How to upload and insert multiple images in PHP and mysql database - php

Question

I am a beginner in PHP. I encoded some images in a base64String. All images are successfully decoding in the specified folder. My problem is am only able to record one image/path in the database. Somebody help me to come up with the PHP to insert all images paths in one row in the database.
here is the php code
<?PHP
if(isset($_POST['image']))
{
$image = $_POST['image'];
$identity = $_POST['id'];
$username = $_POST['username'];
//create unique image file name based on micro time and date
$now = DateTime::createFromFormat('U.u', microtime(true));
$id = rand(1000000, 10000000000);
$id2=rand(1000000, 10000000000);
$upload_folder = "upload";
$id="$id$id2";
$path = "$upload_folder/$id.jpeg";
if(file_put_contents($path, base64_decode($image)) != false){
echo "uploaded_success";
$sql = "UPDATE apartment SET Image_path = '$path' WHERE apart_username
='$username' AND id = '$identity'";
mysqli_query($conn, $sql);
}
else{
echo "uploaded_failed";
}
exit;
}
else{
echo "images_not_in";
exit;
}
?>

Answer 1

You need some sort of loop...all I did in the example below was instead of making a single variable called image I made a array called $imagesArr. And I added a foreach loop on the imagesArr so it will run the code you wrote for each image you input into that array. I also killed the exit at the end as that would stop the loop. That should work
<?PHP
if(isset($_POST['image']))
{
//$image = $_POST['image']; - I commented this out
$imagesArr = array('image1.jpeg','image2.jpeg','image3.jpeg'); //etc. put all of your images here into this array
$identity = $_POST['id'];
$username = $_POST['username'];
foreach ($imagesArr as $key => $image) {
//create unique image file name based on micro time and date
$now = DateTime::createFromFormat('U.u', microtime(true));
$id = rand(1000000, 10000000000);
$id2=rand(1000000, 10000000000);
$upload_folder = "upload";
$id="$id$id2";
$path = "$upload_folder/$id.jpeg";
if(file_put_contents($path, base64_decode($image)) != false){
echo "uploaded_success";
$sql = "UPDATE apartment SET Image_path = '$path' WHERE apart_username
='$username' AND id = '$identity'";
mysqli_query($conn, $sql);
}
else{
echo "uploaded_failed";
}
}
else{
echo "images_not_in";
}
}