I am trying to create a json response using a for loop and a function but I can't seem to get it to work correctly. How would this be done?
PHP
$count = 0;
foreach ($bookings as $booking){
$item = get_users_custom($user,$count);
$item[$count]['booking_id']=$booking->id;
$count++;
}
echo $item;
function get_users_custom($user,$count=0){
$feed[$count]['user_id']=$user->id;
return $feed;
}
PHP json_encode() function converts a PHP value into a JSON value. For example, from a PHP array, it can create a JSON representation of that array.
$count = 0;
foreach ($bookings as $booking){
$item = get_users_custom($user,$count);
$item[$count]['booking_id']=$booking->id;
$count++;
}
echo json_encode($item);
function get_users_custom($user,$count=0){
$feed[$count]['user_id']=$user->id;
return $feed;
}
You should create a simple php array and the convert it to JSON using json_encode()
https://www.w3schools.com/js/js_json_php.asp
Related
I need to generate a JSON Object and push it to a JSON object array using PHP.
This is my code.
public function getJSONData()
{
$csv = $this->getCsvData();
$finalArray = array();
// First foreach to iterate the data array.
foreach ($csv["data"] as $key => $value) {
// Second foreach to iterate the headlines array.
$newArray = array();
foreach ($csv["headlines"] as $index => $headline) {
// $newArray[$key]->$csv["headlines"] = $value;
// print_r($headline);
// print_r($value[$index]);
// echo " ";
array_push($newArray, array($headline => $value[$index]));
}
echo json_encode($newArray);
echo "<br>";
array_push($finalArray, json_encode($newArray));
}
// dd($finalArray);
}
From this code, I'm getting the following response.
[{"ID":12348},{"Status":1},{"Manufacturere_ID":101},{"Famiy_matchcode":"101-iphone-11"},{"Name":"iPhone 11"},{"Price":639.95}]
[{"ID":12348},{"Status":1},{"Manufacturere_ID":101},{"Famiy_matchcode":"101-iphone-11"},{"Name":"iPhone 11"},{"Price":509.95}]
[{"ID":12348},{"Status":1},{"Manufacturere_ID":101},{"Famiy_matchcode":"101-iphone-11"},{"Name":"iPhone 11"},{"Price":349.95}]
[{"ID":12349},{"Status":1},{"Manufacturere_ID":101},{"Famiy_matchcode":"101-iphone-11"},{"Name":"iPhone 11"},{"Price":639.95}]
[{"ID":12349},{"Status":1},{"Manufacturere_ID":101},{"Famiy_matchcode":"101-iphone-11"},{"Name":"iPhone 11"},{"Price":509.95}]
[{"ID":12349},{"Status":1},{"Manufacturere_ID":101},{"Famiy_matchcode":"101-iphone-11"},{"Name":"iPhone 11"},{"Price":349.95}]
[{"ID":12350},{"Status":1},{"Manufacturere_ID":101},{"Famiy_matchcode":"101-iphone-11"},{"Name":"iPhone 11"},{"Price":639.95}]
[{"ID":12350},{"Status":1},{"Manufacturere_ID":101},{"Famiy_matchcode":"101-iphone-11"},{"Name":"iPhone 11"},{"Price":509.95}]
But it is not a valid JSON and I really need to get an output like this:
[{"ID":12348,"Status":1,"Manufacturere_ID":101,"Famiy_matchcode":"101-iphone-11","Name":"iPhone 11","Price":639.95}, {"ID":12348,"Status":1,"Manufacturere_ID":101,"Famiy_matchcode":"101-iphone-11","Name":"iPhone 11","Price":509.95}]
This is a standard JSON object array.
In my code, I'm using array_push($newArray, array($headline => $value[$index])); to generate the array and take it as JSON.
Please help me on this.
You seem to be creating arrays and adding json data in several places, build the data as a normal array and then encode the result...
// Foreach to iterate the data array.
foreach ($csv["data"] as $key => $value) {
// Combine headers with data and add to final result
$finalArray[] = array_combine($csv["headlines"], $value);
}
echo json_encode($finalArray);
i want to print data which is coming from api when i print data it print only one data at a time how to print all these data in foreach loop i am using this but not work and getting and error Trying to get property 'Name' of non-object how to solve this problems thanks in advance
this is the response
this is my code
$response = sabreApiCall($url, $data_array);
$results = json_decode($response);
$i =0;
foreach ($results->GeoSearchRS->GeoSearchResults->GeoSearchResult[$i] as $hotel)
{
echo $hotel->Name;
$i ++;
}
}
Just return $results as laravel will return it as json.
why are you using $i variable to loop through this array. Simply use foreach like this
$response = sabreApiCall($url, $data_array);
$results = json_decode($response);
foreach ($results->GeoSearchRS->GeoSearchResults->GeoSearchResult as $hotel)
{
echo $hotel->Name;
}
}
I need json response in different array, but below code not give all the result.
while ($row=mysqli_fetch_assoc($result))
{
//$data[]=$row;
$data['id']=$row['id'];
$data['name']=$row['name'];
$data['Latitude']=$row['Latitude'];
$data['Longitude']=$row['Latitude'];
$lat_user=$row['Latitude'];
$long_user=$row['Longitude'];
$res=file_get_contents("https://maps.googleapis.com/maps/api/distancematrix/json".
"?units=imperial&origins=$lat,$long&destinations=$latuser,$longuser");
$json_res=json_decode($res);
$data['time']=$json_res->{'rows'}{0}->{'elements'}{0}->{'duration'}->{'text'};
}
echo json_encode($data,true);
You need to save your items into some array, e.g $dataArray at the end of each iteration and after cycle use this array to create json
$dataArray = array();
while ($row=mysqli_fetch_assoc($result))
{
//$data[]=$row;
$data['id']=$row['id'];
$data['name']=$row['name'];
$data['Latitude']=$row['Latitude'];
$data['Longitude']=$row['Latitude'];
$lat_user=$row['Latitude'];
$long_user=$row['Longitude'];
$res=file_get_contents("https://maps.googleapis.com/maps/api/distancematrix/json".
"?units=imperial&origins=$lat,$long&destinations=$latuser,$longuser");
$json_res=json_decode($res);
$data['time']=$json_res->{'rows'}{0}->{'elements'}{0}->{'duration'}->{'text'};
$dataArray[] = $data;
}
echo json_encode($dataArray,true);
I have a JSON with the Following structure.
{
"1":{"Itemname":"dtfg","unitprice":"12","Qty":"4","price":"$48.00"},
"2":{"Itemname":"kjh","unitprice":"45","Qty":"7","price":"$315.00"},
"3":{"Itemname":"yjk","unitprice":"76","Qty":"8","price":"$608.00"},
"4":{"Itemname":"hgj","unitprice":"4","Qty":"45","price":"$180.00"}
}
I need the Itemname to be made into a PHP array, Unitprice into another one, Qty to another one and price to another one. How do I do that?
$getArray = get_object_vars(json_decode($json));
print_r($getArray);
echo $getArray[1]->Itemname;
echo $getArray[1]->unitprice;
you require get_object_vars as well for achieving your requirement.
<?php
$json =<<<JSONLIVES
{
"1":{"Itemname":"dtfg","unitprice":"12","Qty":"4","price":"$48.00"},
"2":{"Itemname":"kjh","unitprice":"45","Qty":"7","price":"$315.00"},
"3":{"Itemname":"yjk","unitprice":"76","Qty":"8","price":"$608.00"},
"4":{"Itemname":"hgj","unitprice":"4","Qty":"45","price":"$180.00"}
}
JSONLIVES;
$items = json_decode($json, TRUE);
$item_names = array();
foreach($items as $key => $item) {
$item_names[] = $item['Itemname'];
}
Or Php >= 5.5
print_r(array_column($items, 'Itemname'));
You need a function called json_decode() to convert your json data into PHP array
$json = {
"1":{"Itemname":"dtfg","unitprice":"12","Qty":"4","price":"$48.00"},
"2":{"Itemname":"kjh","unitprice":"45","Qty":"7","price":"$315.00"},
"3":{"Itemname":"yjk","unitprice":"76","Qty":"8","price":"$608.00"},
"4":{"Itemname":"hgj","unitprice":"4","Qty":"45","price":"$180.00"}
};
var_dump(json_decode($json));
You need to decode your Json by PHP's json_decode()
$decodeJson will return object then you can read Itemname and other values by using $val->Itemname in foreach loop
$json = '{
"1":{"Itemname":"dtfg","unitprice":"12","Qty":"4","price":"$48.00"},
"2":{"Itemname":"kjh","unitprice":"45","Qty":"7","price":"$315.00"},
"3":{"Itemname":"yjk","unitprice":"76","Qty":"8","price":"$608.00"},
"4":{"Itemname":"hgj","unitprice":"4","Qty":"45","price":"$180.00"}
}';
$decodeJson = json_decode($json);
foreach($decodeJson as $key=>$val) {
print_r($val);
}
Live Json decode
Try that:
$json = json_decode($json);
foreach($json as $obj){
echo $obj->name;
.....
}
After some research, I found out that the most efficientt way that solves my problem here would be to do like the following.
$cash=json_decode($new_json, true);
echo $arr3[1]['Itemname'];
echo $arr3[1]['unitprice'];
:
:
and so on.
This can be put into loops easily, fetched into HTML text-fields (as I want here in this scenario) and so on.
I am newbee in php and trying to get json in array and wanna change key in that json below is my code :
$json = json_decode(file_get_contents('all_json_files/jobs.json'), true);
foreach ($json as $key=>$row){
foreach ( $row as $key=>$row){
foreach ( $row as $key=>$row){
foreach ($row as $key=>$row){
if(strcmp($key,"security_block")==0)
{
foreach ($row as $k=>$r){
if(strcmp($k,"job_payload_hash")==0)
{
$row[$k]['job_payload_hash']=$base64String;
print_r($row);
}
}
}
}
}
}
}
print_r($json);
Issue is print_r($row); is updating properly but print_r($json); does not print the updated string .
If the key could appear anywhere, the answer is pretty simple:
function update_hash(&$item, $key, $base64String)
{
if ($key == "job_payload_hash") {
$item = $base64String;
}
}
array_walk_recursive($json, 'update_hash', 'something');
Update
The structure is something different that previously assumed; while the above will work, probably the below is a more direct approach:
foreach (array_keys($json['jobs']) as $jobId) {
$json['jobs'][$jobId]['job']['security_block']['job_payload_hash'] = 'something';
}
You use $key & $row variable in multiple time. for this reason, value of $key is changed each time, so parent loop does not work..
You can use recursive function lik answer of #Ja͢ck .
this is because you have to save not in variables you defined after => in a foreach.
You have to store this in format:
$json[0][0] ... = $base64String;
OR
You have to add a new array like $result = array() before you write the foreach and then store it in $result.
Decode the JSON string using json_decode(), edit your resulting array, then use json_encode(); to return the array to a JSON encoded string.
Also, use array_key_exists() rather than comparing array key strings.
$array = json_decode($json);
if(array_key_exists("job_payload_hash", $array){
$array["job_payload_hash"] = base64encode($var);
}
$json = json_encode($array);