I have updated windows today and now when I use the command line and type PHP nothing returns. tried various PHP commands, nothing, not even an error or response. blank.
I had the correct path in the environment variables. Tried to change to another PHP version and even tried removing the path from environment variables but still returns empty!
It doesn't even say that "PHP" is not recognized although I removed the environment variable!!
I have no clue how to solve this.
If you are not passing extra parameters when you call it from command line, that´s how it supposed to work.
Try running:
php --help (to see all options from command line)
Also, to make sure it is running try to do this:
php -v (to check version)
php -F filename.php
The last one should run your php file.
I had the same challenge.
Here's a solution:
Use a standard terminal window (instead of Powershell).
Try php -v again.
IF you get an error mentioning VCRUNTIME140.dll
THEN you need to install run-time components that are required to run C++ applications built using Visual Studio 2015 here: https://www.microsoft.com/en-us/download/details.aspx?id=48145
Related
Ok, so I have a problem with this thing I found on a MacBook Air. It's called terminal and you can do crazy stuff on it. So anyways, when I enter the command "php" it gives me a multiline console but it doesn' do anything when I run a line of php! For instance, I type echo "Hello World" but it just returns it like a typewriter and nothing happens! Can someone please tell me what is going on, and is there a way to exit this?
Firstly check if you have php properly installed:
type in console:
php -v
you should see version of installed php for ex.:
PHP 7.3.3 ...
to run single line of code from console you do it this way:
php -r 'echo "\nHello World\n";'
where \n is new line character.
to enter interactive mode and run multiple lines of code:
php -a
and once you see:
Interactive mode enabled
php >
type:
echo "\nHello World\n";
and hit [Enter] key.
that's it.
to leave interactive mode type:
exit
note lack of ; at the end.
If you want to run from console a php code that you have in a file:
php -f <path-to-the-file>
but this is a default behavior of php so if you miss flag -f and just type:
php
it will do nothing, expecting you providing it a path to file after the php like in the example with flag -f:
php <path-to-file>
So if a programmer intention is to enter an interactive mode but he types only php without any flags, the php will not warn about missing path to the file so programmer may have the impression he's into php interactive mode as he wanted but this is not true.
to see all possible options in php cli, type:
php --help
I believe if you just type php into the terminal it will start a php server process on the local mac. If you want to run a script you have to cd in to to the working directory and type php filename.php.
If you want to use PHP code directly you must enter php -a without a flag you will just enter in php environment.
When running the php command directly from your command line, it behaves as it is reading a .php from the command line
You noticed that it just echo's back any thing you write toward it, this is the same as it is executing a .php file, its echoíng any html back to the browser
Example:
$ php
sss
<?PHP
echo 'Hello!';
?>
More data!
ctrl + d (to signal that the end of the filehas reached)
Output:
sss
Hello!More data!
I was trying to find the location of my php.ini file, and an answer to How to find the php.ini file used by the command line? stated I could find that information within the result returned by php --ini. But when I tried this, the command never returns a result (I've tried several times, with 10+ minute waits). No errors are given; it seems to be stuck in a loop. Other PHP commands, such as php -i do work. What causes this? And can I do something to fix it?
I checked my version number. I don't have the required version for --ini.
I'm running PHP 5.1.2. According to the PHP Manual Page shared by #MarkBaker the --ini option is "Available as of PHP 5.2.3."
On my debian i run xampp. I want to execute a python script using php shell_exec.
This is my php code:
shell_exec("/opt/lampp/htdocs/news/hello.py 2>1 &");
When i run it from the browser i get this error:
/usr/bin/python: /opt/lampp/lib/libz.so.1: no version information available (required by /usr/bin/python)
If i run it from the terminal window using this: php /opt/lampp/htdocs/page/index.php it works without any problems.
So any ideas how can i make it work from the browser?
Thanks
I'm guessing xampp comes with it's own libraries instead of using the system libraries, and that probably means it's setting LD_LIBRARY_PATH to it's local library directory.
This will also cause other programs started from php to use this libraries, which they may not be compatible with.
To veryfy that, try system("env");, that sould show you all the exported environment variables. If LD_LIBRARY_PATH is set, use:
shell_exec("LD_LIBRARY_PATH= /opt/lampp/htdocs/news/hello.py 2>1 &");
That unsets it before running the python script.
I wrote a script to parse some data from a website using cURL and it works fine when I run it in my browser, however when I want to run it in the command line I get the error "call to undefined function curl_init()". Do php scripts run under different settings from the command line?
This is happening because you are simply trying to call a PHP function from bash. If you have curl installed in your linux environment then the command should simply be curl [-options] [url]. The simplest of them being something like:
$ curl http://someurl.com/path/to/xmlfile.xml
You can test for this from the command line by tying "$ which curl" (without the quotes of course). That will give you the path to where it is stored in case you have to use the full path. (e.g. /usr/bin/curl [-options] [url]).
EDIT:
after having re-read your question I realized that I dumbly missed the fact that you said you were trying to run the PHP script from the command line and not curl itself. And now I, too, am stumped by your problem. Sorry!
I have a program that returns a comma-separated string of numbers after doing some background processing. I intended to run this in symfony using shell_exec; however, all I get is NULL (revealed through a var_dump(). I tried the following debugging steps.
I ran the file (it's a PHP class) through a command-line lime unit test in Symfony - it works and gives the correct result there.
Just to check, I tried a simple command ls -l at the same place to see whether I would get anything. Again, I had the same problem - the var_dump in the browser showed NULL, but it worked through the command line.
What could be the problem? Are there restrictions on running shell_exec() in a browser?
EDIT: Just to clarify, shell_exec() commands work when I run them as standalone php scripts on the web server (for example, by putting them in my document root. They don't seem to be working under the symfony framework, for some reason.
I finally solved it, and it turned out to be something quite simple, and quite unrelated.
The shell command I was running was in this format: face_query -D args. I didn't realize that Apache would be executing PHP as user www-data and thus the program face_query wouldn't be in the PATH (the directory is actually ~/bin). Changing the program name to the full path of the program solved it.
I also gather from this that only commands which www-data has permission to execute can be run. In this case, www-data is in the same group as my user, but it might be a problem otherwise.
Have you tried using exec? Or one of the other variants. I am never sure of which one to use and always lump with exec.
http://uk.php.net/manual/en/function.exec.php
Is your web server running php in safe mode?
Note: This function is disabled when PHP is running in safe mode.
From: http://php.net/manual/en/function.shell-exec.php