how to combine 2 array values into single one by common value - php

Question

1.fetching the values from a same table with different date
<?php
$date= date("Y-m-d");;
$prev_date = date('Y-m-d', strtotime($date .' -1 day'));
$result_yest=mysql_query("SELECT isp,sum(sent) AS `sent_yest` FROM red_global WHERE status_date='$prev_date' and sent > 0 group by 1",$link1);
$data_yest = array(); // create a variable to hold the information
while (($row_yest = mysql_fetch_array($result_yest, MYSQL_ASSOC)) !== false){
$data_yest[] = $row_yest; // add the row in to the results (data) array
}
print_r($data_yest);
$result_today=mysql_query("SELECT isp,sum(sent) AS `sent_today` FROM red_global WHERE status_date='$date' and sent > 0 group by 1",$link1);
$data_today = array(); // create a variable to hold the information
while (($row_today = mysql_fetch_array($result_today, MYSQL_ASSOC)) !== false){
$data_today[] = $row_today; // add the row in to the results (data) array
}
print_r($data_today);
exit;
?>
2.Array results in which one array contains yesterday's sent count and another one aray contains today's sent count both array having the common isp
Array (
[0] => Array ( [isp] => aol [sent_yest] => 46838 )
[1] => Array ( [isp] => gmail [sent_yest] => 33015 )
[2] => Array ( [isp] => juno [sent_yest] => 93544 )
[3] => Array ( [isp] => roadrunner [sent_yest] => 6181 )
[4] => Array ( [isp] => yahoo [sent_yest] => 71444 )
)
Array (
[0] => Array ( [isp] => aol [sent_today] => 14135 )
[1] => Array ( [isp] => att [sent_today] => 624 )
[2] => Array ( [isp] => gmail [sent_today] => 21263 )
[3] => Array ( [isp] => juno [sent_today] => 74934 )
[4] => Array ( [isp] => roadrunner [sent_today] => 939 )
[5] => Array ( [isp] => yahoo [sent_today] => 22059 )
)
Now i need a result like this isp name, yesterday's sent count, today's sent count
[isp, sent_yest, sent_today],
[aol, 46838, 14135],
[att, 0, 624],
[gmail, 33015, 21263],
Anyone help me to solve this.. Thanks in advance

Answer 1

Do it like below:-
$final_array = array();
if(count($arr1)>=count($arr2)){
foreach ($arr1 as $arr){
$key='';
foreach ($arr2 as $ar2){
if($arr['isp'] == $ar2['isp']){
$final_array[$arr['isp']] = array($arr['isp'],$arr['sent_yest'],$ar2['sent_today']);
$key ='';break;
}else{
$key = $arr['isp'];
}
}
if($key!==''){
$final_array[$key] = array($arr['isp'],$arr['sent_yest'],0);
$key ='';
}
}
}
if(count($arr2)>count($arr1)){
foreach ($arr2 as $ar2){
$key='';
foreach ($arr1 as $arr){
if($ar2['isp'] == $arr['isp']){
$final_array[$ar2['isp']] = array($ar2['isp'],$arr['sent_yest'],$ar2['sent_today']);
$key ='';break;
}else{
$key = $ar2['isp'];
}
}
if($key!==''){
$final_array[$key] = array($ar2['isp'],0,$ar2['sent_today']);
$key ='';
}
}
}
echo "<pre/>";print_r($final_array);
Output:-https://eval.in/814625

Answer 2

I would avoid foreach if it's possible, since it leads to code that's much harder to understand. With array operation it can look like this:
// First we merge the two arrays
$merged = array_merge($data_yest, $data_today);
// Then format it
$final = array_reduce($merged, function($final, $item) {
// Initialize for each isp if it's not present
// This way we avoid overwriting previous data and have a default value 0
if (! isset($final[ $item['isp'] ])) {
$final[ $item['isp'] ] = [
'sent_yest' => 0,
'sent_today' => 0,
];
}
// And if one of the days is present, we add it
if (isset($item['sent_yest'])) {
$final[ $item['isp'] ][ 'sent_yest' ] = $item['sent_yest'];
}
if (isset($item['sent_today'])) {
$final[ $item['isp'] ][ 'sent_today' ] = $item['sent_today'];
}
// Then return the modified array
return $final;
}, []);
print_r($final);
exit;
Result looks like this:
Array
(
[aol] => Array
(
[sent_yest] => 46838
[sent_today] => 14135
)
[gmail] => Array
(
[sent_yest] => 33015
[sent_today] => 21263
)
[juno] => Array
(
[sent_yest] => 93544
[sent_today] => 74934
)
[roadrunner] => Array
(
[sent_yest] => 6181
[sent_today] => 939
)
[yahoo] => Array
(
[sent_yest] => 71444
[sent_today] => 22059
)
[att] => Array
(
[sent_yest] => 0
[sent_today] => 624
)
)