IE11 and input type="number" - php

Question

I have a form with input type="number" which is giving me problems in IE11: some values are accepted and some others are not, apparently randomly.
Here's the code:
<input type="number" style="text-align:right" min="1.00" placeholder="1,00" name="value-name" id="value" step="0.01" title="title" required/>
For some reason IE11 accepts 9.2, 9.4, 9.5, 9.6, 9.7, 9.9 but refuses 9.3 and 9.8. This is just an example, it's happening with all numbers and I'm not understanding the reason behind it. Moreover some numbers were accepted some minutes ago but now they aren't anymore.
In addition to this, all of the previous values should not be valid because I'm in Europe and , is the delimiter for the decimal part, not .. Instead, when I use ,, IE does not traslates it to . and, when passed to PHP through a POST, PHP's is_numeric() returns false!
How can I make all of this work? Thanks

Answer 1

I fixed this by accepting both . and , as decimal dividers.
I added the attributes formnovalidate lang="en" to the form input and performed the form validation through Javascript, with the following code:
function validateForm(minValue) {
var number = document.getElementById("value").value.replace(",",".");
if(number != "") {
var isNaNres = isNaN(parseFloat(number));
var isFiniteRes = isFinite(number);
if (!isNaNres && isFiniteRes && number >= minValue && number.match("^[0-9]+(\.[0-9]{1,2})?$"))
return true;
}
alert("<Error message>");
return false;
}
The regular expression match was needed to guarantee that the number had at maximum 2 decimal places