php echo "%" displaying more than once - php

Question

Testing with data scraping. The output I'm scraping, is a percent. So I basically slapped on a
echo "%<br>";
At the end of the actual number output which is
echo $ret_[66];
However there's an issue where the percent is actually appearing before the number as well, which is not desirable. This is the output:
%
-0.02%
Whereas what I'm trying to get is just -0.02%
Clearly I'm doing something wrong with the PHP. I'd really appreciate any feedback/solutions. Thank you!
Full code:
<?php
error_reporting(E_ALL^E_NOTICE^E_WARNING);
include_once "global.php";
$doc = new DOMDocument;
// We don't want to bother with white spaces
$doc->preserveWhiteSpace = false;
$doc->strictErrorChecking = false;
$doc->recover = true;
$doc->loadHTMLFile('http://www.moneycontrol.com/markets/global-indices/');
$xpath = new DOMXPath($doc);
$query = "//div[#class='MT10']";
$entries = $xpath->query($query);
foreach ($entries as $entry) {
$result = trim($entry->textContent);
$ret_ = explode(' ', $result);
//make sure every element in the array don't start or end with blank
foreach ($ret_ as $key => $val){
$ret_[$key] = trim($val);
}
//delete the empty element and the element is blank "\n" "\r" "\t"
//I modify this line
$ret_ = array_values(array_filter($ret_,deleteBlankInArray));
//echo the last element
echo $ret_[66];
echo "%<br>";
}

Answer 1

<?php
echo "%<br>";
?>
On a seperate following PHP code. Does the same thing.