I referred to some examples online and modified functions.php and the front end template to fire an ajax call to fetch some data. But I've hard time understanding on hoe the data is returned from the requested url.
At the end of functions.php, I added,
wp_enqueue_script('jquery');
function myFunction(){
echo "hi";
die();
}
add_action('wp_ajax_myFunction', 'myFunction');
add_action('wp_ajax_nopriv_myFunction', 'myFunction');
In my custom template page, I added,
var datavalue = 'test data string';
jQuery.ajax({
url: "/wp-admin/admin-ajax.php",
method: "GET",
data: { 'datavar' : datavalue }
}).success(function(data) {
console.log("successfully run ajax request..." + data);
}).done(function(){
console.log("I am from done function");
}).fail(function(){
console.log("I am from fail function.");
}).always(function(){
console.log("I am from always function");
});
});
After running it, I get these response.
I am from fail function.
I am from always function
I don't understand how to fetch data from a specific url and display the result in ajax's success function.
I don't even know how the function defined in function.php would be called by this ajax call? How are they related?
Please explain. Also I would like to fire ajax call to query database by passing keyword, how can I do that in wordpress?
Your AJAX function should include an action parameter to tell admin-ajax which function you would like to execute.
url: "/wp-admin/admin-ajax.php",
method: "GET",
data: {
action : 'myFunction'
}
(or, if you are set up for it, then you can include it in your url, as below)
url: "/wp-admin/admin-ajax.php?action=myFunction"
Also, your function in functions.php should be written in PHP:
function myFunction(){
echo 'hello';
die();
}
You have to use a action on ajax like.
jQuery.ajax({
url: "/wp-admin/admin-ajax.php",
method: "GET",
data: {
action : 'myFunction'
'datavar' : datavalue,
}
});
PHP function need to edit.
function myFunction(){
echo 'success calling functions';
wp_die();
}
you are not passing the "action" parameter in "data". Which contains callback function's name. Please check the attached link.
https://www.sitepoint.com/how-to-use-ajax-in-wordpress-a-real-world-example/
In this you've to make a callback functions.
Wordpress dsnt work with the specific url.
But if you still want to use the specific url. Follow the steps:-
1. Make a wordpress template.
2. Add your specific url code there.
3. Make a page in the admin panel and assign the template you've created above.
4. Now the permalink of that page can be used as a specific url in the jQuery ajax.
In addition to above answers, in your function.php, make use of $_REQUEST. The $_REQUEST contains all the data sent via AJAX from the Javascript call. Something like this
function myFunction() {
if ( isset($_REQUEST) ) {
{
global $wpdb;
$keyword = $_REQUEST["keyword"];
if($keyword){
$query = "
SELECT `$keyword`, COUNT($keyword) AS Total
FROM `profileinfo` GROUP BY `$keyword`
";
$result = $wpdb->get_results($query);
$data = array();
foreach($result as $row)
{
$data[] = $row
}
echo json_encode($data);
}
}
}
die();
}
add_action( 'wp_ajax_myFunction', 'myFunction' );
add_action('wp_ajax_nopriv_myFunction', 'myFunction');
Related
I have a function that adds social buttons to my blog posts , but once i load more posts using ajax I cant figure out how can I call add_social_buttons() and pass the data to div.
I'm not really familiar with ajax , i tried this method :
$.ajax({
type:"POST",
url:"functions.php",
data: "social_sharing_buttons()",
success: function(data){
$('.pp').html(data);
}
but it seems that it tries to invoke some totally other function Fatal error: Call to undefined function add_action().
As far as I am aware, you can't. What you can do is have a handler file for your classes, so for example say we have this PHP class,
<?php
class Car {
function getCarType() {
return "Super Car";
}
}
?>
Then in your handler file,
<?php
require_once 'Car.php';
if(isset($_POST['getCarType'])) {
$car = new Car();
$result = $car->getCarType();
echo $result;
}
?>
You'd post your AJAX request to the handler, you could make specific handlers for each request or you could have a generic AJAX handler, however that file could get quite big and hard to maintain.
In your case you'd have in that data,
"getSocialButtons" : true
Then in your AJAX handler file,
if (isset($_POST['getSocialButtons'])) {
// Echo your function here.
}
Then you'd echo out the function within that if statement and using the success callback in your AJAX request do something like this.
document.getElementById("yourDivId").innerHTML = data
That is assuming you're using an ID. Adjust the JS function to suit you.
Try to call that function social_sharing_buttons() like this in function.php:
$.ajax({
type:"POST",
url:"functions.php",
data: {action: 'add'},
success: function(data){
$('.pp').html(data);
}
in functions.php
if(isset($_POST['action']) && !empty($_POST['action'])) {
if($_POST['action'] == 'add') {
echo social_sharing_buttons();
}
}
I am writing a javascript which will post hostname of the site to a php page and get back response from it, but I don't know how to assign the hostname to adrs in url and not sure that code is correct or not.And this needs to done across server
javascript:
function ursl()
{
$.ajax({
url: 'http://example.com/en/member/track.php?adrs=',
success: function (response)
if (response)=='yes';
{
alert("yes");
}
});
}
track.php
$url=$_GET['adrs'];
$sql="SELECT * FROM website_ad where site='$url'";
$res=mysqli_query($link,$sql);
if(mysqli_num_rows($res)==0)
{
echo"no";
}
else
{
echo"yes";
}
Your ajax function should be written thusly:
$.ajax({
url: 'http://example.com/en/member/track.php?adrs=' + window.location.hostname,
success: function (response) {
if (response === 'yes') {
$.getScript('http://example.com/en/pop.js', function () {
// do anything that relies on this new script loading
});
}
}
});
window.location.hostname will give you the host name. You are passing it to the ajax url by concatenating it. Alternatively, as katana314 points out, you could pass the data in a separate parameter. Your ajax call would then look like this:
$.ajax({
url: 'http://example.com/en/member/track.php?adrs=',
data: {adrs: window.location.hostname},
success: function (response) {
if (response === 'yes') {
$.getScript('http://example.com/en/pop.js', function () {
// do anything that relies on this new script loading
});
}
}
});
I'm not sure what you intend response to be, but this code assumes it is a string and will match true if the string is 'yes'. If response is meant to be something else, you need to set your test accordingly.
$.getScript() will load your external script, but since it's asynchronous you'll have to put any code that is dependent on that in the callback.
In this type of GET request, the variable simply comes after the equals sign in the URL. The most basic way is to write this:
url: 'http://example.com/en/member/track.php?adrs=' + valueToAdd,
Alternatively, JQuery has a more intuitive way of including it.
$.ajax({
url: 'http://example.com/en/member/track.php',
data: { adrs: valueToAdd }
// the rest of the parameters as you had them.
Also note that you can't put a script tag inside a script. You will need some other way to run the Javascript function mentioned; for instance, wrap its contents in a function, load that function first (with a script tag earlier in the HTML), and then call it on success.
And for the final puzzle piece, you can retrieve the current host with window.location.host
You'll need to change this line to look like so:
url: 'http://example.com/en/member/track.php?adrs='+encodeURIComponent(document.URL)
The full success function should look like so:
success: function (response){
if (response==="yes"){
//do your thing here
}
}
That should solve it...
The website I'm developing is structured in this way:
It has a function that switches the module for the homepage content when $_GET['module'] is set, example:
function switchmodules()
{
$module=$_GET['module'];
switch($module)
{
case 'getnews': news(); break;
default: def();
}
}
As you can see, this switch calls another function for each module.
For example I wrote getNews() to work in this way:
function getNews()
{
$id=$_GET['id'];
if(!id)
{
//CODE TO LIST ALL NEWS
}
if(isset($id))
{
//CODE TO GET ONLY 1 NEWS BY ID
}
}
So, as you can see I'm not using an unique file for each module; all operations of a module are part of an unique function in which an action is switched again to change the result.
If I want to get a news from database I should use an url like this: ?index.php&module=getnews&id=1
My question now is:
With jQuery and $.ajax() method is there a way to get a news (for example) using this structure based on functions switched by a get? Or do I have to change everything and make a file for each function?
you can simply call the same url via $.ajax(). the only thing which should be changed for axjax calls is that you don't output your layout, but only the news itsself.
in php you can check for an ajax request like
if (isset($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') {
// dont output layout
}
If this code is in say 'test.php' you can do:
<script>
$.get(
'/test.php',
{
module: 'news',
id: 1
},
function( data ) {
alert( data );
}
);
</script>
And js will send GET request to test.php with needed params. Then your server script will decide how to process request.
jQuery
$(document).ready( function() {
var form = '#my_awesome_form';
$(form + ' input[type=submit]').click(function(e) {
e.preventDefault();
$.ajax({
type: "GET",
url: 'index.php',
data: $(form).serialize(),
success: function( response ) {
alert('DONE!');
}
});
});
});
HTML
<form id="my_awesome_form" // OTHERS PROPERTIES //>
// LOT OF FIELDS HERE //
<input type="submit" value="Send">
</form>
I'm running into trouble accessing global variables when I make an AJAX call to a php function in the MediaWiki framework.
My jQuery AJAX call looks like this:
jQuery.ajax({
url: 'GeneralFunctions.php',
type: 'GET',
dataType: 'json',
data: {
text: anchorText
},
success: function (data) {
alert("data: " + data);
}
});
My GeneralFunctions.php file looks like this:
<?php
if (isset($_GET['text'])) {
jsonInlineParse((string) $_GET['text']);
}
function jsonInlineParse($wikiText)
{
global $wgOut;
$return = $wgOut->parseInline($wikiText); //fails here
echo json_encode($return);
}
?>
When I run the jQuery call through a click event I get as far as the parseInline() function. The global variable is never defined in the scope and I get the error:
Fatal error: Call to a member function parseInline() on a non-object in /path/to/file/GeneralFunctions.php on line 54
I'm not sure how to make the parse call and define the global variable when the AJAX call is made?
UPDATE
$wgOut is the OutputPage object associated with MediaWiki. It holds all the HTML of the page and is used throughout the MediaWiki framework to add content to a page or article. It is used on the server side to create customized output for wiki articles. I use it to create forms or add HTML on many of our wikis.
More info here: http://www.mediawiki.org/wiki/Manual:$wgOut
UPDATE 2
#Juhana I changed my function to look like this which results in the same error as before. Each echo outputs "NULL".
<?php
function jsonInlineParse($wikiText)
{
include_once '/path/to/file/includes/OutputPage.php';
include_once '/path/to/file/includes/parser/Parser.php';
echo var_dump($wgOut);
global $wgOut;
echo var_dump($wgOut);
$return = $wgOut->parseInline($wikiText);
echo $return;
echo json_encode($return);
}
?>
I took a different approach after running into global variable problems. I changed the AJAX call I was making and the code below works very well for me. I'm using the editable jquery table you can find here.
PHP
function ajax_parse(){
global $wgRequest;
if($wgRequest->wasPosted()){
$text = $wgRequest->getVal("text");
wfDebug("Recieving::::".$text);
if(!strpos($text, "href")){
$text = myInlineParse($text);
$text = str_replace("<pre>", "", $text);
$text = str_replace("</pre>", "", $text);
}
wfDebug("Returning::::".$text);
echo $text;
}
exit;
}
function myInlineParse( $wikiText ) {
global $wgOut;
return $wgOut->parseInline( $wikiText );
}
JavaScript
// inject wikitext after hitting save
function postSave(o) {
var response = new Array("");
for(var i=0;i<o.row.length;i++){
new Ajax.Request(wgScript +'/Special:EditClass/ajax_parse',
{
asynchronous: false,
parameters: {'text': o.row[i].innerHTML},
onSuccess: function(text){
response.push(text.responseText);
}
}
);
}
return response;
}
For whatever reasons, extensions don't seem to have access to $wgOut. I solved this for my extension by using the hook: OutputPageParserOutput for the code I needed output (I needed to inject some scripts and stylesheets as well as using another hook to modify links and didn't want to bother with Resource_Loader though it is useful and recommended):
$wgHooks['OutputPageParserOutput'][] = array($this, 'doOutputPageParserOutput'); // 'doOutputPageParserOutput' defined as method in my class
As with other hooks, you can get rid of the array in favor of just a function name if you don't want to execute within a class.
Fiddling inside CodeIgniter and trying to get a grip on it all as I've never worked with AJAX before.
For some reason, my AJAX is working perfectly when I use the GET method, but if I switch it over to the POST method, it stops working.
My JS:
$(document).ready(function(){
$('.love').click(function(event) {
$.ajax({
type: 'GET',
url: base_url + '/ajax/love_forum_post',
data: { post_id: 2, user_id: 1, ajax: 1 },
});
return false;
});
});
And my CONTROLLER:
function love_forum_post()
{
$post_id = $this->input->get('post_id');
$user_id = $this->input->get('user_id');
$is_ajax = $this->input->get('ajax');
if ($is_ajax)
{
$this->load->model('forums_model');
$this->forums_model->add_love($post_id, $user_id);
}
// If someone tries to access the AJAX function directly.
else
{
redirect('', 'location');
}
}
If I switch the type to 'POST' inside my JS and then catch it on the other end with $this->input->post() it doesn't work.
Any suggestions?
I have tested your code in 2 scenarios:
first - without csrf protection, and I see no reason for your code not to run properly.
To be able to test it easier, append $.ajax call with success response.
Something like this
success: function(response) {
alert(response);
}
And add response to your love_forum_post method.
echo print_r($this->input->post(), true);
This would give you clean view of what it going on in your method.
In my installation everything works just fine.
Second scenario is with csrf protection.
In this case add new param to your post object.
<?php if ($this->config->item('csrf_protection') === true) : ?>
post_data.<?php echo $this->security->get_csrf_token_name()?> = '<?php echo $this->security->get_csrf_hash()?>';
<?php endif ?>
This would make CI accept post from this url.
Hopefuly it would help.
Cheers
By any chance you have csrf_protection enabled?
If yes you need to send the token and the value key as post parameter along with post request.
Try to use this
$post_data = $_POST;
and print the post data using this
print_r($post_data);die();
and you can see there if you catch the post data;
Gudluck!!