In this case each person can be assigned to an unlimited number of companies. One of these assigned companies should always be the person's main company. As you can see in the SQL query which I have posted the ID of the person's main organization is stored in the column "main_company_id" in the "person" table.
I have database Internal on server 192.168.0.1 with Person_Company Table as given
+----+-----------+------------+------------+
| id | person_id | company_id | created_at |
+----+-----------+------------+------------+
| 1 | 1005 | 2589 | 00:00:00 |
| 2 | 1006 | 2590 | 00:00:00 |
| 3 | 1007 | 2591 | 00:00:00 |
+----+-----------+------------+------------+
Person Table is as given
+------+-------+---------+-----------------+-----------------+
| id | name | phone | main_company_id | ref_id |
+------+-------+---------+-----------------+-----------------+
| 1005 | John | 0123456 | 2590 | 273722702297768 |
| 1006 | Doe | 7894560 | 2591 | 955413080598021 |
| 1007 | Smith | 9517530 | 2589 | 164283934074454 |
+------+-------+---------+-----------------+-----------------+
Company Table is as given
+------+-----------+---------+-----------------+
| id | name | vat | ref_id |
+------+-----------+---------+-----------------+
| 2589 | Company A | 0123456 | 540603005841231 |
| 2590 | Company B | 7894560 | 725472422399397 |
| 2591 | Company C | 9517530 | 367043795528136 |
+------+-----------+---------+-----------------+
Now there is another database External on the same server 192.168.0.1 with External_Person tables as given:
+----+-----------------+-------+----------------------+--------+
| id | ref_id | name | internal_primary_key | gender |
+----+-----------------+-------+----------------------+--------+
| 1 | 273722702297768 | John | ABC123456 | male |
| 2 | 955413080598021 | Doe | BCD456789 | female |
| 3 | 164283934074454 | Smith | DEF789456 | male |
+----+-----------------+-------+----------------------+--------+
And another table on this External database is External_Company
+----+-----------------+-----------+----------------------+
| id | ref_id | name | internal_primary_key |
+----+-----------------+-----------+----------------------+
| 1 | 540603005841231 | Company A | XX4123456 |
| 2 | 725472422399397 | Company B | XX5456789 |
| 3 | 367043795528136 | Company C | XX6789456 |
+----+-----------------+-----------+----------------------+
What I want to achieve is like this result:
+----+------------+-------------+------------------+
| id | person_key | company_key | main_company_key |
+----+------------+-------------+------------------+
| 1 | ABC123456 | XX4123456 | XX5456789 |
| 2 | BCD456789 | XX5456789 | XX6789456 |
| 3 | DEF789456 | XX6789456 | XX4123456 |
+----+------------+-------------+------------------+
I have already achieved two columns through this statement:
SELECT EEP.internal_primary_key as Person_Key, EEC.internal_primary_key as Company_Key
FROM Internal.Person_Company as IPC
JOIN Internal.Person as IP on IP.id = IPC.person_id
JOIN Internal.Company as IC on IC.id = IPC.company_id
JOIN External.External_Person as EEP on IP.ref_id = EEP.ref_id
JOIN External.External_Company as EEC on IC.ref_id = EEC.ref_id
WHERE IPC.person_id = 1005;
And this has the output like this result:
+----+------------+-------------+
| id | person_key | company_key |
+----+------------+-------------+
| 1 | ABC123456 | XX4123456 |
| 2 | BCD456789 | XX5456789 |
| 3 | DEF789456 | XX6789456 |
+----+------------+-------------+
How can I get the main company's internal_primary_key of the person in this given scenario? How can I amend my this existing query to achieve the desired result which I have mentioned above?
Does this work for you? You have a lot of good work, it seems all you would need is add the EEC.internal_primary_key as main_company_key code to your select statement.
SELECT EEP.internal_primary_key as person_Key, EEC.internal_primary_key as company_Key, EEC.internal_primary_key as main_company_key
FROM Internal.Person_Company as IPC
JOIN Internal.Person as IP on IP.id = IPC.person_id
JOIN Internal.Company as IC on IC.id = IPC.company_id
JOIN External.External_Person as EEP on IP.ref_id = EEP.ref_id
JOIN External.External_Company as EEC on IC.ref_id = EEC.ref_id
WHERE IPC.person_id = 1005;
I have done this successfully after doing some research upon databases
SELECT EEP.internal_primary_key as Person_Key, EEC.internal_primary_key as Company_Key, MEEC.internal_primary_key as Main_Company_Key
FROM Internal.Person_Company as IPC
JOIN Internal.Person as IP on IP.id = IPC.person_id
JOIN Internal.Company as IC on IC.id = IPC.company_id
JOIN External.External_Person as EEP on IP.ref_id = EEP.ref_id
JOIN External.External_Company as EEC on IC.ref_id = EEC.ref_id
JOIN Internal.Company as MIC on MIC.id = IP.main_company_id
JOIN External.External_Company as MEEC on MIC.ref_id = MEEC.ref_id
WHERE IPC.person_id = 1005;
And now this results as I wanted:
+----+------------+-------------+------------------+
| id | person_key | company_key | main_company_key |
+----+------------+-------------+------------------+
| 1 | ABC123456 | XX4123456 | XX5456789 |
| 2 | BCD456789 | XX5456789 | XX6789456 |
| 3 | DEF789456 | XX6789456 | XX4123456 |
+----+------------+-------------+------------------+
Related
So I have a table. What it does is it has a count for different users. I want to color code it so that a certain color shows up based on the count for the users. So if the count is 0 it will be green. If the count is 1-2 it will be yellow. If the count is 3+ it will be red. I would like a query that can do this. The current search query for the table is "SELECT * FROM table1 WHERE firstname ='$name'"
+--------------------------------------------------------------------------+
| ID | firstname | lastname | address | count |
| | | | | |
+--------------------------------------------------------------------------+
| 1 | john | doe |james street, idaho, usa | 2 |
| | | | | |
+--------------------------------------------------------------------------+
| 2 | cindy | smith |rollingwood av,lyn, canada| 0 |
| | | | | |
+--------------------------------------------------------------------------+
| 3 | rita | chatsworth |arajo ct, alameda, cali | 1 |
| | | | | |
+--------------------------------------------------------------------------+
| 4 | randy | plies |smith spring, lima, (peru)| 2 |
| | | | | |
+--------------------------------------------------------------------------+
| 5 | Matt | gwalio |park lane, (atlanta), usa | 4 |
| | | | | |
+--------------------------------------------------------------------------+```
Here is the table with the
Am trying to connect two tables Customer and Customer_Usage for getting the result.Tables are showing below.
Table: Customer
+----+-------+-------------+--------+
| id | Ip_Id | Customer_Id | Class |
+----+-------+-------------+--------+
| 1 | 100 | A | First |
| 2 | 100 | B | First |
| 3 | 100 | C | First |
| 4 | 101 | D | First |
| 5 | 101 | E | First |
| 6 | 100 | F | Second |
+----+-------+-------------+--------+
Table: Customer_Usage
+----+-------------+----------------+
| id | Customer_Id | Usage |
+----+-------------+----------------+
| 1 | A | 1245 |
| 2 | B | 4414 |
| 3 | C | 8521 |
| 4 | D | 2314 |
| 5 | E | 521 |
| 6 | F | 5412 |
+----+-------------+----------------+
The condition is while enter a value for search Ip_Id, example for 100 it will give a result like below. How to make a joint for these two tables in Laravel using Mysql
Output result
+-------+-------------+----------------+
| Ip_Id | Customer_Id | Usage |
+-------+-------------+----------------+
| 100 | A | 1245 |
| 100 | B | 4414 |
| 100 | C | 8521 |
| 100 | F | 5412 |
+-------+-------------+----------------+
This is the query am trying.
$result = DB::table('Customer')
->where('Ip_Id','=','100')
->get();
Left join is recommended to achieve what you need.
DB::table('Customer')
->select('Customer.Ip_Id','Customer.Customer_Id','Customer_Usage.Usage')
->leftJoin('Customer_Usage', 'Customer_Usage.Customer_Id', '=', 'Customer.Customer_Id')
->where('Customer.Ip_Id',100)
->get();
Use Eloquent Inner Join like:
$results = DB::table('Customer')
->select('Customer.Ip_Id','Customer.Customer_Id', 'Customer_Usage.Usage')
->join('Customer_Usage','Customer.Customer_Id', '=','Customer_Usage.Customer_Id')
->where('Ip_Id', 100)
->get();
You will get the desired output like above.
I have two tables one for units and one for Amenities
Table units
+---------+---------------------+---------------------+-----------+----------+
| unit_id | date added | date modified | unit name | user |
+---------+---------------------+---------------------+-----------+----------+
| 1 | 2001-10-29 13:11:00 | 2001-10-29 13:11:00 | Villa 1 | Smith |
| 2 | 2001-10-29 13:11:00 | 2001-10-29 13:11:00 | Villa 2 | Smith |
| 3 | 2001-10-29 13:11:00 | 2001-10-29 13:11:00 | Villa 3 | Jones |
| 4 | 2001-10-29 13:11:00 | 2001-10-29 13:11:00 | Apartment | Smith |
+---------+---------------------+---------------------+-----------+----------+
Table Amenities
+---------+-----------+-------------------+
| id | Unit_id | Amenity |
+---------+-----------+-------------------+
| 1 | 1 | Air conditions |
| 2 | 1 | Internet |
| 3 | 1 | Water heaters |
| 4 | 1 | TV |
| 5 | 2 | TV |
| 6 | 2 | pool |
| 7 | 2 | Internet |
| 8 | 3 | Internet |
| 9 | 4 | Internet |
+---------+-----------+-------------------+
i want to select units where it has both TV and Internet
I try
select units.* from units left join Amenities on units.unit_id=Amenities.Unit_id
where Amenities.Amenity='TV' and Amenities.Amenity='Internet'
but not work
DROP TABLE IF EXISTS amenities;
CREATE TABLE amenities
(unit_id INT NOT NULL
,amenity VARCHAR(50) NOT NULL
,PRIMARY KEY(unit_id,amenity)
);
INSERT INTO amenities VALUES
(1,'Air conditions'),
(1,'Internet'),
(1,'Water heaters'),
(1,'TV'),
(2,'TV'),
(2,'pool'),
(2,'Internet'),
(3,'Internet'),
(4,'Internet');
SELECT unit_id
FROM amenities
WHERE amenity IN ('TV','Internet')
GROUP
BY unit_id
HAVING COUNT(*) = 2;
+---------+
| unit_id |
+---------+
| 1 |
| 2 |
+---------+
Obviously, you'd never have a table like the one you describe. Instead, you'd have a table of unit, a table of amenities, and a table which says which amenity belongs to which unit.
SELECT ua.*
FROM units AS ua
INNER JOIN units AS ub ON ua.unit_id = ub.unit_id
INNER JOIN Amenities AS aa
ON ua.unit_id = aa.Unit_id
AND aa.Amenity = 'TV'
INNER JOIN Amenities AS ab
ON ub.unit_id = ab.Unit_id
AND ab.Amenity = 'Internet';
Here's the output generated with your data:
+---------+---------------------+---------------------+-----------+-------+
| unit_id | date added | date modified | unit name | user |
+---------+---------------------+---------------------+-----------+-------+
| 1 | 2001-10-29 13:11:00 | 2001-10-29 13:11:00 | Villa 1 | Smith |
| 2 | 2001-10-29 13:11:00 | 2001-10-29 13:11:00 | Villa 2 | Smith |
+---------+---------------------+---------------------+-----------+-------+
I have three tables below that shows the student records, subjects and students with subjects.
I would like to ask what is the effective SQL query to show the results below. I can show it using JOIN but not with the format below.
+------+-----------+-----------+-----+----------+-----------+--------+
| Name | Address | Telephone | Sex | Subjects | Teacher | Active |
+------+-----------+-----------+-----+----------+-----------+--------+
| John | somewhere | 12345 | M | | Teacher 1 | YES |
| John | somewhere | 12345 | M | Math | | YES |
| John | somewhere | 12345 | M | Science | | YES |
| John | somewhere | 12345 | M | English | | YES |
| Matt | somewhere | 123456 | M | | Teacher 2 | YES |
| Matt | somewhere | 23456 | M | Math | | YES |
| Matt | somewhere | 123456 | M | Science | | YES |
| Girl | somewhere | 5431 | F | | Teacher3 | YES |
| Girl | somewhere | 5431 | F | Physics | | YES |
| Girl | somewhere | 5431 | F | Math | | YES |
+------+-----------+-----------+-----+----------+-----------+--------+
select * from student_record;
+------------+------+-----------------+-----------+-----+----------+--------+
| id_student | name | address | telephone | sex | teacher | active |
+------------+------+-----------------+-----------+-----+----------+--------+
| 1 | John | Somewhere | 12345 | M | Teacher | 0 |
| 2 | Matt | Somewhere There | 12345222 | M | Teacher1 | 0 |
| 3 | Girl | Somewhere here | 3333 | F | Teacher2 | 0 |
+------------+------+-----------------+-----------+-----+----------+--------+
select * from subjects;
+------------+--------------+---------------------+
| id_subject | subject_name | subject_description |
+------------+--------------+---------------------+
| 1 | Math | Math |
| 2 | Science | Science |
| 3 | English | English |
| 4 | Physics | Physics |
+------------+--------------+---------------------+
select * from with_subjects;
+--------------------+--------------------+------------+
| id_student_subject | student_id_subject | student_id |
+--------------------+--------------------+------------+
| 1 | 1 | 1 |
| 2 | 2 | 1 |
| 3 | 3 | 1 |
| 4 | 4 | 1 |
| 5 | 4 | 2 |
| 6 | 3 | 2 |
| 8 | 1 | 2 |
| 9 | 1 | 3 |
| 10 | 2 | 3 |
| 11 | 3 | 3 |
| 12 | 4 | 3 |
+--------------------+--------------------+------------+
how about
select a.name as "Name",a.address as "Address",a.telephone as "Telephone" ,a.sex as "Sex",null as "Subject",a.teacher as "Teacher",a.active as "Active" from student_record as a
union a.name as "Name",a.address as "Address",a.telephone as "Telephone" ,a.sex as "Sex",b.subject_name as "Subject",null as "Teacher",a.active as "Active" from (student_record as a inner join with_subjects as c on a.id_student = c.student_id) inner join subjects as b on c.student_id_subject = b.id_subject
Not tested it. It wotn be in the same order as your example, but should have all of the data there
I am having the following tables in my DB
PROJECTS
+----+-------------------------------------------+
| id | name |
+----+-------------------------------------------+
| 1 | YANNONALI COURT |
| 2 | UNIVERSITY OF COLORARDO DENVER RESEARCH 2 |
| 3 | G.R.E.A.T PROGRAM DESALTER BUILDING |
| 4 | MONARCH CLUB |
| 5 | LAFAYETTE MERCANTILE |
| 6 | CAMELBACK VILLAGE RAQUET AND HEALTH CLUB |
| 7 | BACK COUNTRY |
| 8 | URBAN CRASHPAD |
| 9 | PRIVATE RESIDENCE |
| 10 | EATON RESIDENCE |
+----+-------------------------------------------+
PROJECT_ASSIGNMENTS(WHERE projects.id=project_assignment.target_id)
+-------+-----------+-------------+
| id | target_id | property_id |
+-------+-----------+-------------+
| 19178 | 1 | 48 |
| 19192 | 1 | 39 |
| 19391 | 1 | 3 |
| 19412 | 2 | 3 |
| 19591 | 2 | 34 |
| 19610 | 2 | 34 |
| 21013 | 3 | 2 |
| 21032 | 3 | 2 |
| 30876 | 4 | 2433 |
| 38424 | 5 | 2580 |
+-------+-----------+-------------+
PROPERTIES(WHERE properties.id= project_assignment.property_id)
+----+------------------+
| id | name |
+----+------------------+
| 2 | Residential |
| 3 | Multi Family |
| 34 | New Construction |
| 39 | Contemporary |
| 48 | Southwest |
+----+------------------+
I want O/P ordered by no.of projects in the list...
Residential(177) //12 - total no.of projects which is having this property
Multi Family(15)
New Construction(13)
Contemporary(11)
please give me some MySQL queries
Thank You
This should do the trick:
select
c.name,
count(c.id) as CountOfProperties
from
projects a,
project_assignments b,
properties c
where
a.ID=b.target_id
and b.property_id=c.ID
group by
c.name
order by
count(c.id) desc;
Try this::
select
prop.name,
count(prop.id) as CountOfProperties
from
projects p
inner join project_assignments pa on (p.ID=pa.target_id)
inner join properties prop on (pa.property_id=prop.ID)
group by
prop.name
order by
count(prop.id) desc;