onchange dropdown show checkbox is checked in php - php

Question

code:
<script>
$(document).ready(function(){
$(".menu").click(function(){
ids = $('.menu:checked').map(function() {
return this.id;
}).get().join(',');
console.log(ids);
$("#ids").val(ids);
});
});
</script>
<?php
if(isset($_POST['submit']))
{
$adminid = $_POST['admin'];
$menuids = explode(",", $_POST['ids']);
foreach ($menuids as $idd)
{
$sql = "update menu set admin_id = concat(admin_id,'$adminid',',') where id = '$idd'";
$result = mysqli_query($link,$sql);
}
if($result == true)
{
$msg .= "<p style='color:green'>successfull</p>";
}
else
{
$msg .= "<p style='color:red'>error!</p>";
}
}
?>
<form method="post">
<select name="admin" id="admin">
<option value="">---Select Admin---</option>
<?php
$sql = "select * from admin";
$result = mysqli_query($link,$sql);
while ($row = mysqli_fetch_array($result))
{
?>
<option value="<?php echo $row['id']; ?>"><?php echo $row['firstname']?></option>
<?php
}
?>
</select>
<table>
<tr>
<th>Share</th>
<th>Menu Name</th>
</tr>
<?php
$query = "select * from menu";
$results = mysqli_query($link,$query);
while ($fetch = mysqli_fetch_array($results))
{
?>
<tr>
<td>
<input type="checkbox" class="menu" id="<?php echo $fetch['id']; ?>" name="menuid" />
</td>
<td>
<?php echo $fetch['menu_name']; ?>
</td>
</tr>
<?php
}
?>
</table>
<input type="text" name="ids" id="ids" value=""/>
<input type="submit" name="submit" id="submit" />
</form>
In this code I am update a table having name menu in database. Now, I want to check only those checkbox where admin_id like ,1, or ,2, which is update by query. How can I fix this issue ?please please help.
Thank You

Answer 1

while ($fetch = mysqli_fetch_array($results))
{
?>
<tr>
<td>
<input type="checkbox" class="menu" value="<?php if($fetch['id']==1 or
$fetch['id']==2 ) { echo "checked";} else{} ?>" name="menuid" />
</td>
<td>
<?php echo $fetch['menu_name']; ?>
</td>
</tr>
<?php
}
?>