I've try several times for dropdownlist validation,
my codes are in PHP and HTML, the the validation part is not working though and i've refer some of the solutions in stackoverflow which has similar case like mine.
Declare variable
$call_department = $db->escape((int)$_POST['call_department']); //where i declare this variable
HTML files
<tr><td>Department</td><td><select name='call_department'>
<option></option>
<?php $call_dept = $db->get_results("select type_id,type_name from site_types where type=1 order by type_name;");
foreach ($call_dept as $dept )
{?>
<option value='<?php echo $dept->type_id;?>'><?php echo $dept->type_name; required?></option>
<?php } ?>
</select></td></tr>
Validation part:
<?php
if(isset($_REQUEST['call_department']) && $_REQUEST['call_department'] == '0') {
echo 'Please select a department.';
}
?>
1) Set first option value="0" like this
<option value="0">select</option>
2) Required attribute should be set to select tag not to option tag <select name='call_department' required>
<select name='call_department' required>
<option value="0">select</option>
<?php $call_dept = $db->get_results("select type_id,type_name from site_types where type=1 order by type_name;");
foreach ($call_dept as $dept )
{
?>
<option value='<?php echo $dept->type_id;?>'><?php echo $dept->type_name; ?></option>
<?php } ?>
</select>
Related
I'm having a hard time to fix and how can make my codes work well.
My textbox echo correctly while my dropdown box is not.
Can anyone help me and also clean my codes?
I wanna know how did you do it and can u please explain it to me.
Thank you so much.
index.php
<?php include 'test.php' ?>
<form method="post" action="index.php">
Textbox: <input type="text" name="txt1" value="<?php echo $txt1;?>">
Dropdown: <select name="drpdown1" value="<?php echo $drpdown1;?>">
<option></option>
<option value="1">Mark</option>
<option value="2">Extreme</option>
</select>
<input type="submit" name="btn1">
</form>
test.php
<?php
$txt1 = "";
$drpdown1 = "";
if ($_SERVER["REQUEST_METHOD"] == "POST") {
$txt1 = $_POST["txt1"];
$drpdown1 = $_POST["drpdown1"];
}
?>
You're not echoing the value of $drpdown1 correctly:
// this is wrong for a select:
<select name="drpdown1" value="<?php echo $drpdown1;?>">
// etc.
If you want to select automatically the previously selected value, you need to add the selected attribute:
<select name="drpdown1">
<option value="1" <?php if ($drpdown1 === '1') { echo "selected='selected'"; } ?>>Mark</option>
<option value="2" <?php if ($drpdown1 === '2') { echo "selected='selected'"; } ?>>Extreme</option>
// etc.
you have to know more about the dropdown box because you can not put the value inside the
<select value="<?php echo $drpdown1;?>">
you have to compare the value inside the option directly. example
<select name="drpdown1">
<?php
if($drpdown1 == ""){
?>
<option selected></option>
<option value="1">Mark</option>
<option value="2">Extreme</option>
<?php
}else if($drpdown1 == "1"){
?>
<option></option>
<option value="1" selected>Mark</option>
<option value="2">Extreme</option>
<?php
}
?>
</select>
Hi I have a stored value in mysql from a select box. When i call a edit page I would like the select box to populate with the value i have stored in mysql
$taskCompany = $mysqli->real_escape_string($_POST['taskCompany']); This returns 1
<select id="taskCompany" required name="taskCompany" class="form-control">
<option value="" disabled selected>Select a Company</option>
<option value="1">building</option>
<option value="2">maintenace</option>
</select></div>
I would like the select box to show the correct option when loading the edit page. I do not store any select option in the database values or text just the value that is select when job was created.
Thanks Jon
I'd I have understood correctly, you have he value/values in your MySQL database and you want them to be shown in your drop down list:
You could do it like:
<option value = "1" <?php if($taskCompany == 1) echo "select='selected'";?>>building</option>
Or if you have the names coming from the database too.
<select id="taskCompany" required name="taskCompany" class="form-control">
<option>SELECT</option>
<?php
$res = musql_query("SELECT * FROM yourtablename");
while($row = mysql_fetch_array($res))
{
$taskCompany = $row['taskCompany'];
$co_name = $row['taskCompanyName'];
?>
<option value = "<?php echo $taskCompany; ?>" ><?php echo co_name; ?></option>
<?php } ?>
Here I have used $co_name to be displayed as a name assuming that you have building, maintenance etc stored in your database.
This is for the time being, as I wanted to demonstrate but Please
consider mysqli/PDO as mysql_* is deprecated.
<?php $taskCompany = $mysqli->real_escape_string($_POST['taskCompany']); ?>
<select id="taskCompany" required name="taskCompany" class="form-control">
<option value="" disabled selected>Select a Company</option>
<option value="1" <?php if($taskCompany == 1) echo "selected='selected'"; ?>>building</option>
<option value="2" <?php if($taskCompany == 2) echo "selected='selected'"; ?>>maintenace</option>
</select></div>
You can do this
<?php foreach($taskCompany as $row){ ?>
<option value="unique id for select options">name for select options</option>
<?php } ?>
Good afternoon,
Using cakephp, how can I select a value in a select box in an update operation?
in the view I get the variables like this for example:
<?php $category = $itemEditar['Anuncio']['category']; ?>
and I need to select an option from a select box:
<select id="select_category" name="enquiry">
<option value="" >selecione</option>
<option value="Category1">Categoria1</option>
<option value="Category2">Categoria2</option>
<option value="Category3">Categoria2</option>
</select>
to be an update operation, I need to mark the category that was saved in the database, and am not getting how to do this.
You want to check the $category against each or the options and if they match set the selected attribute .
<select id="select_category" name="enquiry">
<option value="" >selecione</option>
<option<?= $category == "Category1"?" selected = 'selected'":"" ?> value="Category1">Categoria1</option>
<option<?= $category == "Category2"?" selected = 'selected'":"" ?> value="Category2">Categoria2</option>
<option<?= $category == "Category3"?" selected = 'selected'":"" ?> value="Category3">Categoria2</option>
</select>
the correct answer is:
<select id="select_category" name="enquiry" >
<option value="Category1" <?php echo $category == "Category1"?" selected = 'selected'":"" ?> >Categoria1</option>
<option value="Category2" <?php echo $category == "Category2"?" selected = 'selected'":"" ?> >Categoria2</option>
<option value="Category3" <?php echo $category == "Category3"?" selected = 'selected'":"" ?> >Categoria2</option>
</select>
I have this code:
if(isset($_POST['search']))
{
$res1=mysql_query("SELECT * FROM aircraft where acode = '$_POST[ac]'") or die(mysql_error());
while($row=mysql_fetch_array($res1))
{
$airc=$row['acode'];
$amode=$row['amodel'];
$stat=$row['status'];
$rem=$row['remarks'];
echo "<center><table><form name=\"frmMain\" method=\"post\">
<tr><td><font face=consolas><b>Aircraft Code:</b></font></td><td><input type=text name=arc value='$airc' readonly=readonly></td></tr>
<tr><td><font face=consolas><b>Aircraft Model:*</b></font></td><td><input type=text name=am value='$amode'></td></tr>
<tr><td><font face=consolas><b>Status:*</b></font></td><td><input type=text name=st value='$stat'></td></tr>
<tr><td><font face=consolas><b>Remarks:*</b></font></td><td><input type=text name=rm value='$rem'></td></tr></table>";
}
}
On submit 'search' button, this code displays the data from aircraft table. The user is allowed to update the data with the (*) sign.
Since the Status are the following by default (Available, Not Available), I changed this
<tr><td><font face=consolas><b>Status:*</b></font></td><td><input type=text name=st value='$stat'></td></tr>
to this,
<tr><td><font face=consolas><b>Status:*</b></font></td><td><select name=st>
<option value=Available>Available</option>
<option value='Not Available'>Not Available</option>
</select></td></tr>
But I want the dropdown to have it's default value depending on
$stat=$row['status']; since this is an update form.
If the data being retrieved has it's status 'Available', then the dropdown should have it's default value as 'Available'.
How can I achieve that? I tried <select name=status value='$stat'> but it doesn't work. Any help will be appreciated. Thanks!
Just put selected="selected" on the option depending on your $row['status'],
<option selected="selected" value="available">Available</option>
write Available and Unavailable into an array
$theArray = array("Available","Not Available");
loop the array:
<tr><td><font face=consolas><b>Status:*</b></font></td><td><select name=st>
<?php
foreach ($theArray as $key => $value) {
if ($value == $stat) {
echo('<option selected="selected" value='.$value.'>'.$value.'</option>');
} else {
echo('<option value='.$value.'>'.$value.'</option>');
}
}
?>
</select></td></tr>
and in each loop we check if the value in the array, is the same as it is in the variable, if so, we put the selected there
understand the logic?
<select name=status>
<option value="available" <?php if($row['status']=="available") echo "selected=\"selected\""; ?>>Available</option>
<option value="unavailable" <?php if($row['status']=="unavailable") echo "selected=\"selected\""; ?>>Unvailable</option>
</select>
Basically echo selected="selected" for the option depending on value of the concerned field.
<?php
$status = "navail";
?>
<select name="sel">
<option value="avail" <?php if($status == "avail") echo "SELECTED";?> > Avail </option>
<option value="navail" <?php if($status == "navail") echo "SELECTED";?> > Navail </option>
</select>
You can define your variable value with additional option tag and mark that as selected like:
<select name="role" id="role">
<!-- This is default define value using php variable $r -->
<option selected="selected" value="<?php echo $r; ?>" disabled="disabled"><?php echo $r; ?></option>
<!-- Other options values -->
<option value="2">Option-2</option>
<option value="2">Option-2</option>
</select>
You can set the selected dropdown option from database as below:
<select name="status">
<option <?php echo ($row['status'] == 'Available') ? 'selected' : '' ?> value='Available'>Available</option>
<option <?php echo ($row['status'] == 'Not Available') ? 'selected' : '' ?> value='Not Available'>Not Available</option>
</select>
Declare the options in an array like
$arr = array("available" => "available","unavailable" => "unavailable");
and input the drop down like this
echo form_dropdown("st", $arr, set_value("st", (isset($row['status'];) ? $row['status']; : ""))
This is the method commonly used in frameworks like codeigniter.. i think it works in core php too..
its my first time here though and i tried using basic principles in php, dont know if this helps you but if you're trying to grab the defaulted value which you inputted on your database then edit it again i suggest you try this one
<select name="st">
<?php if($row['status']=="Available"){?><option value="Available">Available</option><?php }?>
<?php if($row['status']=="Unavailable"){?><option value="Unavailable">Unavailable</option><?php }?>
</select>
Assuming that the column name in your database is 'status', give it a try works for me
Im trying to implement the search feature in my website.
when the search keyword is entered in the textbox, and the category combo is selected, the form will be Posted and the result will be shown on the same page.
what i want is to keep the selected category of the combo by default in the form after posted
For eg., If i select the category 'Automobiles' in the combo and click search, after form submit, the combo should show the automobiles as default selected option. Please help me. Any help will be appreciated
I assume you get categories from database.
you should try:
<?php
$categories = $rows; //array from database
foreach($rows as $row){
if($row['name'] == $_POST['category']){
$isSelected = ' selected="selected"'; // if the option submited in form is as same as this row we add the selected tag
} else {
$isSelected = ''; // else we remove any tag
}
echo "<option value='".$row['id']."'".$isSelected.">".$row['name']."</option>";
}
?>
Assuming that by "combo" you mean "A regular select element rendering as a drop down menu or list box" and not "A combobox that is a combination of a drop down menu and free text input":
When outputting the <option> elements, check the value against the submitted data in $_POST / $_GET and output selected (in HTML) or selected="selected" (in XHTML) as an attribute of the option element.
Here is the JQuery way I am using.
<select name="name" id="name">
<option value="a">a</option>
<option value="b">b</option>
</select>
<script type="text/javascript">
$("#name").val("<?php echo $_POST['name'];?>");
</script>
But this is only if you have jquery included in your webpage.
Regards
<?php
$example = $_POST["friend"];
?>
<form method="POST">
<select name="friend">
<option value="tom" <?php if (isset($example) && $example=="tom") echo ' selected';?>>Thomas Finnegan</option>
<option value="anna" <?php if (isset($example) && $example=="anna") echo ' selected';?>>Anna Karenina</option>
</select>
<br><br>
<input type="submit">
</form>
This solved my problem.
This Solved my Problem. Thanks for all those answered
<select name="name" id="name">
<option value="a">a</option>
<option value="b">b</option>
</select>
<script type="text/javascript">
document.getElementById('name').value = "<?php echo $_GET['name'];?>";
</script>
$countries_uid = $_POST['countries_uid'];
while($row = mysql_fetch_array($result)){
$uid = $row['uid'];
$country = $row['country_name'];
$isSelected = null;
if(!empty($countries_uid)){
foreach($countries_uid as $country_uid){//cycle through country_uid
if($row['uid'] == $country_uid){
$isSelected = 'selected="selected"'; // if the option submited in form is as same as this row we add the selected
}
}
}else {
$isSelected = ''; // else we remove any tag
}
echo "<option value='".$uid."'".$isSelected.">".$country."</option>";
}
this is my solutions of multiple select dropdown box after modifying Mihai Iorga codes
After trying al this "solves" nothing work. Did some research on w3school before and remember there was explanation of keeping values about radio. But it also works for Select option. See here an example. Just try it out and play with it.
<?php
$example = $_POST["example"];
?>
<form method="post">
<select name="example">
<option <?php if (isset($example) && $example=="a") echo "selected";?>>a</option>
<option <?php if (isset($example) && $example=="b") echo "selected";?>>b</option>
<option <?php if (isset($example) && $example=="c") echo "selected";?>>c</option>
</select>
<input type="submit" name="submit" value="submit" />
</form>
Easy solution:
If select box values fetched from DB then to keep selected value after form submit OR form POST
<select name="country" id="country">
<?php $countries = $wpdb->get_results( 'SELECT * FROM countries' ); ?>
<option value="">
<?php if(isset($_POST['country'])){echo htmlentities($_POST['country']); } else { echo "Select Country *"; }?>
</option>
<?php foreach($countries as $country){ ?>
<option <?php echo ($_POST['country'] == $country->country_name ? 'selected="selected"':''); ?> value="<?php echo $country->country_name; ?>"><?php echo $country->country_name; ?>
</option>
<?php } ?>
</select>