I need help on below statement. I need to put WHERE items.IID = 8 so that it shows only details pertaining to IID number 8. But when I use WHERE items.IID = 8, it is not working. I have to use this type of join as I want to do Sum and Count of some fields. There are 3 tables. 1st is items, 2nd is ItemPurchaseHistory and 3rd is ItemIssuedHistory.
SELECT items.IID, items.ItemName, ItemPurchaseHistorySum.SumOfUnitsPurchased, ItemPurchaseHistorySum.SumOfCost,
ItemPurchaseHistoryCount.CountOfUnitsPurchased,
ItemIssuedHistorySum.SumOfUnitsIssued
FROM items
LEFT JOIN (SELECT IID, SUM(UnitsPurchased) AS SumOfUnitsPurchased, SUM(Cost) AS SumOfCost
FROM ItemPurchaseHistory
GROUP BY IID) ItemPurchaseHistorySum ON ItemPurchaseHistorySum.IID = items.IID
LEFT JOIN (SELECT IID, Count(UnitsPurchased) AS CountOfUnitsPurchased
FROM ItemPurchaseHistory
GROUP BY IID) ItemPurchaseHistoryCount ON ItemPurchaseHistoryCount.IID = items.IID
LEFT JOIN (SELECT IID, SUM(UnitsIssued) AS SumOfUnitsIssued
FROM ItemIssuedHistory
GROUP BY IID) ItemIssuedHistorySum ON ItemIssuedHistorySum.IID = items.IID
WHERE item.IID = $_GET['id']
ORDER BY items.IID ASC
Related
I have 2 tables, borrowers and loans. I want to display on the main page the list of ALL borrowers with or without loans. If with loan, display the newest one.
I have the following sql query, basically it returns the above description except it displays the very first loan of the borrower instead of the latest one.
(Side note: I used GROUP BY to avoid duplicates. Without it the query returns duplicated borrower names if they have multiple loans. Just wanted to know if this is an efficient way of doing so.)
SELECT b.b_id,
b.isdeleted,
b.picture,
b.firstname,
b.middlename,
b.lastname,
b.address,
b.contactno,
b.birthday,
b.businessname,
b.occupation,
b.comaker,
b.comakerno,
b.remarks,
b.datecreated,
b.activeloan,
l.l_id,
l.amount,
l.payable,
l.balance,
l.mode,
l.term,
l.interestrate,
l.amortization,
l.releasedate,
l.duedate,
l.status,
l.c_id
FROM borrowers as b
LEFT JOIN loans as l ON b.b_id = l.b_id
WHERE b.isdeleted = 0
GROUP BY b.b_id
It seems the below query does exactly what i wanted.
I added the below subquery on the "ON" clause.
(SELECT MAX(l_id)
FROM jai_db.loans as l2
WHERE l2.b_id = b.b_id LIMIT 1)
SELECT b.b_id, b.isdeleted, b.picture, b.firstname, b.middlename, b.lastname, b.address, b.contactno,
b.birthday, b.businessname, b.occupation, b.comaker, b.comakerno, b.remarks, b.datecreated, b.activeloan,
l.l_id, l.amount, l.payable, l.balance, l.mode, l.term, l.interestrate, l.amortization,
l.releasedate, l.duedate, l.status, l.c_id
FROM jai_db.borrowers as b
LEFT JOIN jai_db.loans as l
ON l.l_id = (SELECT MAX(l_id)
FROM jai_db.loans as l2
WHERE l2.b_id = b.b_id LIMIT 1)
WHERE b.isdeleted = 0
I have this query
select courses.id, y.qs_world, courses.name_en as name,
courses.description_en as description,
source_link, courses.slug, fee, duration, courses.university_id, college_id,
study_level_id, application_fee, courses.currency_id
from courses
left join university_ranks as y on courses.university_id = y.university_id
and y.year = '2021'
left join universities on courses.university_id = universities.id
left join countries on countries.id = universities.country_id where courses.status = 1
order by ROW_NUMBER() OVER (PARTITION BY countries.id ORDER BY courses.id)
This query is taking too long to execute, but it is working well if I remove the last row.
I used indexing but nothing different.
The EXPLAIN notes are to Using temporary,Using filesort but I want to improve the query without using temporary or filesort
How can I achieve this?
UPDATE:
I tried this query but same speed
SELECT * FROM (
SELECT
`courses`.`id`,`courses`.`status`, `y`.`qs_world`, `courses`.`name_en` as `name`, `courses`.`description_en` as `description`,
`source_link`, `courses`.`slug`, `fee`, `duration`, `courses`.`university_id`, `college_id`,
`study_level_id`, `application_fee`, `courses`.`currency_id`, `countries`.`id` as country_id
FROM
courses
left join `university_ranks` as `y` on `courses`.`university_id` = `y`.`university_id`
and `y`.`year` = '2021'
left join `universities` on `courses`.`university_id` = `universities`.`id`
left join `countries` on `countries`.`id` = `universities`.`country_id`
) UserCourse where status = 1
order by ROW_NUMBER() OVER (PARTITION BY country_id ORDER BY id)
countries.id as country_id --> universities.country_id
then remove
left join `countries` ON `countries`.`id` = `universities`.`country_id`
Move where status = 1 into the inner query.
It seems like
order by ROW_NUMBER() OVER (PARTITION BY country_id ORDER BY id)
could be replaced by
ORDER BY country_id, id
Get rid of the outer query
Don't say LEFT unless the 'right' table might have a missing row. (It confuses the reader as to your intent.)
I'm trying to create a leaderboard but i'm not sure how to do the mysql query.
I would like to count all the levels from a player in the skills table and get the total Level and count all the experience from a player in the experience table and get the Total Exp along with displaying the persons name from the users column.
There is 3 tables factions_mcmmo_users, factions_mcmmo_experience, factions_mcmmo_skills.
This is what i have so far but it doesn't work:
$sql = ("SELECT a.id,
(SELECT COUNT(*) FROM factions_mcmmo_experience WHERE user_id = a.id) as TotalXP,
(SELECT COUNT(*) FROM factions_mcmmo_skills WHERE user_id = a.id) as TotalLevel
FROM (SELECT DISTINCT id FROM factions_mcmmo_users) a LIMIT 10;");
Any help would be very appreciated
EDIT: I have it working now but i'm unsure if its the most efficient way to do things so if anyone could help me out if theres a better way, it would mean a lot.
I would also like to know if it's possible to display the total exp and level with commas if the number is in the thousands for example: total level 5,882 and total xp 582,882
EDIT 2:
I have figured out how to format the numbers but still don't know if my code is efficient
$sql = ("SELECT id, user,
(SELECT FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy),0) FROM factions_mcmmo_skills b WHERE b.user_id = a.id) as TotalLevel,
(SELECT FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy),0) FROM factions_mcmmo_experience c WHERE c.user_id = a.id) as TotalXP
FROM (SELECT id, user FROM factions_mcmmo_users) a group by id ORDER BY TotalLevel DESC, TotalXP DESC LIMIT 10;");
EDIT 3
Updated code from scaisEdge but was displaying everyones level as 1 and XP as 1, so i changed count(*) changed to sum, added an order By TotalLevel in Descending order and that seems to have worked but i can't get it to display the persons name (user column) in the user table? not sure if i was supposed to change to sum because it didn't work the other way.
$sql = ("SELECT a.id, b.TotalXP, c.TotalLevel
FROM (SELECT DISTINCT id FROM factions_mcmmo_users) a
INNER JOIN (
SELECT user_id, Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy) as TotalXP
FROM factions_mcmmo_experience
GROUP By user_id
) b on b.user_id = a.id
INNER JOIN (
SELECT user_id, Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy) as TotalLevel
FROM factions_mcmmo_skills
GROUP by user_id
) c on c.user_id = a.id
ORDER BY TotalLevel DESC
LIMIT 10;");
EDIT 4
Everything working but when i try to format the totals using "FORMAT(Sum(Columns), 0) on the inner joins, the EXP Total appears to work but the main Total Level is not displaying results that are over 1,000 and it breaks the leaderboard positioning, it should be sorting them on total level but it appears to be random, when u remove the format,0 it goes back to working
I would like it to display commas if the number number is the thousands for example: Total Level: 5,532 and Total EXP 5882,882
See live demo: http://mcbuffalo.com/playground/leaderboards/server/factions-mcmmo.php
Updated Code trying to use Format:
$sql = ("SELECT a.id, a.user, b.TotalXP, c.TotalLevel
FROM (SELECT id, user FROM factions_mcmmo_users) a
INNER JOIN (
SELECT user_id, FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy), 0) as TotalXP
FROM factions_mcmmo_experience
GROUP By user_id
) b on b.user_id = a.id
INNER JOIN (
SELECT user_id, FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy), 0) as TotalLevel
FROM factions_mcmmo_skills
GROUP by user_id
) c on c.user_id = a.id
ORDER BY TotalLevel DESC;");
EDIT 5
Changed number with PHP, everything works
Original Images
you could use an couple of inner join
$sql = ("SELECT a.id, a.name, b.TotalXP, c.TotalLevel
FROM (SELECT DISTINCT id, name FROM factions_mcmmo_users) a
INNER JOIN (
SELECT user_id, COUNT(*) as TotalXP
FROM factions_mcmmo_experience
GROUP By user_id
) b on b.user_id = a.id
INNER JOIN (
SELECT user_id, COUNT(*) as TotalLevel
FROM factions_mcmmo_skills
GROUP by user_id
) c on c.user_id = a.id
LIMIT 10
i am using this query to fetching products.the product table has 302,716 rows.it is taking too much time to execute around 2-3 minutes.but when i removed order by it takes less time.
SELECT DISTINCT
product.ProductID,
company.CompanyName
FROM
product
INNER JOIN company
ON company.CompanyID = product.CompanyID
LEFT JOIN company_csv_data
ON company.CompanyID = company_csv_data.CompanyID
LEFT JOIN productcategory
ON product.ProductID = productcategory.ProductID
LEFT JOIN category
ON category.CategoryID = productcategory.CategoryID
LEFT JOIN supplier
ON product.supplier = supplier.id
LEFT JOIN template_vouchers tm
ON product.ProductID = tm.voucher_id
WHERE company.turn_on = 1
AND product.ProductEndDate >= CURRENT_DATE
AND turn_off = 1
GROUP BY product.ProductID
ORDER BY clicks DESC,
product.CodeOpen DESC,
product.Online,
product.EntryDate DESC
LIMIT 0, 15
You could improve the query's speed/performance by creating indexes for the columns in the select and where clauses (this will slow down insert, delete and update statements..)
I'm having a hard time figuring out and trying how to fix this.
Can you help me give a logic or idea how can get the ranking of each category for each branch based on sales?
For example:
Rank 1 for branch_code_id = 9 is Accicular since it has 300,000 sales
Rank 2 for branch_code_id = 9 is WLO since it has only 200,000
sales.
Same as with other branches. I only need the rank of category for each branch_code_id.
I can't figure out how to loop this one. Rank will be placed in the "r" column as you can see in the excel output.
By the way, here's the sql statement i used to get the result you see in the screenshot.
SELECT
a.id,
a.date,
a.branch_code_id,
SUM(b.amount),
c.category
FROM
sales_add_h AS a
INNER JOIN sales_add_i AS b ON a.id = b.sales_h_id
INNER JOIN control_panel_item_create AS c ON b.item_code_id = c.id
GROUP BY c.category, a.branch_code_id, b.amount
ORDER BY SUM(b.amount) DESC
Thanks Guys!
Try this query
SELECT
#rn:=if(#prv=branch_code_id, #rn+1, 1) as rId,
#prv:= branch_code_id as branch_code_id,
val,
id,
date,
category
FROM
(SELECT
a.id,
a.date,
a.branch_code_id,
SUM(b.amount) as val,
c.category
FROM
sales_add_h AS a
INNER JOIN
sales_add_i AS b ON a.id = b.sales_h_id
INNER JOIN
control_panel_item_create AS c ON b.item_code_id = c.id
GROUP BY
c.category, a.branch_code_id, b.amount
ORDER BY
a.branch_code_id, SUM(b.amount) DESC)tmp
JOIN
(SELECT #rn:=0, #prv:=0)t
SQLFIDDLE to understand how ranking works.
I have done ranking for each branch_id as you have mentioned, if you want to rank for each category in a particular branch than you need to add another variable which stores the category and compare it within the if clause and also need to sort data within inner query accordingly order by c.category, a.branch_code_id, SUM(b.amount) DESC