Why mySQL table won't export properly as HTML table - php

Question

I use bootstrap 3 template and connect to a mysql database, sort the table and export some datas as HTML table in order to display it on bootstrap webpage.
Here is the mySQL look like :
The following code won't get expected results:
<div class="well">
<?php
//MySQL Database Connect
include '/includes/dbconnect.php';
$result = mysqli_query($conn,"SELECT * FROM webpilot ORDER BY NEXT_EVENT ASC");
if(mysqli_num_rows($result) >= 1) {
echo '<table class="table table-striped table-bordered table-hover">';
echo "<tr><th>ID</th><th>NAME:</th><th>EPOCH</th></tr>";
while($row = mysqli_fetch_array($results)) {
echo "<tr><td>";
echo $row['ID'];
echo "</td><td>";
echo $row['NAME'];
echo "</td><td>";
echo $row['NEXT_EVENT'];
echo "</td></tr>";
}
echo "</table>";
}
?>
</div> <!-- well -->
dbconnect.php :
<?php
$localhost="xxx.xx.xxx.com";
$username="dboxxxxxxx";
$password="xxxxxx";
$database="dbxxxxxx";
$conn = mysqli_connect($localhost,$username,$password,$database);
//test if connection failed
if(mysqli_connect_errno()){
die("connection failed: "
. mysqli_connect_error()
. " (" . mysqli_connect_errno()
. ")");
}
?>
original page link can be found here : http://s529471052.onlinehome.fr/bs3/gpio/dyntable.htm

Answer 1

Its just a simple typo
$result = mysqli_query($conn,"SELECT * FROM webpilot ORDER BY NEXT_EVENT ASC");
if(mysqli_num_rows($result) >= 1) {
echo '<table class="table table-striped table-bordered table-hover">';
echo "<tr><th>ID</th><th>NAME:</th><th>EPOCH</th></tr>";
//while($row = mysqli_fetch_array($results)) {
^^^^^^^^
while($row = mysqli_fetch_array($result)) {
While testing Add
ini_set('display_errors', 1);
ini_set('log_errors',1);
error_reporting(E_ALL);
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT); `
to the top of your script. This will force any mysqli_ errors to
generate an Exception that you can see on the browser and other errors will also be visible on your browser.
Answer for additional info provided in a comment
From your comment below, it appears you are trying to run PHP code from a web page with a .htm extension. That wont work unless you have configured Apache to do this
Change the web page file name to have a .php extension and then Apache will pass the PHP code to the PHP interpreter for compilation and execution.

Answer 2

$result = mysqli_query($conn,"SELECT ID, NAME, NEXT_EVENT FROM webpilot ORDER BY NEXT_EVENT ASC");
$table = '<table>
<tr>
<th>ID</th>
<th>NAME</th>
<th>EPOCH</th>
</tr>';
if($result ) {
while ($row = mysqli_fetch_assoc($result)) {
$table .= '<tr>
<td>'. $row['ID'] .'</td>
<td>'. $row['NAME'] .'</td>
<td>'. $row['NEXT_EVENT'] .'</td>
</tr>';
}
} else {
$table .= '<tr><td colspan="3">No date found</td></tr>';
}
$table .= '</table>';
echo $table;
Try this, This will help for your requirement.

Answer 3

I'm assuming that your connection to the database is OK (though the given page link suggests otherwise).
It seems the table is not exporting properly because $result was misspelled as $results in the code segment printing the data rows: $row = mysqli_fetch_array($results).
Try the modification below (also refactored for better readability):
<div class="well">
<?php
//MySQL Database Connect
include '/includes/dbconnect.php';
$result = mysqli_query($conn,"SELECT * FROM webpilot ORDER BY NEXT_EVENT ASC");
if(mysqli_num_rows($result) >= 1)
{
echo '<table class="table table-striped table-bordered table-hover">';
echo "<tr><th>ID</th><th>NAME:</th><th>EPOCH</th></tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>$row['ID']</td>";
echo "<td>$row['NAME']</td>";
echo "<td>$row['NEXT_EVENT']</td>";
echo "</tr>";
}
echo "</table>";
}
?>
</div> <!-- well -->
Also, you may want to check that $results and $row contain the expected data in the expected formats using print_r($results) and print_r($row).