$prepStatement->execute(array_values($inv)); does not work - php

Question

i can't find the solution.
$prepStatement->execute(array_values($inv)); does not work
I got an error at this line.
my php script:
<?php
$response=array();
$json = $_REQUEST['json'];
$data = json_decode($json);
var_dump(json_decode($json, true));
print "Starting request". "<br/>";
if($_SERVER['REQUEST_METHOD'] == "POST" && (json_last_error() === JSON_ERROR_NONE))
{
if($data->connection && $data->wykazy)
{
print "connection and wykazy exist". "<br/>";
if ($data->connection->Host && $data->connection->db && $data->connection->User && $data->connection->password) {
print "connection Host, db, User, password are OK". "<br/>";
try
{
$opt = [
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION,
PDO::ATTR_DEFAULT_FETCH_MODE => PDO::FETCH_ASSOC,
PDO::ATTR_EMULATE_PREPARES => false,
];
$dbObj = new PDO('mysql:host='.$data->connection->Host.';dbname='.$data->connection->db, $data->connection->User, $data->connection->password, $opt);
print "Proba ustanowienia polaczenia! Bledy: " . $dbObj->errorCode() . "<br/>";
createWykaz($dbObj, $data);
}
catch (PDOException $e)
{
print "Blad podczas tworzeniu obiektu dbObj!: " . $e->getMessage() . "<br/>";
$response["success"]=0;
$response["message"]="Can not connect to database!: " . $e->getMessage();
echo json_encode($response);
die();
}
//$mysqli = new mysqli($data->connection->Host, $data->connection->User, $data->connection->password, $data->connection->db);
}
}
else
{
print "connection i wykazy nie istnieją! " . "<br/>";
$response["success"]=0;
$response["message"]="Error: Required fields are missing!";
echo json_encode($response);
}
}
function createWykaz($dbObj, $data)
{
try{
$allowedVariables = array(
'wyk_ilosc',
'wyk_czasod',
'wyk_czasdo',
'wyk_id_czynnosc',
'wyk_id_pracownik',
'wyk_id_partia',
'wyk_status',
);
$sql = "insert into wykaz (". implode(',', $allowedVariables) .")";
$sql.= " VALUES (". substr(str_repeat('?,', sizeof($allowedVariables)), 0, -1) .");";
print "sql: ". $sql . "<br/>";
if($prepStatement = $dbObj->prepare($sql)){
//edit
$dbObj->beginTransaction();
foreach ( $data->wykazy as $inv ) {
$res = $prepStatement->execute(array_values($inv));
}
/*
$prepStatement = $dbObj->prepare($sql)
foreach ($data->wykazy as $row) {
$dbObj->executeMultiple($prepStatement, $row);//return DB_OK
}
*/
$response["success"]=1;
$response["message"]="Wszystkie wykazy successfully added to Database!";
echo json_encode($response);
$dbObj->commit();
}
else {
$response["success"]=0;
$response["message"]="Błąd podczas przygotowania zapytania!"+ $prepStatement;
echo json_encode($response);
}
$dbObj=null;
$prepStatement=null;
}catch(PDOException $e){
//Error handling goes here
echo "Sorry, the website is experiencing problems.";
echo "Error: Our query failed to execute and here is why: \n";
echo "Query: " . $sql . "\n";
echo "Errno: " . $e->getMessage() . "\n";
$response["success"]=0;
$response["message"]="Our query failed to execute!". $e->getMessage();
echo json_encode($response);
$dbObj=null;
$prepStatement=null;
}
}
?>
it works till:
$prepStatement->execute(array_values($inv));
I am getting an error at this position, but $data->wykazy is an array.
I can change my code to:
$sth = $db->prepare('INSERT INTO numbers VALUES (?, ?, ?)');
foreach ($alldata as $row) {
$db->execute($sth, $row);
}
but I will try the other way.
Thanks for help
Sebastian
The output from Postman:
Postman part1
Postman part2