('annual')->whereLoose('id',$id);
return $grade;
}
Where, annual is column name. But it is returning empty set of array [].
all() takes a list of columns to load from the database. In your case, you're fetching only one column called annual, therefore filtering on id later on does not return results. Replace your code with the following and it should work:
$grade = Grade::all('id', 'annual')->whereLoose('id', $id);
Keep in mind that it will return a collection of objects, not a single object.
NOTE: you're always loading all Grade objects from the database which is not efficient and not necessary. You can simply fetch object with given id with the following code:
$grade = Grade::find($id); // fetch all columns
$grade = Grade::find($id, ['id', 'annual']); // fetch only selected columns
The code you are using is loading all rows from the grades table and filtering them in code. It is better to let your query do the filter work.
For the columns part, you can add the columns you need to the first() function of the query, like so:
public function verify($id,$sid)
{
$grade = Grade::where('id', $id)->first(['annual']);
return $grade->annual;
}
I'm having issues getting a proper count total with my Laravel model.
Model Structure
User
Item
ItemLike
A user can have multiple Items, and each of these Items can have multiple ItemLikes (when a user 'likes' the item).
I can easily get the individual ItemLike counts when using an Item model:
return $this->itemLikes()->count();
But I can't figure out how to get the total # of ItemLike's a User has across all the Item's he owns.
EXAMPLE
User A has 3 Items. Each Item has 5 ItemLike's, for a grand total of 15.
I tried using eager loading on the User model like this:
return $this->items()->with('itemlikes')->get()->count();
But that returns 3 (the # of Items)
These are the queries it ran, which appears like the second query is the one I want, yet every way I try it I still get 3 instead of 15
select * from `items` where `items`.`user_id` = '1000'
select * from `item_likes` where `item_likes`.`item_id` in ('1000', '1001', '1002')
After suggestions from others I found 2 solutions to get the result.
Using whereIn:
$itemViewCount = ItemView::
whereIn('item_views.item_id', $this->items()->lists('id'))
->count();
return $itemViewCount;
2 queries for a total of 410μs
Using join:
$itemViewCount = $this->items()
->join('item_views', 'item_views.item_id', '=', 'items.id')
->count();
return $itemViewCount;
2 queries for a total of 600μs
Isn't it just a case of creating a method that would return the number of items for the model. e.g.:
#UserModel
public function nbLikes()
{
$nbLikes = 0;
foreach($this->items() as $item) {
$nbLikes += $item->itemLikes()->count();
}
return $nbLikes;
}
And then User::nbLikes() should return the piece of data you are looking for?
try this:
$query="select count(il.id) from item_likes il,item itm where il.item_id=itm.id and tm.user_id=1000";