I want to echo an img every time $i increases, but it only echos the last $i.
for($i=0; $i<=5;$i++)
$sql="SELECT DISTINCT id, Make FROM sve WHERE id='".$i."'";
$rezult=mysqli_query($db, $sql);
$red=mysqli_fetch_object($rezult);
echo "<img src='brend/brend$red->id.png' class='imgbrend' strana='".$red->Make."'/>";
You can use MySQL's IN or BETWEEN keywords, rather than using a for loop and then iterate over the result set.
Your query becomes something like this:
SELECT DISTINCT id, Make FROM sve WHERE id BETWEEN 0 AND 5
Then you need a loop like so:
while ($red = mysqli_fetch_object($rezult)) {
echo "<img src='brend/brend" . $red->id . ".png' class='imgbrend' strana='" . $red->Make . "'/>";
}
Full code:
$sql = "SELECT DISTINCT id, Make FROM sve WHERE id BETWEEN 0 AND 5";
$rezult = mysqli_query($db, $sql);
while ($red = mysqli_fetch_object($rezult)) {
echo "<img src='brend/brend" . $red->id . ".png' class='imgbrend' strana='" . $red->Make . "'/>";
}
Related
In mysql I want to display matched information with values... But the code I use select information separately and I get a bad result. What I want is to wrap the "select" functions together so they both look for specific information in mysql database.
Here's the code I use:
$name = explode(',',$name); //splits search
$query = "SELECT * FROM lucky WHERE name LIKE '%" . implode("%' AND name LIKE '%", $name) . "%'";
$sname = explode(',',$sname); //splits search
$query = "SELECT * FROM lucky WHERE sname LIKE '%" . implode("%' AND sname LIKE '%", $sname) . "%'";
$result = $mysqli->query($query);
while($row = $result->fetch_assoc()) {
echo "<table id='box'>";
echo "<tr;>";
echo "<td id='text''>Name:</td><td id='haha'>" . $row['name']. "</td>";
echo "<td id='text'>Second Name:</td><td id='haha'>" . $row['sname'] . "</td>";
echo "</tr;>";
echo "</table>";
} else { echo "No mathed information" ; }
Thanks in advance :)
UPADATE
Thanks to Spencer for his help!!!
Here's the code that I use now. Please use this to select matched information from the database!!!
$query = SELECT *
FROM lucky
WHERE name LIKE '$name'
AND sname LIKE '$sname'
$result = $mysqli->query($query);
while($row = $result->fetch_assoc()) {
echo "<table id='box'>";
echo "<tr;>";
echo "<td id='text''>Name:</td><td id='haha'>" . $row['name']. "</td>";
echo "<td id='text'>Second Name:</td><td id='haha'>" . $row['sname'] . "</td>";
echo "</tr;>";
echo "</table>";
} else { echo "No mathed information" ; }
If your $sname string contains the value "jack,jill", then the query would only return rows that have a name column value that contains both of those strings, for example: 'jack and jill' and 'jillojellojacko' would match. But the query will not return rows where the name column contains 'jack' but doesn't contain 'jill'.
If your intent is to search for rows that have either of the values matching, for example
$name = 'fee,fi,fo'
$sname = 'fum'
That is, any rows where name column contains either 'fee', or 'fi', or 'fo', or sname column contains 'fum', you could use a query of the form:
SELECT t.*
FROM lucky t
WHERE t.name LIKE '%fee%'
OR t.name LIKE '%fi%'
OR t.name LIKE '%fo%'
OR t.sname LIKE '%fum%'
If you replace all those ORs with ANDs, then a row will need to satisfy all of those predicates to be returned. If you want a combination of AND and OR, then use parens to specify the order of precedence...
i'm trying to find a solution to make my php script show only the last 3 entries in a row but all i can find is how to show the first entries not the last 3. any ideas?
this is the script that shows the entries:
<?php
// Grab the data from our people table
$sql = "select * from people";
$result = mysql_query($sql) or die ("Could not access DB: " . mysql_error());
while ($row = mysql_fetch_assoc($result)) {
echo "<div class=\"picture\">";
echo "<p>";
// Note that we are building our src string using the filename from the database
echo "<img src=\"content/uploads/" . $row['filename'] . "\" alt=\"\" /><br />";
echo $row['fname'] . " " . "<br />" . "<br />" . $row['lname'] . "<br />";
echo "</p>";
echo "</div>";
}
?>
try this
$sql = "SELECT * FROM people ORDER BY id DESC LIMIT 3";
id=>is your column name you you might have to change this
and dont use mysql function as they are depricated and soon going to be dropped. Learn mysqli or PDO
Just do reverse ORDER BY, ie. if your table is ordered by column id, then do ORDER BY id DESC and then use LIMIT 3:
$sql = "select * from people ORDER BY id DESC LIMIT 3";
And PS, mysql_* are deprecated...
I have a table with two collumns (shortened), NAME and CATEGORY.
I want to output the number of distinct categorys. For an examle: Sport : 5 , Houses : 10.
I use this one:
$test = mysqli_query($con,"SELECT category, COUNT(category) as count FROM tablename GROUP BY category ORDER BY count DESC");
This work then I run the code in SQL Shell, but I have no clue on how to output it in PHP. I have searced Google up and down without any successfull solution.
Any help?
I want to output it in a table format.
EDIT: Here is my full code: (tablename is changed, and $con is removed)
$test = mysqli_query($con,"SELECT DISTINCT lkategori, COUNT(lkategori) as count FROM tablename GROUP BY lkategori ORDER BY count DESC");
while($row = mysql_fetch_array($test)) {
echo $row['lkategori'] . ":" . $row['count'];
die("test");
}
$test = mysqli_query($con,"SELECT DISTINCT lkategori, COUNT(lkategori) as count FROM tablename GROUP BY lkategori ORDER BY count DESC");
echo "<table border='1'>";
while($row = mysqli_fetch_array($test)) {
echo "<tr>";
echo "<td>" . $row['lkategori'] . "</td>";
echo "<td>" . $row['count'] . "</td>";
echo "</tr>";
}
echo "</table>";
This will output all the categories and the count returned by the sql statement into a table. Also as a sidenote you should look into PDO.
EDIT: to make sure you do get the distinct values you should use the DISTINCT keyword in your sql statement:
$test = mysqli_query($con,"SELECT DISTINCT category, COUNT(category) as count FROM tablename GROUP BY category ORDER BY count DESC");
use this
while($row = mysqli_fetch_array($test)) {
echo $row['lkategori'] . ":" . $row['count'];
die("test");
}
Thanks
I have had a long road to get to this last question. Everything is my code is working now, but I can't get this last little issue. Right now I have:
$sql = "SELECT phonenumber,email, dataplan AS currentplan, SUM(datamb) AS
value_sum FROM maindata GROUP BY phonenumber, dataplan";
$result = mysql_query($sql);
$row = mysql_fetch_assoc($result);
$val = $row["value_sum"];
$plan = $row["currentplan"];
$remain = $plan - $val;
if (!$result) {
echo "Could not successfully run query ($sql) from DB: " . mysql_error();
exit;
}
if (mysql_num_rows($result) == 0) {
echo "No rows found, nothing to print so am exiting";
exit;
}
It only subtracts the first value as opposed to the values for all. displayed like this:
while ($row = mysql_fetch_assoc($result)){
echo "<tr>";
echo "<td>".$row['phonenumber'] . "</td> ";
echo "<td>".$row['currentplan'] . "</td> ";
echo "<td>".ROUND ($row["value_sum"],2) . "MB</td> ";
echo "<td>".$remain . " MB</td> ";
echo "<td>".$row['email'] . "</td></tr>";
}
So my goal is to subtract all value_sums from all dataplans, but what I have now, gives me the first value for all columns. Thank you!
mysql_fetch_assoc() will always get one row. You can use it in loop, or better use PDO, eg. like this:
$sql = "SELECT phonenumber,email, dataplan AS currentplan, SUM(datamb) AS
value_sum FROM maindata GROUP BY phonenumber, dataplan";
$results = $pdo->query($sql);
You can read about creating PDO connections here http://www.php.net/manual/en/book.pdo.php
I have a MySQL database called "bookfeather" with several tables that contain list books. Under each table, each book has a given number of votes. The PHP code below allows the user to enter in a book title ($entry), and then returns the total number of votes that book has in all tables ($sum).
How could I use PHP to make a 2-column, 25-row table that lists the 25 books in the database with the highest value for $sum (in descending order)?
Thanks in advance,
John
mysql_connect("mysqlv10", "username", "password") or die(mysql_error());
mysql_select_db("bookfeather") or die(mysql_error());
// We preform a bit of filtering
$entry = strip_tags($entry);
$entry = trim ($entry);
$entry = mysql_real_escape_string($entry);
$result = mysql_query("SHOW TABLES FROM bookfeather")
or die(mysql_error());
$table_list = array();
while(list($table)= mysql_fetch_row($result))
{
$sqlA = "SELECT COUNT(*) FROM `$table` WHERE `site` LIKE '$entry'";
$resA = mysql_query($sqlA) or die("$sqlA:".mysql_error());
list($isThere) = mysql_fetch_row($resA);
$isThere = intval($isThere);
if ($isThere)
{
$table_list[] = $table;
}
}
//$r=mysql_query("SELECT * , votes_up - votes_down AS effective_vote FROM `$table[0]` ORDER BY effective_vote DESC");
if(mysql_num_rows($resA)>0){
foreach ($table_list as $table) {
$sql = "SELECT votes_up FROM `$table` WHERE `site` LIKE '$entry'";
$sql1 = mysql_query($sql) or die("$sql:".mysql_error());
while ($row = mysql_fetch_assoc($sql1)) {
$votes[$table] = $row['votes_up'];
$sum += $row['votes_up'];
//echo $table . ': "' . $row['votes_up'] . " for $entry from $table\"<br />";
}
}
}
else{
print "<p class=\"topic2\">the book \"$entry\" has not been added to any category</p>\n";
}
//within your loop over the DB rows
//$votes[$table] = $row['votes_up'];
//afterwards
if($sum>0){
print "<table class=\"navbarb\">\n";
print "<tr>";
print "<td class='sitenameb'>".'<a type="amzn" category="books" class="links2b">'.$entry.'</a>'."</td>";
print "</tr>\n";
print "</table>\n";
//echo "<p class=\"topic3\">".''.$entry.''. "</p>\n";
echo "<p class=\"topic4\">". number_format($sum) . ' votes in total.'."</p>\n";
Try something like this. All of this hasn't been tested so please add comments for changes. I'll work with you to get the code right.
// After getting your array of tables formated like
$tableArray = array("`tableA`", "`tableB`", "`tableC`");
// create a table statement
$tableStatement = implode(", ", $tableArray);
// create a join statement
$joinStatement = "";
for ($i = 1; $i < count($tableArray); $i++) {
if ($joinStatement != "")
$joinStatement .= " AND ";
$joinStatement .= $tableArray[0] . ".site = " . $tableArray[$i] . ".site"
}
$firstTable = $tableArray[0];
$sql = "SELECT SUM(votes_up) FROM " . $tableStatement . " WHERE " . $joinStatement . " AND " . $firstTable . ".site LIKE '" . $entry . "' GROUP BY " . $firstTable . ".site ORDER BY SUM(votes_up) DESC";
Edit --------
I now realize that the query above won't work perfectly because votes_up will be ambiguous. Also because you probably want to be doing joins that grab records that are only in one table. I think the concept is the right direction even though the query may not be perfect.
You can do something like
$selectStatement = "SUM(tableA.votes_up) + SUM(tableB.votes_up) as total_votes_up"
I did something like this recently. In your database, you'll have to rename each field to a corresponding book name.php like (TaleofTwoCities.php). Now on your page that will display the vote results, you'll need to include some php files that will drive the database query on each load. I called mine "engine1.php" and "engine2.php." These will do all your sorting for you.
$query1 = mysql_fetch_row(mysql_query("SELECT url FROM pages ORDER BY counter DESC
LIMIT 0,1"));
$query2 = mysql_fetch_row(mysql_query("SELECT url FROM pages ORDER BY counter DESC
LIMIT 1,1"));
$query3 = mysql_fetch_row(mysql_query("SELECT url FROM pages ORDER BY counter DESC
LIMIT 2,1"));
and so on.. then..
$num1 = "$query1[0]";
$num2 = "$query2[0]";
$num3 = "$query3[0]";
That part sorts your listings by the number of votes from highest to lowest, with url, in your case, being the name of the books(remember you want it to end in .php - you'll see why in a second), and counter being the field that logs your votes.
Make your second engine.php file and add something like this:
$vquery1 = mysql_fetch_row(mysql_query("SELECT counter FROM pages WHERE
url='book1.php'"));
$vquery2 = mysql_fetch_row(mysql_query("SELECT counter FROM pages WHERE
url='book2.php'"));
$vnum1 = "$vquery1[0]";
$vnum2 = "$vquery2[0]";
and so on... Until you get to 25 for both this and engine 1.
Now, in your results page, after you put in the require_once(engine.php) and require_once(engine2.php) at the start of your body, start an HTML table. You only want two columns, so it'll be something like..
<table border=1 cellspacing=0 cellpadding=0>
<tr>
<?php include $num1; ?>
</tr>
<tr>
<?php include $num2; ?>
</tr>
And so on... By naming your field with "book1.php" and including the engines, $num1 will change to a different .php file depending on votes from high to low. Now all you have to do is make small php files for each book like so - no headers or anything because you're inserting it into the middle of html code already:
<td style="width:650px;"><center><img src="images/book1.jpg" alt="" border="none"
/></a></center></td>
<td style="width:150px;">Votes: <?php echo $vnum1;?></td>
And there you have it. A code that will dynamically give you results from high to low depending on the number of votes each book has.