Return Json from Php to Swift Alamofire - php

Question

Hi guys i am using alamofire on a swift 3 iphone program, my problem is that i need to return a value from the php page my problem is that the value that comes back to me is this. How do I make sure that the value I return is: no prova#email.it
I hope I have explained
RETURN VALUE(NOT CORRECT):
SUCCESS: {
message = "no Optional(\"prova#email.it\")";
}
no Optional("prova#email.it")
SWIFT CODE:
import Foundation
import Alamofire
class User{
//URL to our web service
var email=""
var password=""
func PrintValue(){
// print(username);
//print(password);
}
func Login() -> String{
//var ris="";
var readvalue=""
let URLString = "http://localhost/test/login_mobile.php"
let parameters_value: Parameters = [
"email": email,
"password": password
]
//Sending http post request
Alamofire.request(URLString, method: .post, parameters: parameters_value).responseJSON
{
response in
//printing response
print(response)
//getting the json value from the server
if let result = response.result.value {
//converting it as NSDictionary
let jsonData = result as! NSDictionary
//displaying the message in label
readvalue = (jsonData.value(forKey: "message") as! String?)!
print(readvalue)
}
}
return readvalue
}
}
PHP CODE:
<?php
include 'user.php';
header('Content-Type: application/json');
$email= $_POST['email'];
$password = $_POST['password'];
$ris['message']="";
$user = new User();
//procedo con il login
if($user->login($email,$password,"MOBILE")==true){
$ris['message']="yes";
}
else{
$ris['message']="no $email";
}
echo json_encode($ris);
?>

Answer 1

I think it can be done something like:
if let readvalue = jsonData.value(forKey: "message") as? String {
print(readvalue)
}
must print wihtout Optional

Answer 2

Just did this in a playground and it works as expected..
import UIKit
let response: [AnyHashable: Any] = [
"message": "hello world"
]
class MyCoolClass {
func login() {
var readvalue = ""
let jsonData = response as NSDictionary
readvalue = jsonData.value(forKey: "message") as! String
debugPrint("the readvalue is: \(readvalue)")
}
}
let instance = MyCoolClass()
instance.login()
This will print: "the readvalue is: hello world"
The code is not very failsafe...

Answer 3

You need to use nil coalescing to make your value non-optional. e.g. print(readvalue ?? "nil"). Something better would be reengineer your response handling to properly return a typed value or a specific error.