So I made my first database online. I used phpmyadmin, I created the table and the user.
Now I'd like to show the table on a page of my site, as well as giving the possibility to people to edit the database from the site.
My problem is that the database does not work: it doesn't connect. I have no idea what to do.
My database is called letstenf_santi and my table passeggeri.
This is the code I'm trying to use to show the table on the site.
<?php
//establishing connection
mysql_connect('localhost', 'root', '');
//selecting a database
mysql_select_db('letstenf_santi');
$sql = 'SELECT * FROM `letstenf_santi`.`passeggeri`';
$records=mysql_query($sql);
?>
<html>
<head>
<title>mostra</title>
</head>
<body>
<table width="300" border="1" cellpadding="10" cellspacing="1">
<tr>
<th>id pass</th>
<th>nome</th>
<th>eta</th>
<th>sesso</th>
</tr>
<?php
while($pass=mysql_fetch_assoc($records)){
echo "<tr>";
echo "<td>".$pass['idpasseggero']."</td>";
echo "<td>".$pass['nome']."</td>";
echo "<td>".$pass['eta']."</td>";
echo "<td>".$pass['sesso']."</td>";
echo "</tr>";
}
?>
</table>
</body>
</html>
instead of this,
mysql_connect('localhost', 'root', '');
mysql_select_db('letstenf_santi');
you can try this,
$connection=mysql_connect('localhost', 'root', '');
$db=mysql_select_db('letstenf_santi',$connection);
try this code
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "letstenf_santi";//your db name
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$sql = "SELECT * FROM tablename";//replace table name with your table name
$result = mysqli_query($conn, $sql); ?>
<html>
<head>
<title>mostra</title>
</head>
<body>
<table width="300" border="1" cellpadding="10" cellspacing="1">
<tr>
<th>id pass</th>
<th>nome</th>
<th>eta</th>
<th>sesso</th>
</tr>
<?php if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
echo "<tr>";
echo "<td>".$row['idpasseggero']."</td>";
echo "<td>".$row['nome']."</td>";
echo "<td>".$row['eta']."</td>";
echo "<td>".$row['sesso']."</td>";
echo "</tr>";
}
} else {
echo "0 results";
}
mysqli_close($conn);
?>
</table>
</body>
</html>
Related
I tried to add a delete "button"(link to file with function) it should delete a row from the database, but it didn't work. I looked for tutorials and answers on forums but found nothing how solve for my problem.
<td>Delete</td>
link from code:
The link works correctly, but when I tried to delete it just doesn't want to take 'commentId' variable and go back to test.php page
Table on website:
dbh.inc.php
<?php
$serverName = "localhost";
$dBUsername = "root";
$dBPassword = "";
$dBName = "php-login";
$conn = mysqli_connect($serverName, $dBUsername, $dBPassword, $dBName);
if (!$conn){
die("connection failed: " . mysqli_connect_error());
}
test.php
<?php
include_once 'header.php';
include "includes/dbh.inc.php";
include 'includes/test.inc.php';
?>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0/css/bootstrap.min.css" integrity="sha384-Gn5384xqQ1aoWXA+058RXPxPg6fy4IWvTNh0E263XmFcJlSAwiGgFAW/dAiS6JXm" crossorigin="anonymous">
</head>
<body>
<div class="container">
<div class="box">
<h4 class="display-4 text-center">Comments</h4><br>
<?php if (isset($_GET['success'])) { ?>
<div class="alert alert-success" role="alert">
<?php echo $_GET['success']; ?>
</div>
<?php } ?>
<table class="table table-striped">
<thead>
<tr>
<th scope="col">#</th>
<th scope="col">Username</th>
<th scope="col">Comment</th>
<th scope="col">Action</th>
</tr>
</thead>
<?php
$i=0;
while($row = mysqli_fetch_array($result)) {
?>
<td><?php echo $row["commentId"]; ?></td>
<td><?php echo $row["usersUid"]; ?></td>
<td><?php echo $row["comment"]; ?></td>
<td>Delete</td>
</tr>
<?php
$i++;
}
?>
</table>
</div>
</div>
</body>
</html>
test.inc.php
<?php
include "dbh.inc.php";
$sql = "SELECT * FROM commenttb ORDER BY commentId DESC";
$result = mysqli_query($conn, $sql);
delete.inc.php
<?php
include "dbh.inc.php";
if(isset($_GET['commentId'])) {
$id = $_GET['commentId'];
$delete = "DELETE FROM `commenttb` WHERE `commentId` ='$id'";
$result = mysqli_query($conn, $delete);
if ($result) {
header("Location: ../test.php?success=successfully deleted");
} else {
header("Location: ../test.php?error=unknown error occurred");
}
}else {
header("Location: ../test.php?error=smth gone wrong");
}
If I press on the link "delete" it should take 'commentId' variable from row e.g. 5 and by SQL query from delete.inc.php file delete row with this id from my database
I tried change $_Get to $_POST and add method="POST" to link on delete.inc.php file, but it didn't work
I have managed to take information from my database of the website, however I have no idea how to present the results in a table and how to style it. I tried putting <table> outside of the whole PHP, clearly did not work. I tried echoing a <table> tag before the result echo and a closing </table> tag after it, but that did not do it. This is the code I am working with:
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "onlib";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
//Takes all the results from the table with genre 5.
$sql = "SELECT name, description, content FROM books WHERE genre='5'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<span style='color:white;'>"."<br> Name: ".$row["name"]."<br> Description: ".$row["description"]."<br> Content: ".$row["content"] ."<br>"."</p>";
}
} else {
echo "0 results";
}
$conn->close();
?>
I am still new in PHP, trying to understand how the whole thing works. Thanks in advance!
<?php
function tableV1 ($row) {
echo '<tr>';
echo '<td>' . $row['name'] . '</td>';
echo '<td>' . $row['description'] . '</td>';
echo '<td>' . $row['content'] . '</td>';
echo '</tr>';
}
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "onlib";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); }
?>
Always do Database Connection first, before Outputting anything, that way, you can create custom error message to show instead of a failed database conntection or no content at all.
<style type="text/css">
table {}
tbody {}
td {}
th {}
thead {}
tr {}
</style>
Style is used inside the <head></head> to style the table, CSS it's called.
<table>
<thead>
<th>Name</th>
<th>Description</th>
<th>Content</th>
</thead>
<tbody>
<?php
// Takes all the results from the table with genre 5.
$sql = "SELECT name, description, content FROM books WHERE genre='5'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// Output data of each row
while($row = $result->fetch_assoc()) {
tableV1($row);
}
} else {
echo '<tr><td colspan="3">0 results</td></tr>';
}
?>
</tbody>
</table>
Output contents from database.
<?php
$conn->close();
?>
Close database connection in the end. All together:
<?php
function tableV1 ($row) {
echo '<tr>';
echo '<td>' . $row['name'] . '</td>';
echo '<td>' . $row['description'] . '</td>';
echo '<td>' . $row['content'] . '</td>';
echo '</tr>';
}
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "onlib";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); }
?>
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8" />
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<title>Page Title</title>
<meta name="viewport" content="width=device-width, initial-scale=1">
<style type="text/css">
table {}
tbody {}
td {}
th {}
thead {}
tr {}
</style>
</head>
<body>
<table>
<thead>
<th>Name</th>
<th>Description</th>
<th>Content</th>
</thead>
<tbody>
<?php
// Takes all the results from the table with genre 5.
$sql = "SELECT name, description, content FROM books WHERE genre='5'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// Output data of each row
while($row = $result->fetch_assoc()) {
tableV1($row);
}
} else {
echo '<tr><td colspan="3">0 results</td></tr>';
}
?>
</tbody>
</table>
</body>
</html>
<?php
$conn->close();
?>
Try this:
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "onlib";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
//Takes all the results from the table with genre 5.
$sql = "SELECT name, description, content FROM books WHERE genre='5'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
echo "<table>";
echo "<thead>
<tr>
<th>Name</th>
<th>Description</th>
</tr>
</thead>";
echo "<tbody>";
while($row = $result->fetch_assoc()) {
echo "<tr>";
echo "<td>".$row["name"]."</td>";
echo "<td>".$row["description"]."</td>";
echo "</tr>";
}
echo "</table>";
} else {
echo "0 results";
}
$conn->close();
?>
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "onlib";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
//Takes all the results from the table with genre 5.
$sql = "SELECT name, description, content FROM books WHERE genre='5'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
echo '<table>';
echo '<tr><td>Name</td><td>Description</td><td>Content</td></tr>'
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<tr><td>".$row["name"]."</td><td>".$row["description"]."</td><td>".$row["content"] ."</td></tr>";
}
echo '</table>';
} else {
echo "0 results";
}
$conn->close();
?>
The basic table format is this
for example:
<table>
<tr>
<td>row 1 item 1</td>
<td>row 1 item 2</td>
</tr>
<tr>
<td>row 2 item 1</td>
<td>row 2 item 2</td>
</tr>
</table>
so try:
if ($result->num_rows > 0) {
echo "<table>";
while($row = $result->fetch_assoc()) {
echo "<tr>";
echo "<td>".$row["name"]."</td>";
echo "<td>".$row["description"]."</td>";
echo "<td>".$row["content"]."</td>";
echo "</tr>";
}
echo "</table>";
} else {
echo "0 results";
}
Try this approach:
[... some HTML header and code ...]
<table>
<thead>
<tr><th>Name</th><th>Description</th><th>Content</th></tr>
</thead>
<tbody>
<?php
[ ... extract something from the database ...]
while($row = $result->fetch_assoc())
{
echo "<tr><td>$row[name]</td><td>$row[description]</td><td>Content</td></tr>\n";
}
}
?>
</tbody>
</table>
[... some HTML footer ...]
Obviously, replace the [...] sections with your own code. The idea is here to use PHP to output the dynamic part of your HTML code, and is the power of PHP combined with HTML.
I try to avoid "echoing" to much HTML in my PHP, but it does work (reference other answers).
Detail: when setting up a <table> you should setup a header section <thead> <tfoot> (if applicable) and body section <tbody>. Ref What is the purpose for HTML's tbody?
Basically, I want to make each tuple point to different URL so that I can view the semesters of the clicked department, and I am viewing this in a table.
I tried passing an href tag before echo in this code, but that is taking me to the same link when I press any tuple in the table.
<!Doctype html>
<table border="1" id="table">
<p>
<tr>
<th bgcolor="#9999FF">Departements</th>
</>
</tr>
<?php $servername="localhost" ; $username="root" ; $password="" ; $dbname="dbms_pro" ; // Create connection $conn=n ew mysqli($servername, $username, $password, $dbname); // Check connection if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); } $sql = "SELECT dep_name FROM department"; $result = $conn->query($sql); if ($result->num_rows > 0) { // output data of each row while($row = $result->fetch_assoc()) { echo "
<tr>
<td department:>" . $row["dep_name"]. "</tr>
</td>"; } } else { echo "0 results"; } $conn->close(); ?>
</table>
</html>
There is basically one tag in html to make hyperlinks and it is a (http://www.w3schools.com/tags/tag_a.asp):
You need to iterate over array and add a unique id to href attribute to make what you want. Example code below, however it's not good to mix html and php in one file.
<!Doctype html>
<head></head>
<body>
<table border="1" id="table">
<p>
<tr>
<th bgcolor="#9999FF">Departements</th>
</>
</tr>
<?php foreach ($departements as $row) {
echo "
<tr>
<td><a href='/department/{$row["id"]}'>{$row["dep_name"]}</tr>
</td>";
}
?>
</table>
</body>
</html>
It is showing that connection has been created. But I don't know what is the problem in query. After that query I tried to echo something and it is visible there in browser.
<html>
<head>
</head>
<body>
<?php
$servername = "localhost:8888";
$username = "root";
$password = "";
$dbname = "employees";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}else {
echo "Connected successfully";
}
$res = mysqli_query($conn,"select * from dept_manager");
echo"dept_manager";
while($row=mysqli_fetch_assoc($res))
{
?>
<table>
<tr>
<td><?php echo $row['emp_no'] ?></td>
<td><?php echo $row['dept_no']?></td>
<td><?php echo $row['from_date'] ?></td>
<td><?php echo $row['to_date'] ?></td>
</tr>
</table>
<?php
}
?>
</body>
</html>
$sql = "select * from dept_manager";
$result = $conn->query($sql);
while($row = $result->fetch_assoc()){
// your code here
}
Try with this..
Try this in the place of while loop:
<?php
$res = mysqli_query($conn,"select * from dept_manager");
echo"dept_manager";
echo "<table>";
while($row=mysqli_fetch_assoc($res))
{
echo "<tr><td>" . $row['emp_no'] . "</td><td>" . $row['dept_no'] . "</td><td>" . $row['from_date'] . "</td><td>" . $row['to_date'] . "</td></tr>";
}
echo "</table>";
?>
You have mentioned servername:localhost:8888 just check once remove
8888 and try.
I have tried with your code in my local system,same code working fine.
Just i have entered my database name and table name,it's working fine.
So you just follow my example and test once.
COde:-
<html>
<head>
</head>
<body>
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "mydashboard";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
else{
echo "Connected successfully";
}
$res = mysqli_query($conn,"select * from content_values");
while($row=mysqli_fetch_assoc($res))
{
?>
<table>
<tr>
<td><?php echo $row['name'] ?></td>
</tr>
</table>
<?php
}
?>
</body>
</html>
Output:-
Connected successfully
Name:
Test QA AndroidSD
image sampl
GMAIL
test PDF
Nat Geo Video
Recently I have been building my first website and as it is my first time working with PHP and databases I am having trouble. I have been researching for an answer for over three hours now. After following several tutorials I cannot get the databases information to display inside the table on my webpage. The only items that appear are a table header and one blank row. Am I not connecting to the database or is it something else that has to do with my code? Below is the code from the PHP that is inside my html file.
<?php
$connection = mysql_connect('localhost', 'root', '');
mysql_select_db('jcsavage_initiumjobs');
if(!$conmnection){
die('Could not connect: ' . mysql_error());
}
$result = mysql_query("SELECT name, address, ages FROM companies ORDER BY name");
?>
<table id='company_tables' border='1' align='centre'>
<tr> <th colspan='3'>Companies</th> </tr>
<tr> <th>Name of Company</th> <th>Location</th> <th>Ages Accepted</th> </tr>
<?php
while($row = mysql_fetch_array($result)){
?>
<tr><td> <?php . $row['name'] . ?> </td><td> <?php . $row['address'] . ?> </td><td> <?php . $row['ages'] . ?> </td></tr>
<?php
}
?>
</table>
<?php
mysql_close($connection);
?>
I also had a second question. What do the strings localhost and root mean? And why is the password blank? Any help is appreciated. If you need more information about my database, my website hoster, more code, or anything else, feel free to ask.
Try
<?php
while($row = mysql_fetch_array($result)){
?>
<tr><td> <?php echo $row['name']; ?> </td><td> <?php echo $row['address']; ?> </td><td> <?php echo $row['ages']; ?> </td></tr>
<?php
}
?>
$connection = mysql_connect('localhost', 'root', '');
localhost is the domain of the server that is hosting the database 'jcsavage_initiumjobs'
root is the MySQL userid that you are connecting to MySQL server with.
'' is the password, which in this case has not been set. When you set a password on the Userid 'root' you would add that instead of an empty (non existant) password
So for example if you set root's password to 'andBranch' you world code you connect as
$connection = mysql_connect('localhost', 'root', 'andBranch');
Try this code
<?php
$connection = mysqli_connect('localhost', 'root', '','jcsavage_initiumjobs');
if(!$connection){
die("Could not connect:" . mysqli_connect_error());
}
?>
<html>
<body>
<table id='company_tables' border='1' align='centre'>
<tr><th colspan='3'>Companies</th></tr>
<tr><th>Name of Company</th><th>Location</th><th>Ages Accepted</th> </tr>
<?php
$statement = "SELECT name, address, ages FROM companies ORDER BY name";
if($result = mysqli_query($connection, $statement))
{
while($data = mysqli_fetch_object($result))
{
echo "<tr><td>$data->name</td><td>$data->address</td><td>$data->ages</td></tr>";
}
}
?>
</table>
</body>
</html>