A PHP Error was encountered Severity: Notice Message: Undefined variable: result - php

Question

A PHP Error was encountered Severity: Notice
Message: Undefined variable: result
Filename: user/messages.php
Line Number: 87
Backtrace:
File: E:\xampp\htdocs\ci\application\views\user\messages.php Line: 87
Function: _error_handler
File: E:\xampp\htdocs\ci\application\controllers\users\Dashboard.php
Line: 12 Function: view
File: E:\xampp\htdocs\ci\index.php Line: 315 Function: require_once
here is my code
Controller
<?php defined('BASEPATH') OR exit('No direct script access allowed');
class Bills extends CI_Controller{
function __construct(){
parent::__construct();
}
public function bill(){
$id = $this->session->userdata('email');
$this->load->database();
$this->load->helper(array('form', 'url', 'html'));
$this->load->model('fuser/Bill');
$data['result'] = $this->Bill->bills();
$this->load->view('user/messages',$data);
}
}
?>
**Model**
<?php
class Bill extends CI_Model
{
function __construct()
{
// Call the Model constructor
parent::__construct();
}
//we will use the select function
public function bills($id)
{
//data is retrive from this query
$query = $this->db->get('invoices');
return $query->result();
}
}
?>
**View**
<div class="billing_tabs_text_part">
<?php foreach($result as $row){?>
<p><?php echo $row['book_id']; }?></p>
</div>

Answer 1

i am not sure which section is your problem so i suggest something how to find error
public function bill()
{
echo 'ok'; // check controller work
$id = $this->session->userdata('email');
$this->load->database();
echo 'ok1';
$this->load->helper(array('form', 'url', 'html'));
echo 'ok2';
/*$this->load->model('fuser/Bill');
$data['result'] = $this->Bill->bills();
$this->load->view('user/messages', $data);*/
}
if this is print ok, ok1 , ok2 then this is query problem , if no print ok,ok1 then this is not query problem
in this case try to find error, if other ok then must print ok
public function bill()
{
echo 'ok';
/*$id = $this->session->userdata('email');
$this->load->database();
$this->load->helper(array('form', 'url', 'html'));
$this->load->model('fuser/Bill');
$data['result'] = $this->Bill->bills();
$this->load->view('user/messages', $data);*/
}

Answer 2

use <?php echo $row->book_id; }?> in view
because your data is object array.

Answer 3

You need to find where the problem is exactly
try to var_dump the results and see if you're actually getting any results and that result is not a null or false;
so before this line:
$data['result'] = $this->Bill->bills();
try to
var_dump($this->Bill->bills());
die();
if you're getting results try the other way using dummy content instead of $this->Bill->bills(); use :
$data['result'] = [0 => 1, 1 =>2]; and var_dump from the view
see if you're getting results, and in line where you have
return $query->result();
make it like this:
return $query->result() ? : [];

Answer 4

What gives you $query->result(); try to print in model itself

Answer 5

don't return , print and check the result
ex:
var_dump($query->result());