PHP SQL statement using REGEXP to fetch multiple values - php

How do I use REGEXP to fetch multiple data from the array $vall.
I referred a sample code from:
PHP sql statement where clause to multiple array values
Some of the sample data: CGCG-0025-0,CGCR-0003-0,CGRQ-0163-0
foreach ($list as $value) // this $list is from another array
{
$part = $value[3];
$vall[] = $value[3]; // $list1 is an empty array
}
$partnumber =[];
foreach($vall as $v)
{
$partnumber[] = "*.".$v.".*";
print_r(array_values($partnumber)); // these are some of the values Array ( [0] => *.CGCG-0025-0.* ) Array ( [0] => *.CGCG-0025-0.* [1] => *.CGCG-0025-0.* ) Array ( [0] => *.CGCG-0025-0.* [1] => *.CGCG-0025-0.* [2] => *.CGCR-0003-0.* )
}
foreach($partnumber as $x)
{
echo '<br>'.$partnumber; // shows 'Array' on each lines
}
$fsql="select * from Error where RptDatime = 201706091000 and partnumber REGEXP '".implode("|",$partnumber)."'";
//example 1 $fsql="select * from MPdError where RptDatime = 201706091000 and partnumber = ('CGRQ-0057-0') ";
//example 1 shows the correct data but i need multiple partnumber
$getResults = $conn->prepare($fsql);
$getResults->execute();
$results = $getResults->fetchAll(PDO::FETCH_BOTH);
foreach($results as $row)
{
$mac = $row['Machine'];
$id = $row['Id'];
echo '<br><br><br>ID:'.$id.'<br>Machine Number :'.$mac;
}

Though this may not be a good solution as it contains a huge security risk, I will still post it based on what is needed above.
REGEXP is not needed for data that are not complex in design.
$fsql = "select * from Error where RptDatime = 201706091000 and partnumber in ('" . implode("','", $vall) . "');"

Related

Add multiple SQLresults to an array while in a foreach loop

I am having some trouble trying to get this done. The issue is:
I have an array that looks like
wants_arr_flat ( [0] => booze [1] => nudes [2]
=> rooms
I want my foreach loop to go through these values making a different SQL statement and then saving the result of that SQL statement on to another array. The code I am trying to work with now is this.
foreach ( $wants_arr_flat as $value ) {
$sql = "SELECT * FROM offers WHERE user_id != $_SESSION[user_id] AND offer='$value'";
$result=$conn->query($sql);
$want_match_arr = mysqli_fetch_row($result);
echo '<pre>'; print_r($want_match_arr); echo '</pre>'; //testing echo
Obviously this is just overwriting the last array each iteration so I only end up with one result in the array.
instead of
$want_match_arr = mysqli_fetch_row($result);
use
$want_match_arr[] = mysqli_fetch_row($result);
If you get multiple rows from SQL then this is better.
$want_match_arr = [];
foreach ( $wants_arr_flat as $value ) {
$sql = "SELECT * FROM offers WHERE user_id != $_SESSION[user_id] AND offer='$value'";
$result=$conn->query($sql);
while ($row = mysql_fetch_assoc($result)) {
$want_match_arr[] = $row;
}
}
echo '<pre>'; print_r($want_match_arr); echo '</pre>'; //testing echo

Make Associative array with three element in array

I want three element in associative array, so far am successful in getting two in the array.
$sql = "SELECT * FROM `notification_table` ";
$resultsd1 = mysqli_query($conn, $sql);
$row = mysqli_fetch_assoc($resultsd1);
$associativeArray = array();
while ($row = mysqli_fetch_assoc($resultsd1))
{
$associativeArray[$row['name']] = $row['price'] ;
}
foreach($associativeArray as $k => $id){
echo $k."=>".$id .' ';
}
And am getting the response like this
name1=>24.725 name2=>24.265
Now i want to add another column in array as well and the name is column is notification_check .
Am not able to get how to add three columns in a single array. Any help will be appreciated.
I want the output like name1=>24.725=>yes_notification name2=>25.43=>no_notification
And when i print_r($row) is show this output Array ( [sno] => 1 [name] => name1 [price] => 23 [notification_check] => yes_notification)
You could shorten this and use mysqli_fetch_all to create an array of all of the data and then manipulate the array using array_column to create the index...
$result = mysqli_fetch_all($resultsd1, MYSQLI_ASSOC);
$associativeArray = array_column($result, null, 'name');

foreach is not working while trying to get students

echo "<pre>"; print_r($jobbrnchesids); exit;
<pre>Array
(
[0] => Array
(
[id_branch] => 6
)
[1] => Array
(
[id_branch] => 1
)
)
From the above array, i am getting job id branches.. Now i am trying to Get the students who are with these branches.
i have tried like this way but it something is going wrong unable to debug can anyone help me out.
$studentBranch = '';
foreach ($jobbrnchesids as $k => $v){
$stuBranch = $conn->query("SELECT student_pid FROM tbl_students
WHERE graduation_branch = ".$v." ");
$studentsWithBranches[] = $stuBranch->fetch_assoc();
}
echo "<pre>"; print_r($studentsWithBranches); exit;
instead of $v it need to be $v['id_branch']
missing array index 'id_branch'
Try:
$stuBranch = $conn->query("SELECT student_pid FROM tbl_students
WHERE graduation_branch = ".$v['id_branch']." ");
Reduce your overhead by doing the following:
$branchIds = array_column($jobbrnchesids,"id_branch");
$result = $conn->query("SELECT student_pid FROM tbl_students
WHERE graduation_branch IN (".implode(",",$branchIds.")");
$studentsWithBranches = $result?$result->fetch_all(MYSQLI_ASSOC):[];
array_column Returns the values from a single column in the input array
$studentBranch = '';
foreach ($jobbrnchesids as $k => $v) {
$stuBranch = $conn->query("SELECT student_pid FROM tbl_students WHERE graduation_branch = '" . ['id_branch'] . "'");
$studentsWithBranches[] = $stuBranch->fetch_assoc();
}
echo "<pre>";
print_r($studentsWithBranches);
exit;

Why is my array coming out like this?

I am querying the DB successfully using an array and I am getting the correct result. But I am having difficulty using the results because of the way the array is created.
Here is the OUTPUT:
Array (
[0] => Array (
[0] => Array (
[0] => 1#1.1
)
[1] => 2#2.2
)
[2] => 3#3.3
)
Here is how the code is generated:
$owners_string = $row['profile_id'];
$owners_stringd = unserialize($owners_string);
foreach ($owners_stringd as $profileid => $valuee) {
if ($valuee) {
$sql = "select email from {$mysql_tbl_pre}profile where profile_id = '$valuee' ";
$err = mysqli_query($estate_db, $sql);
if (!$err)
error_dlg(mysqli_error($estate_db));
elseif (mysqli_num_rows($err) <= 0)
info_dlg("Error");
while ($row = mysqli_fetch_array($err))
$new_array[$profileid] = $row['email'];
$new_array = array($new_array);
foreach ($new_array as $emailvalue)
$emailsd = print_r($emailvalue, true);
} else {
$emailsd = "";
}
}
I know how to implode the results, but when i do implode this result, is comes out as "Array, 1#1.1" (which ever email was last).
I need it to be one entire result such as 1#1.1,2#2.2,3#3.3
These are two separate Tables. The first Tables stores a string of Ids that, the second Tables has each Id in its own row with an email in a separate column.
Solution from the while loop:
while ($thisemail = mysqli_fetch_array($rsz)) {
$emailsd .= $thisemail['email'] . ',';
}
foreach ($emailsd as $emailvalue)
$email = print_r($emailvalue, true);

php getting values out of an array with same 'id' number

I'm having trouble getting the value out of an array
Array
(
[0] => id
[column_name] => id
)
Array
(
[0] => businessType
[column_name] => businessType
)
Array
(
[0] => name
[column_name] => name
)
Array
(
[0] => city
[column_name] => city
)
...
I'm getting those values from
mysql_query("
SELECT column_name
FROM information_schema.columns
WHERE table_name='businessUpgrade'
")
And in my while loop
while($row = mysql_fetch_array($result)){
while($column = mysql_fetch_array($colName)){
if($row[$i] == 1){
//here comes the missing part
}
$i++;
}
}
I tried diffrent things, but according to print_r, the values I need to get have the same number of id (0). Is there any way, I can get the values out of this array.
I found that I should do it with foreach, but somehow everything I try it fails.
There is no need to use 2 while loops.
The $row array is an associative array, so you can use...
$columns = array();
// {query}
while($row = mysql_fetch_array($result)) {
$columns[] = $row['column_name'];
}
var_dump($columns);
Your $columns array now contains an index of all the columns. It's a zero-index, so these can be pulled individually using:
echo $columns[0]; // The first column from the query "id"
echo $columns[2]; // The third column from the query "name"
You can also loop this array as needed.
foreach ($columns as $id => $column) {
if ($id == 0) {
// Do something with the first column:
echo $column;
} elseif ($id == 2) {
// Do something with the third column:
echo $column;
}
}
try this
$res = mysql_query("
SELECT column_name
FROM information_schema.columns
WHERE table_name='businessUpgrade'
");
while($r = mysql_fetch_row($res)){
$arr[]=$r;
}
NOTE . do not use mysql. Try mysqli or PDO instead.
And with this:
while($row = mysql_fetch_array($result)){
while($column = mysql_fetch_assoc($colName)){
if(($column['0'] == $row[$i]) && ($row[$i] == 1)){
//something like this???
}
}
$i++;
}
Your question is a bit messy XD.....i hope this helps anyway.

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