Prepared statement does not match bind variables even though it does? - php

Question

As far as I can tell, I select 6 columns from the table, and I bind 6 variables so why does it tell me that it does not match?
This is for a rating script where people can vote cars.
This script works with the Insert/Select/Union but I noticed that everything was getting really slow when people voted the images from the folder structure so I would like to move the selected images to another folder where they can be accessed faster, however I seem to get a problem when trying to bind the result. This is usually not a problem for me.
Could someone explain to me why this is happening in this particular case ?
Update:
I forgot to include the category variables SORRY they are in the real script just defined up the script... So why all the downvotes? I told you the SQL works- I just tried to improve it.
$cat1 = 1;
$cat2 = 2:
$cat3 = 3;
$stmt = $dbCon->prepare(" INSERT INTO cars_daily ( cars_daily_identifier, cars_daily_source, cars_daily_views, cars_daily_votes, cars_daily_rating, cars_daily_category) "
. " (SELECT cars_car_id, cars_car_source, cars_car_views, cars_car_votes, cars_car_rating, cars_car_category "
. " FROM cars_bcar "
. " WHERE cars_car_category IN (?) ORDER BY RAND() LIMIT 5) "
. " UNION "
. " (SELECT cars_car_id, cars_car_source, cars_car_views, cars_car_votes, cars_car_rating, cars_car_category "
. " FROM cars_car "
. " WHERE cars_car_category IN (?) ORDER BY RAND() LIMIT 5) "
. " UNION "
. " (SELECT cars_car_id, cars_car_source, cars_car_views, cars_car_votes, cars_car_rating, cars_car_category "
. " FROM cars_car "
. " WHERE cars_car_category IN (?) ORDER BY RAND() LIMIT 5) ");
$stmt->bind_param('iii', $cat1, $cat2, $cat3);
if ($stmt->execute()) {
echo "<br><br>";
echo "Success SELECT/INSERT";
echo "<br><br>";
} else {
echo "<br><br>";
print_r($stmt->error);
echo "<br><br>";
echo "Fail SELECT/INSERT";
}
$stmt->bind_result($cars_car_id, $cars_cars_source, $cars_car_views, $cars_car_votes, $cars_car_rating, $cars_car_category);
while ($stmt->fetch()) {
copy("models/$cars_cars_source", "daily/$cars_cars_source");
}

Answer 1

The cause
An INSERT query won't yield records (like a SELECT would) even if the values to be inserted come from a SELECT statement.
A solution
One option is to run the INSERT query and then run a separate SELECT to fetch the values that were inserted.
$selectSQL = " (SELECT cars_car_id, cars_car_source, cars_car_views, cars_car_votes, cars_car_rating, cars_car_category "
. " FROM cars_bcar "
. " WHERE cars_car_category IN (?) ORDER BY RAND() LIMIT 5) "
. " UNION "
. " (SELECT cars_car_id, cars_car_source, cars_car_views, cars_car_votes, cars_car_rating, cars_car_category "
. " FROM cars_car "
. " WHERE cars_car_category IN (?) ORDER BY RAND() LIMIT 5) "
. " UNION "
. " (SELECT cars_car_id, cars_car_source, cars_car_views, cars_car_votes, cars_car_rating, cars_car_category "
. " FROM cars_car "
. " WHERE cars_car_category IN (?) ORDER BY RAND() LIMIT 5) ";
//run the INSERT statement
$stmt = $dbCon->prepare(" INSERT INTO cars_daily ( cars_daily_identifier, cars_daily_source, cars_daily_views, cars_daily_votes, cars_daily_rating, cars_daily_category) " . $selectSQL);
$stmt->bind_param('iii', $cat1, $cat2, $cat3);
if ($stmt->execute()) {
echo "<br><br>";
echo "Success SELECT/INSERT";
echo "<br><br>";
} else {
echo "<br><br>";
print_r($stmt->error);
echo "<br><br>";
echo "Fail SELECT/INSERT";
}
$stmt->close(); //close the prepared statement
//run the SELECT statement
$stmt = $dbCon->prepare($selectSQL);
$stmt->bind_param('iii', $cat1, $cat2, $cat3);
$stmt->execute()
$stmt->bind_result($cars_car_id, $cars_cars_source, $cars_car_views, $cars_car_votes, $cars_car_rating, $cars_car_category);
.