I want to keep the H:i:s format so 10:52:20 however when I try:
$timeleft = strtotime($time1)-strtotime($time2);
I get something like 4521
I would like the result to retain the format. Is there a way to do this?
Yeah, what you get is unix timestamp which is in seconds. You can use date function to get required format like this:
$timestr_formated = date("H:i:s", $timeleft);
print($timestr_formated);
You can use DateTime::diff.
$time1 = new DateTime('2017-05-01 12:00:00');
$time2 = new DateTime('2017-05-01 11:25:30');
$timeleft = $time1->diff($time2);
echo $timeleft->format('%H:%i:%s'); // output: 00:34:30
In case you want to allow more than 24 hours.
$time1 = new DateTime('2017-05-02 12:00:00');
$time2 = new DateTime('2017-04-02 11:25:30');
$timeleft = $time1->diff($time2);
echo str_pad($timeleft->format('%a') * 24 + $timeleft->format('%h'), 2, "0") .
$timeleft->format(':%i:%s'); // output: 720:34:30
You can use date function by below format:
$timeleft = date('H:i:s', strtotime($time1)-strtotime($time2));
Related
I have two fields which store data like 2018-03-26 11:20:35 and 02:25:10(2 hours 25 minutes and 10 seconds) first data is date and time. second one is only time. I want to sum it and finally my result should 2018-03-26 13:45:45
How to do that in php code?
I have tried this way:
<?php
$date = '2018-03-26 11:20:35';
//echo $date;
//echo "<br>";
$hours = '02:25:10'; /* this data dynamic */
$sumTime = strtotime($date) + strtotime($hours);
$new_time = date("Y-m-d H:i:s", $sumTime);
echo $new_time;
Output:
Warning: date() expects parameter 2 to be integer, float given in C:\my-project-path\test.php on line 7
Here's a simple solution, some checks are skipped:
// convert your date to DateTime object
$date = '2018-03-26 11:20:35';
$dt = new DateTime($date);
// convert your period to DateInterval
$hours = '02:25:10'; /* this data dynamic */
$parts = explode(':', $hours);
$interval = new DateInterval('PT' . (int)$parts[0] . 'H' . $parts[1] . 'M' . $parts[2] . 'S');
// Add interval to date
$dt->add($interval);
// Format date as you need
echo $dt->format('Y-m-d H:i:s');
You could create a duration in seconds by comparing today at "00:00:00" and today at $hours. Actually, strtotime($hours) returns the timestamp of today at $hours, so, the addition of the two timestamp don't give the expected result.
If $hours is lesser than 24 hours, you could use:
$date = '2018-03-26 11:20:35';
$hours = '02:25:10';
$d0 = strtotime(date('Y-m-d 00:00:00'));
$d1 = strtotime(date('Y-m-d ').$hours);
$sumTime = strtotime($date) + ($d1 - $d0);
$new_time = date("Y-m-d H:i:s", $sumTime);
echo $new_time;
Outputs:
2018-03-26 13:45:45
You should check DateTime::add:
http://php.net/manual/en/datetime.add.php
http://php.net/manual/en/datetime.examples-arithmetic.php
Example:
<?php
// Convert h:m:s format to PThHmMsS format
sscanf('02:25:10', '%d:%d:%d', $hour, $minute, $second);
$intervalSpec = sprintf('PT%dH%dM%dS', $hour, $minute, $second);
$datetime = new DateTimeImmutable('2018-03-26 11:20:35');
$newDatetime = $datetime->add (new DateInterval($intervalSpec));
echo $newDatetime->format(DateTime::W3C);
It could be done with some simple string manipulation:
$dt = new DateTime("$date UTC");
$modify = preg_replace('/:/', ' hours ', $hours, 1);
$modify = preg_replace('/:/', ' minutes ', $modify, 1);
$modify .= ' seconds';
$dt->modify($modify);
demo
If you have MySQL as your data storage, you could do:
DATE_ADD(field1, INTERVAL field2 HOUR_SECOND)
demo
you can do something like:
$hour = $hours->format('H'); //This way you get a string which contains the hours
$date->modify('+'.$hour.' hour'); //you modify your date adding the hours
I'm assuming you only need the hours, and not minutes and seconds
EDIT:
you can do like that using regexp
$date = new \DateTime('2018-03-26 11:20:35');
$hours ='02:25:10';
preg_match("/^([0-9].*):([0-9].*):([0-9].*)/",$hours,$matches);
$date->modify('+'.$matches[1].' hour');
$date->modify('+'.$matches[2].' minute');
echo $date->modify('+'.$matches[3].' second')->format('Y-m-d H:i:s');
I am trying to add hh:mm:ss with the date. How can i do it?
I tried with the following but it works when the hour is string, but when adding time is similar to MySQL Date time it is not working.
$new_time = date("Y-m-d H:i:s", strtotime('+5 hours'));
I am trying to get solution for the following:
$timeA= '2015-10-09 13:40:14';
$timeB = '03:05:01'; // '0000-00-00 03:05:01'
OutPut:
$timeA + $timeB = 2015-10-09 16:45:15 ?
How Can I Add this?
Use DateInterval():
$timeA = new DateTime('2015-10-09 13:40:14');
$timeB = new DateInterval('PT3H5M1S'); // '03:05:01';
$timeA->add($timeB);
echo $timeA->format('Y-m-d H:i:s');
You would need to break your time down into the right DateInterval format but that is easily done with explode();
Here's how that might look:
$parts = array_map(function($num) {
return (int) $num;
}, explode(':', '03:05:01'));
$timeA = new DateTime('2015-10-09 13:40:14');
$timeB = new DateInterval(sprintf('PT%uH%uM%uS', $parts[0], $parts[1], $parts[2]));
$timeA->add($timeB);
echo $timeA->format('Y-m-d H:i:s');
Demo
print date('Y-m-d H:i:s',strtotime($timeA." +03 hour +05 minutes +01 seconds"));
Should work also.
So:
$timeA= '2015-10-09 13:40:14';
$timeB = vsprintf(" +%d hours +%d minutes +%d seconds", explode(':', '03:05:01'));
print date('Y-m-d H:i:s',strtotime($timeA.$timeB));
Can be the solution.
You may also convert the time into seconds with this approach from: Convert time in HH:MM:SS format to seconds only?
$time = '03:05:01';
$seconds = strtotime("1970-01-01 $time UTC");
Then you could add the seconds to
$currentTime = '2015-10-10 13:40:14';
$newTime = date("Y-m-d H:i:s", strtotime( $currentTime.'+'.$seconds.' seconds'));
If you prefer to use the DateTime objects offered by #John Conde, here are two ways to convert the time string into the format:
$formattedTime = preg_replace("/(\d{2}):(\d{2}):(\d{2})/","PT$1H$2M$3S","03:05:11");
or, as you read it from the database:
select concat(hour(last_modified),'H',minute(last_modified),'M',second(last_modified),'H') from people;
So a more general code approach would be:
$initial = 'some time';
$interval = 'the interval value';
$initialTime = new DateTime($initial);
$intervalTime = new DateInterval($interval);
$initialTime->add($intervalTime);
echo $initialTime->format('Y-m-d H:i:s');
It's maybe a really simple question but I found a little hard since I am still novice on PHP.
Presumably I have:
$time1 = strtotime("today 15:00:00-05:00");
This is just example, $time1 is dynamic at runtime and can be any value, I would like to create new $time2 which has the value:
$time2 = strtotime("this thursday 15:00:00-05:00");
Please note in here $time1 and $time2 have the same 15:00:00-05:00 and only different the day. So, to sump up, I have two inputs:
$time1 which is dynamic at runtime.
the string this thursday.
How to create the $time2 with the value like above.
Find the difference between "today" and "today 15:00:00-05:00" and add it to "this thursday"
$sometime = "today 15:00:00-05:00";
$time1 = strtotime($sometime);
// now find only the hour part
$time = mktime(0,0,0, date('n', $time1), date('j', $time1), date('Y', $time1));
$time_difference = $time1 - $time;
$time2 = strtotime("this thursday") + $time_difference;
Or even simpler:
$sometime = "today 15:00:00-05:00";
$time1 = strtotime($sometime);
// now find only the hour part
$hour_string = date('h:i:s', $time1);
$time2 = strtotime("this thursday $hour_string");
Wonder why you don't use DateTime object of PHP right from the start, but ok:
$dateTime = new DateTime($time1);
$dateTime->modify('+1 day');
$time2 = $dateTime->getTimestamp();
Where you can change the 1 to any amount of days.
As I understand what you want is to concat the two string "this thursday" and "15:00:00-05:00":
$str1 = "this thursday";
$str2 = "15:00:00-05:00";
$time = strtotime($str1." ".$str2);
You may try this. And you need to specify more if it is not fulfilling the requirement.
$time1 = date("Y-m-d H:i:s");
$time2 = 'this thrusday ';
$time2 .= $time1;
$time2 = strtotime($time2);
I have a database column with datatype "time" which stores 11:30:45. I have fetched this time in a variable say
$databasetime = 11:30:45
I want to declare a variable say $currenttime which will contain time just now. Like its 11:33:30 right now and another variable which will contain their difference in seconds like
$timediff = $currenttime - $databasetime;
echo $timediff;
I am trying $currenttime = time(); but I am not getting the result which I desire. I want $timediff = 165 but when I echo time(), I am getting a very big value.
$databasetime = strtotime('11:30:45');
$curtime = time();
echo $curtime - $databasetime;
You can do it in the following way:
$databasetime = '11:30:45';
$time1 = strtotime($databasetime);
$time2 = strtotime('now');
$diff = $time2 - $time1;
echo 'your difference: '.date('H:i:s', $diff);
$datetime1 = new DateTime('10:35:56 2013-11-17');
$datetime2 = new DateTime('10:35:50 2013-11-17');
$interval = $datetime1->diff($datetime2);
echo $interval->m . " Month " .$interval->d ." Days ". $interval->h . " Hours, " . $interval->i." Mintues, ".$interval->s." seconds <br/>";
<?php
$currentTime = time();
$futureDateTime = new DateTime('11:30:45'); // might want to specify a date and timezone, system TZ by default
$futureTime = $futureDateTime->format('U'); // get unix timestamp
$timeDiff = $futureTime-$currentTime;
?>
You use the DateTime 'OO' methods to return 'unix timestamp' integers directly
<?php
$now = new DateTime('now');
$date = new DateTime('11:30:45');
echo $now->getTimestamp() - $date->getTimestamp();
?>
Here is a simple example.
$databasetime = '11:30:45';
$timedif = abs(strtotime('now') - strtotime($databasetime));
echo $timedif; //echos the difference in seconds.
abs is used just to prevent neg numbers, which you may or may not want to do.
My problem is solved now. Actually all answers are right but the problem was due to the default time zone. I wanted Asia/Kolkata time zone but default European timezone apache was picking. That's why I was not getting my desired results.
So, I am finally using below code:
date_default_timezone_set('Asia/Kolkata');
$databasetime = strtotime('11:30:45');
$curtime = time();
echo $curtime - $databasetime;
I have $adate; which contains:
Tue Jan 4 07:59:59 2011
I want to add to this date the following:
$duration=674165; // in seconds
Once the seconds are added I need the result back into date format.
I don't know what I'm doing, but I am getting odd results.
Note: both variables are dynamic. Now they are equal to the values given, but next query they will have different values.
If you are using php 5.3+ you can use a new way to do it.
<?php
$date = new DateTime();
echo $date->getTimestamp(). "<br>";
$date->add(new DateInterval('PT674165S')); // adds 674165 secs
echo $date->getTimestamp();
?>
Just use some nice PHP date/time functions:
$adate="Tue Jan 4 07:59:59 2011";
$duration=674165;
$dateinsec=strtotime($adate);
$newdate=$dateinsec+$duration;
echo date('D M H:i:s Y',$newdate);
Given the fact that $adate is a timestamp (if that's the case), you could do something like this:
$duration = 674165;
$result_date = strtotime(sprintf('+%d seconds', $duration), $adate);
echo date('Y-m-d H:i:s', $result_date);
// add 20 sec to now
$duration = 20;
echo date("Y-m-d H:i:s", strtotime("+$duration sec"));
Do this:
$seconds = 1;
$date_now = "2016-06-02 00:00:00";
echo date("Y-m-d H:i:s", (strtotime(date($date_now)) + $seconds));
$current_time_zone = 150;
date("Y-m-d H:i:s",strtotime(date("Y-m-d H:i:s"))+$current_time_zone);
I made this example for a timezone, but if you change some parts it may help you out:
$seconds_to_add = 30;
$time = new DateTime();
$time->setTimezone(new DateTimeZone('Europe/London'));
$time2 = $time->format("Y/m/d G:i:s");
$time->add(new DateInterval('PT' . $seconds_to_add . 'S'));
$timestamp = $time->format("Y/m/d G:i:s");
echo $timestamp;
echo '========';
echo $time2;
Result:
2018/06/17 3:16:23========2018/06/17 3:15:53
It would be easier with DateTime::modify
(new DateTime($str))->modify("+$duration seconds"); //$str is the date in string
I have trouble with strtotime() to resolve my problem of add dynamic data/time value in the current time
This was my solution:
$expires = 3600; //my dynamic time variable (static representation here)
$date = date_create(date('Y-m-d H:i:s')); //create a date/time variable (with the specified format - create your format, see (1))
echo date_format($date, 'Y-m-d H:i:s')."<br/>"; //shows the date/time variable without add seconds/time
date_add($date, date_interval_create_from_date_string($expires.' seconds')); //add dynamic quantity of seconds to data/time variable
echo date_format($date, 'Y-m-d H:i:s'); //shows the new data/time value
font: https://secure.php.net/manual/en/datetime.add.php (consult Object Oriented style too, the Elzo Valugi solution)
(1) https://secure.php.net/manual/en/function.date.php