How I See my Result in Select from Where MYSQL using PHP? - php

Question

I have this code, i try to call my data from table database mysql , but didn't see any result. always go to else , not go to the process. what would i do?
<?php
require('connectDB.php');
$nama = $_GET['nama'];
echo $nama;
$query = "SELECT * FROM pesan
WHERE nama = '%" . mysqli_real_escape_string($connection, $nama) . "%'
";
$results = mysqli_query($connection, $query);
$baris = mysqli_num_rows($results);
if (!$results) {
die('Invalid query: ' . mysql_error());
}
if ( $baris > 0) {
while($row = mysqli_fetch_assoc($results)) {
?>
<h3>Nama Mobil : <?php echo $row['mobil'] ?></h3>
<h3>ID Pembelian : <?php echo $row['id']; ?></h3>
<h3>Nama anda : <?php echo $row['nama']; ?></h3>
<h3>Alamat : <?php echo $row['alamat']; ?></h3>
<h3>Tanggal Masuk : <?php echo $row['tgl_masuk']; ?></h3>
<?php
}
}else{
echo "error";
}
?>
What wrong with my code?
Thanks!
im sorry , this is my ConnectDB.php , i include in my html.
<?php
$connection = mysqli_connect('localhost', 'root', '', 'dealermobil');
if (!$connection){
die("Database Connection Failed" . mysqli_error());
}
// $db = new PDO ('mysql:host=localhost;dbname=db_login;charset=utf8mb4','root','');
?>

Answer 1

Your connection check and result check is incorrect.
$connection = mysqli_connect('localhost', 'root', '', 'dealermobil');
if (!$connection){
die("Database Connection Failed" . mysqli_connect_error());
}
Also
$results = mysqli_query($connection, $query);
$baris = mysqli_num_rows($results);
if (!$results) {
die('Invalid query: ' . mysqli_error($connection));
}

Answer 2

use this you are using = it should be LIKE when you are trying to search a field in database.
$query = "SELECT * FROM `pesan` WHERE `nama` LIKE '%". mysqli_real_escape_string($connection, $nama) ."%'";