I was trying to paginate some data with Query builder with the following query.
public function productSearch(Request $request)
{
$name = $request->name;
$products = DB::table('products')
->where('name', 'LIKE', "%$name%")
->paginate(4);
return view('product',compact('products');
}
But when I tried to show the pagination in the view page with the following line
{{ $products->links() }}
It shows
Method links does not exist
What could the possible error be since the pagination does not show?
2 types to print pagination link in laravel -
Try with -
use Illuminate\Support\Facades\DB;
public function productSearch(Request $request)
{
$name = $request->name;
$products = DB::table('products')
->where('name', 'LIKE', "%$name%")
->paginate(4);
return view('product',['products' => $products]);
}
In View -
<div class="container">
#foreach($products as $product)
<h4>{{ $product['name'] }}</h5> <br>
#endforeach
</div>
1st type to defined laravel pagination link -
{{ $products->links() }}
And 2nd type to defined laravel pagination link -
{{ $products->render(); }}
Note - Also you missed in your code -> return view('product',compact('products')); in return view('product',compact('products');
Here is your solution.
Just change your return view option
return view('product')->with('products', $products);
Hope this helps you.
Change to :
return view('product',compact('products'));
In View page try :
{{$products->render()}}
In your Controller:
return view('product',compact('products');
In your View:
#foreach($products as $product)
{{ $product->name }}
#endforach
{{ $products->links() }}
try with:
{{ $products->render() }}
Related
how do I display an object name of an array that I fetched from the database in Laravel blade?
When I dump array in Laravel controller I get this "name" => "{"name":"Item 1"}". Now, how do extract Item 1 from array and display in a blade while looping using foreach.
Controller
$data = DB::table('items')
->select('name')
->where('id', $user->id)
->get();
$output = json_decode($data,true);
dd($output);
Results
"name" => "{"name":"Item 1"}
Kindly help.
You have to extract from each object separately.
Variant 1:
Controller:
$data = DB::table('items')->select('name')->where('id', $user->id)->get()
->map(function($item){
$item->name = json_decode($item->name, true);
return $item;
});
return view('some_view', ['data' => $data]);
View:
#foreach($data as $d)
<p>{{ is_array($d->name) ? $d->name['name'] : 'No Name' }}</p> {{-- Just Checking if Json is correctly decoded --}}
#endforeach
Variant 2:
Controller:
$data = DB::table('items')->select('name')->where('id', $user->id)->get();
View:
#foreach($data as $d)
#php($name = json_decode($d->name, true))
<p>{{ is_array($name) ? $name['name'] : 'No Name' }}</p> {{-- Just Checking if Json is correctly decoded --}}
#endforeach
Controller:
$dataes = DB::table('items')
->select('name')
->where('id', $user->id)
->get();
return view('viewName',compact('dataes'));
View:
#foreach($dataes as $data)
{{ $data->name }}
#endforeach
StaffController
public function show($id){
$staffinfo = DB::table('staff')->where('user_id', $id)->get();
return view('staff.view')->with('staffinfo', $staffinfo);
}
view.blade.php
<h1>{{$staffinfo->name}}</h1>
<p>{{$staffinfo->user_id}}</p>
Is this code right to show data from staff table in view by show($id) function?
Getting error:
"Property [name] does not exist on this collection
instance. (View:
F:\xampp\htdocs\gchsc\resources\views\staff\view.blade.php)"
Switch ->get() to ->first(). $staffInfo is a Collection of database records, not a single one:
StaffController.php
$staffinfo = DB::table('staff')->where('user_id', $id)->first();
Then the following will work in your view:
staff/view.blade.php
<h1>{{ $staffinfo->name }}</h1>
<p>{{ $staffinfo->user_id }}</p>
Or, leave your code as is and iterate in your view:
StaffController.php
$staffinfo = DB::table('staff')->where('user_id', $id)->get();
staff/view.blade.php
#foreach($staffInfo AS $staff){
<h1>{{ $staff->name }}</h1>
<p>{{ $staff->user_id }}</p>
#endforeach
I have this function, where i get my categories base on their slug
public function postcategoryposts($slug){
$category = PostCategory::where('slug','=',$slug)->firstOrFail();
return view('front.postcategory-posts', compact('category'));
}
Currently i'm getting my each category posts in blade like:
#foreach($category->posts as $post)
{{$post->title}}
#endforeach
until here everything is normal, the problem is how to divide my posts into pages? I am not able to use:
$category = PostCategory::where('slug','=',$slug)->paginate(10);
because I'm using
firstOrFail();
any idea?
You need to add a function to your model to get posts and then paginate.
In your controller
public function postcategoryposts($slug)
{
$category = PostCategory::where('slug','=',$slug)->firstOrFail();
$posts = $category->getPaginatedPosts(10);
return view('front.postcategory-posts', compact('posts'));
}
In your model
// PostCategory model
public function getPaginatedPosts($limit = 10)
{
// Get category posts using laravel pagination method
return Post::where('category_id', '=', $this->id)->paginate($limit);
}
In your blade view
<div class="container">
#foreach ($posts as $post)
{{ $post->title }}
#endforeach
</div>
{{ $posts->render() }}
More informations about Laravel pagination here
Hope it's helps you :)
i'm passing my array $posts to my view and i'm tryng use pagination but i have the error:
Method links does not exist. (View:
C:\xampp\htdocs\app\resources\views\search.blade.php)
CONTROLLER
$posts = Post::where('visible', 1)
->where('expire_date', '>', $current)->where('delete', 0);
$posts->paginate(1);
$posts = $posts->get();
return view('search', compact('posts'));
VIEW
<div class="pagination-bar text-center">
{{ $posts->links() }}
</div>
Change you code to this:
$posts = Post::where('visible', 1)
->where('expire_date', '>', $current)
->where('delete', 0)
->paginate(1);
return view('search', compact('posts'));
Your code doesn't work because you do not save paginate() results to a variable, like $posts = $posts->paginate(1);. Also, you shouldn't use get() or all() after paginate().
So I know about passing variables via the controller for instance if its a query array I will do
public function index()
{
$query = Request::get('q');
if ($query) {
$users = User::where('username', 'LIKE', "%$query%")->get();
}
return view('view', compact('users'));
}
And when on the blade I will do
#if( ! empty($users))
#foreach($users as $user)
{{ $user->username }}
#endforeach
#endif
Now my question is how do I set a variable using a variable from the foreach? at the moment I am using PHP inside of the blade template file but I feel this is messy, here is what I have
#if( ! empty($users))
#foreach($users as $user)
<?php
$lastOnline = \Carbon\Carbon::createFromTimeStamp(strtotime($user->last_online))->diffForHumans();
$fiveMinsAgo = \Carbon\Carbon::now()->subMinute(5);
?>
{{ $user->username }}
#if ($user->last_online <= $fiveMinsAgo)
{{ $lastOnline }}
#else
Online Now
#endif
#endforeach
#endif
found a solution to my issue if anyone else is ever looking for it.
public function getLastOnlineAttribute($value)
{
$fiveMinsAgo = \Carbon\Carbon::now()->subMinute(5);
$thirtMinsAgo = \Carbon\Carbon::now()->subMinute(30);
$lastOnline = \Carbon\Carbon::createFromTimeStamp(strtotime($value))->diffForHumans();
if ($value <= $fiveMinsAgo) {
echo 'Last Active: '.$lastOnline.'';
}
else {
echo 'Online Now';
}
}
Basically add this into your model for the variable (eg, if its a $user->last_online it would go into the user model) , it is called a eloquent mutator if you are ever looking for more info, https://laravel.com/docs/master/eloquent-mutators
It grabs your data for the variable for instance {{ $user->last_online }}
Note that the Underscore is transformed into a CamelCase in the function name, the output is set at $value, you can then set variables inside of the function and mould the output however you wish, then in the blade you can get rid of all the extra crap and just use {{ $user->last_online }}