getting value of array from certain index in php - php

I want to get the value of an array type given a certain index. The array's values are
$status = [1,2];
And I used these code to get the value:
$task_state = $status[1];
But it actually thought $status is a string and returns
'['
I know that this is actually quite simple, but I just can't seem to find the answer to my problem. Thank you

If $status defined as a string, you can return php value of it with eval function like below:
$status = '[1,2]';
$status_array = eval('return ' . $status . ';');
$task_state = $status_array[0];
Caution
The eval() language construct is very dangerous because it allows execution of arbitrary PHP code. Its use thus is discouraged. If you have carefully verified that there is no other option than to use this construct, pay special attention not to pass any user provided data into it without properly validating it beforehand.

i try to copy your script and here what i get
$status = [1,2];
$task_state = $status[1];
var_dump($status);
exit;
the result is :
array(2) { [0]=> int(1) 1=> int(2) }
can you give me line of your code for displaying '['.
may be your php version is the problem. See refrence.

Maybe you are saying that the values of your array:
$status = array(1,2);
So to get a value from the array:
echo $tatus[0] . "and " . $tatus[1];
output:
1 and 2

Related

Variable without name: ${''}

So variable variables are existing. Meaning that this is working
$a = 'test';
$$a = 'Hello';
echo ${'test'}; //outputs 'Hello'
But now I've come across some rather strange code using a variable without a name:
function test(&$numRows) {
$numRows = 5;
echo ' -- done test';
}
$value = 0;
test($value);
echo ' -- result is '.$value;
test(${''}); //variable without name
http://ideone.com/gTvayV Code fiddle
Output of this is:
-- done test -- result is 5 -- done test
That means, the code is not crashing.
Now my question is: what exactly happens if $numRows value is changed when the parameter is a variable without name? Will the value be written into nirvana? Is that the PHP variable equivalent to /dev/null?
I wasn't able to find anything specific about this.
Thanks in advance
${''} is a valid variable which name happens to be an empty string. If you have never set it before, it is undefined.
var_dump(isset(${''})); // if you have never set it before, it is undefined.
You don't see any error because you disabled the NOTICE error message.
error_reporting(E_ALL);
ini_set('display_errors', 1);
echo ${''}; // Notice: Undefined variable:
You can set it like this:
${''} = 10;
echo ${''}; // shows 10
Now my question is: what exactly happens if $numRows value is changed
when the parameter is a variable without name?
There's no such thing as a variable without name, an empty string in PHP is a totally valid name.
Maybe I'm wrong, but in PHP, all varibles can be accessed by their names (or more precisely, the string representation of their name), and since an empty string is still a string, it counts as a valid name.
Think about variables like an array key-value pair. You can create an array key with an empty string:
$arr = [];
$arr[''] = 'appul';
var_dump($arr['']); // prints: string(5) "appul"
$arr[''] = 'ponka';
var_dump($arr['']); // prints: string(5) "ponka"
Whenever you access $arr[''], you address the same value.
You can access all variables as a string using the $GLOBAL variable too, so you can examine what happens to your "nameless" variable:
${''} = 'ponka';
var_dump($GLOBALS['']); // prints: string(5) "ponka"
${''} = 'appul';
var_dump($GLOBALS['']); // prints: string(5) "appul"
Will the value be written into nirvana? Is that the PHP variable equivalent to /dev/null? I wasn't able to find anything specific about this.
No, it doesn't go to nirvana, it sits quietly in the global space, and it's a little bit trickier to access it, but otherways, it's a normal variable like any others.

Can't understand syntax error, unexpected '=' in eval()'d code

I've search different forms but didn't understand how to solve the problem first found here (first link, second link) but its giving me the error in eval. I can't figure it out how to solve in that code in foreach loop.
foreach($_POST as $key => $value) {
if(!strstr($key, 'removeFile')){
//initialize variables using eval
eval("$" . $key . " = '" . sanitize($value) . "';");
}
}
First, the issues I have with your code:
eval is very, very rarely needed, and extremely dangerous, use with caution. I've been developing in PHP for over 10 years, and never really encountered a situation that needed eval. This is no exception. Eval is not required
You're sanitizing the entire $_POST array. That's great, but there are special functions for doing that, like: filter_input_array, array_filter and many, many more... not to mention ready-made, open source projects and frameworks that already contain a solid request validation component.
Always check the return values of functions, which you seem to be doing with strstr, but be weary of functions that return different types (like strstr: it returns false if the needle isn't found, but returns 0 if the needle is found at the start of the haystack string). Your if statement might not work as intended.
You're assuming sanitize($value) values will not contain any single quotes. Why? Because if they do, you'll end up with a syntax error in your evaled string
Be that as it may, you could easily write your code using variable variables and add a simple check not to step on existing variables in scope:
$sanitized = array_filter($_POST, 'sanitize');//call sanitize on all values
foreach ($sanitized as $key => $value)
{
if (!isset($$key) && strstr($key, 'removeFile') === false)
$$key = $value;
}
But really, $_POST values belong together, they are part of the request, and should remain grouped... either in an array, or in an object of some sort. Don't assign each value to its own variable, because pretty soon you'll loose track of what variables are set and which are not. Using an unset variable creates that variable, assigning value null, so what you have now makes for very error-prone code:
//request 1: POST => id=123&foo=bar
foreach ($sanitized as $k => $v)
$$k = $v;
$query = 'SELECT x, y, z FROM tbl WHERE id = ?';//using posted ID as value
$stmt = $db->prepare($query);
$stmt->execute(array($id));
All is well, because $id was set, but never trust the network, don't assume that, just because $_POST is set, all the keys will be set, and their values will be correct:
//request 2: POST => foo=bar&page=2
foreach ($sanitized as $k => $v)
$$k = $v;
$query = 'SELECT x, y, z FROM tbl WHERE id = ?';//using posted ID as value
$stmt = $db->prepare($query);
$stmt->execute(array($id));//id is null
Now we have a problem. This is just one example of how your code might cause issues. Imagine the script grows a bit, and look at this:
//request 3: POST => id=123&foo=bar&page=2
foreach ($sanitized as $k => $v)
$$k = $v;
//$id is 123, $foo is bar and $page = 2
$query = 'SELECT x, y, z FROM tbl WHERE id = ? LIMIT 10';//using posted ID as value
//a lot more code containing this statement:
$page = someFunc();
$log->write('someFunc returned log: '.$page);
//more code
$offset = 10*($page-1);//<-- page is not what we expected it to be
$query .= sprintf(' OFFSET %d', $offset);
$stmt = $db->prepare($query);
$stmt->execute(array($id));
Now this may seem far-fetched, and idiotic, but believe me: all of these things happen, more than I care to know. Adding some code that accidentally overwrites an existing variable that is used further down happens all the time. Especially in procedural code. Don't just blindly unpack an array. Keep that single variable, and use the keys to avoid:
grey hair
sudden, dramatic baldness
loss of sanity
bleeding ulcers
In a work environment: catastrophic loss of data
Sudden loss of job
... because code like this makes unicorns cry, and bronies will hunt you down
As the first answer to the post you linked to, the problem is that when using double quotes PHP thinks your eval() code starts with a variable. As that is not the case you have two options. Use single quotes and remember to escape the single quotes declaring a string in the code or escape the dollar sign.
Bonus note
There exist more elegant solutions to the problem you are trying to solve. The best solution I can think of is using the extract function. This gives to two main benefits.
It works with all associative arrays
You can specify different flags that can help you distinguish the extracted variables apart and avoid variable injection.
One flag you can use is EXTR_PREFIX_ALL. This will prefix all the extracted variables with your own prefix. You would then access the variables with a prefix of 'PREFIX_' like the following:
$array = [
'variable1' => 'foo',
'variable2' => 'bar'
];
extract($array, EXTR_PREFIX_ALL, 'PREFIX_');
$value1 = $PREFIX_variable1; // Equals: foo
$value2 = $PREFIX_variable2; // Equals: bar
A little on code injection
Suppose you have some code:
$login = false;
The $login variable determines if a user is logged in or not.
Then somewhere you use the ´extract´ function with an array of the following without using any flags.
$array = [
'login' => true,
'foo' => 'bar'
];
extract($array);
Now your $login variable would be set to true and the user posting the data would have overwritten the initial setting and gained access to your website without a valid login. Bear in mind this is a over simplified example, but nonetheless valid.
To overcome this you can use the flag EXTR_SKIP or prefix them like I previously showed. The EXTR_SKIP flag will skip the array element if a variable with the same name already is defined. So now your code would not overwrite your $login variable.
extract($array, EXTR_SKIP); // Skip existing variables
// Or
extract($array, EXTR_PREFIX_ALL, 'prefix'); // Prefix them all.
Hope this can guide to the right choice for your needs.
Regards.

Dynamically created Variables in PHP produce occasionally names like "_GET" or "_POST" instead of the variable names

I have a function from which I call many different variables, and produce another (dynamically created) return variable.
All good. (I explain my Problem below this PHP 5.3 example)
function showArrayIntersection($ar1, $ar2) {
$dynamicName = array_search($ar1, $GLOBALS) . '_' . array_search($ar2, $GLOBALS);
global ${$dynamicName};
${$dynamicName} = implode(array_values(array_intersect($ar1, $ar2)));
}
$Bankers = [6,7,0,6,5,6,2]; // `[]` is equivalent to `array()` introduced in PHP 5.4
$Bond = [6,7,0,5,0];
$Politicians = [4,6,1,6,4,6,3];
$James = [0,1,0,3,7];
showArrayIntersection($James, $Bond);
showArrayIntersection($Bankers, $Politicians);
echo "Moneysystem: $Bankers_Politicians\n";
echo "Moneypenny : $James_Bond\n";
Output:
Moneysystem: 666
Moneypenny : 007
This works most of the time well, but sometimes only instead of a variable name like $James_Bond I get a variable name like POST_POST or GET_GET, meaning instead of the name James or Bond PHP returns either a "_GET" or a "_POST".
Since AbraCadaver asked full of solicitousness: "What in the world are you doing?"
here my solution and explanation:
Einacio: I coudn't create the names on the fly because the already arrive from a first function dynamically, so the actual variable name is not the true name.
And AbraCadaver pointed out that array_search() does not accept an array; unfortunately for sake of brevity I omitted that I pass on as a first argument not an array but another dynamic created variable from the root - I didn't want to make it too complicated, but basically it works like this:
function processUsers ($userName , $request2send ){
global ${$user.'_'.$request2send};
$url2send = "http...?request=".$request2send ;
...
$returnedValue = receivedDataArray ();//example elvis ([0] => Presley );
${$user.'_'.$request2send} = $returnedValue;
}
--- now Now I get the value of the function in the root ---
$firstValue = processUsers ("cuteAnimal" , "getName");
// returns: $cuteAnimal_getName = "Mouse"
and
$secondValue = processUsers ("actorRourke" , "getFirstName");
// returns: $actorRourke_getFirstName = "Mickey";
And now the bummer - a second function which needs the first one to be completed:
function combineValues ($firstValue , $secondValue ){
global ${$firstValue.'AND'.$secondValue};
${$firstValue.'_'.$secondValue} = $firstValue." ".$secondValue;
}
// returnes $actorRourke_getFirstNameANDcuteAnimal_getName = "Mickey Mouse";
Of course the second function is much more complicated and requires first to be completed,
but I hope you can understand now that it is not an array directly which I passed on but dynamic variable names which I could not just use as "firstValue" but I needed the name "actorRourke_getFirstName".
So AbraCadaver's suggestion to use $GLOBALS[..] did not work for me since it requires arrays.
However: Thanks for all your help and I hope I could now explain the issue to you.
Argument 1 for array_search() does not accept an array.
print_r($GLOBALS); will show the empty $_GET and $_POST arrays.
What in the world are you doing?
To go with Einacio:
function showArrayIntersection($ar1, $ar2) {
$GLOBALS[$ar1 . '_' . $ar2] = implode(array_intersect($GLOBALS[$ar1], $GLOBALS[$ar2]));
}
showArrayIntersection('James', 'Bond');
echo "Moneypenny : $James_Bond\n";
You could check to make sure they exist of course isset().
how about just using the names of the variables? it would also avoid value conflicts
function showArrayIntersection($ar1, $ar2) {
$dynamicName = $ar1 . '_' . $ar2;
global ${$dynamicName};
${$dynamicName} = implode(array_values(array_intersect($_GLOBALS[$ar1], $_GLOBALS[$ar2])));
}
$Bankers = [6,7,0,6,5,6,2]; // `[]` is equivalent to `array()` introduced in PHP 5.4
$Bond = [6,7,0,5,0];
$Politicians = [4,6,1,6,4,6,3];
$James = [0,1,0,3,7];
showArrayIntersection('James', 'Bond');
showArrayIntersection('Bankers', 'Politicians');
echo "Moneysystem: $Bankers_Politicians\n";
echo "Moneypenny : $James_Bond\n";

variable value is two strings

Somehow a variable that SHOULD contain only one string (not an array or anything) contain an url, managed to contain two different values;
string(8) "value 1 " string(7) "value 2"
i cannot use this variable because echoing it or using it in another function would print
value 1 value2
which is not what i need, i need only value 1 and i cannot use $var[0]
Two things; how can i do something similar (one variable two strings), and how can i manipulate it.
EDIT : here is the code
public function get_first_image($post) {
$image_id=get_post_thumbnail_id($post->id);
$image_url = wp_get_attachment_image_src($image_id,’large’);
$image_url=$image_url[0];
var_dump($image_url);
return $image_url;
}
the var_dump() results are as mentioned above
Best Regards
Don't reuse $image_url as a variable, this is most likely causing your problem.
You should rename one of your variables:
public function get_first_image($post) {
$image_id = get_post_thumbnail_id($post->id);
$image_array = wp_get_attachment_image_src($image_id,’large’);
$image_url = $image_array[0];
var_dump($image_url);
return $image_url;
}
You question doesn't give a great amount of detail. If you need access to part of a string you can use the explode() function. So if the string contained no spaces between the separate values, you could use $newstring = explode(" ",$oldstring); echo $newstring[0]; This would then give you access to the first part of the string.
I'd recommend you look up string concatenation.
If you can give us further details, we may be able to assist you further.

Accessing psql-array directly in PHP

I am querying a psql database through PHP to get an array of boolean values where indexes are userids, e.g. userconfirm bool[]. When I do something like:
$query = "select userconfirm from calendar where id = '%s'";
$result = $this->db->query($query, 2);
var_dump($result['userconfirm']);
I get:
array(1) { [0]=> array(1) { ["userconfirm"]=> string(20) "[256:258]={t,NULL,t}" } }
Which is to say I get a string where the array should be. Ok, parsing this could probably be done, if I studied up on PHP, but this feels wrong. Surely there's a way to get the array directly?
Main question is: How do I get this array to PHP directly?
Secondary question: Is this a suitable format for keeping track of user attendance? Is there a better way?
(Re-posted from a comment by request)
Glancing at the documentation, it doesn't appear as though there's a way to directly interpolate a PostgreSQL array to an array in PHP. However, if the position of your vector represents a user id, you might be better off restructuring your data to columns with user_id and attended (the latter of which should be a boolean datatype).
PHP's native PostgreSQL driver does not support advanced data-types. In fact, it doesn't even properly support integers, booleans or anything else! (cite: As stated here under "Return Values", all values are returned as strings, NOT their correct data type: http://www.php.net/manual/en/function.pg-fetch-assoc.php)
To help battle this problem, you may want to check out PHPG, a PHP library designed to specifically transform all returned PostgreSQL values to native PHP data-types. Supports arrays for any data-type, Hstores, Geometric data-types, and more:
Numeric / Integers
If you're a numeric[] or integer[] data type which does NOT have the possibility of containing NULL values, then you can simply remove the leading and trailing curly brackets, and explode the string into an array using the comma delimiter: https://github.com/JDBurnZ/PHPG
<?php
$pg_intarr = '{1,2,3,4,5}';
$vals = substr($pg_intarr, 1, -1); // Remove curly brackets
$vals = explode(',',$vals); // Returns: array(1,2,3,4,5)
Strings
However, the problem becomes much more complex when dealing with string-based data types such as character[], character varying[] or text[] and here is why: If the value of an array contains a space or some other special character, then PostgreSQL returns that particular value encapsulated in double quotes. If the value is a single word with no special characters, then that value is returned with no quotes whatsoever.
Here is an example character varying[] value returned from PostgreSQL:
{val1,"val 2",val3,"val-4","val,4"}
The challenge here is:
Can't explicitly explode on "," because not all strings are double-quoted.
Can't explicitly explode on , because a value may contain a comma such as val,4
The only method I was able to derive after MONTHS of encountering this problem over and over again was to take the string provided by PostgreSQL, and perform a subsequent query to UNNEST the array into a result set, which is then read and transformed into a native PHP array:
$grab_vals = pg_query("SELECT UNNEST('" . pg_escape_string('{val1,"val 2",val3,"val-4","val,4"}') . "') AS value");
$grab_vals = pg_fetch_all($grab_vals);
$array_vals = array();
foreach($grab_vals as $val) {
$array_vals[] = $grab_vals['value'];
}
Booleans
In regards to boolean[] values, you could most likely take the same approach as suggested for integers. However because you also anticipate NULL values, we have the added task of mapping the string value NULL to PHP's native NULL data-type:
function pgBool2Php($string) {
if($string == 't') {
return True;
} else if($string == 'f') {
return False;
} else if($string == 'NULL') {
return Null;
} else {
raise new Exception('Mal-formed PostgreSQL Boolean encountered. Expecting value of "t", "f" or "NULL", encountered "' . $string . '"');
}
}
$pg_intarr = '{t,NULL,t,f}';
$vals = substr($pg_intarr, 1, -1); // Remove curly brackets
$vals = explode(',',$vals); // Returns: array('t','NULL','t','f')
$vals = array_map('pgBool2Php', $vals); // Returns: array(True, Null, True, False)
heres my pg_parse function on github

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