Here is
I want to show rows with same stop name one time..
How i use Query and While Loop
I see you have and id column. Assuming that it is unique you can do this all in sql query, no need for while loop.
You will need 2 queries; first will get the maximum (could be minimum also) available id of only one distinct stop name, the second is a join query with the first results and the main table. Something like this:
select * from tablename
inner join
(
select stop, max(id) as id from tablename
group by stop
)
as uniqueIDs
on tablename.id=uniqueIDs.id
u may try this..this will help you to fetch duplicates from table
SELECT tablename.stop FROM tablename INNER JOIN
(SELECT stop FROM tablename GROUP BY stop HAVING COUNT(id) > 1) dup
ON tablename.stop = dup.stop;
Related
I have the following database and want to delete the red ones because they are doubouled. So I have to check every row if another row is matching by pid, price, price_old, link and shop.
But how can I check that and how can I delete it then?
Maybe an easier way would be to generate a id from the values inside each row. So if the values inside a row would be equal also the id would be equal and who have only one value to compare with the other id's.
Is that a better way? - If yes, how can I do that?
Greetings!
Do the fact you have no way for get thi distinct row you could add uniqie id using
ALTER TABLE my_table
ADD id int NOT NULL AUTO_INCREMENT
Once done you could use not in where the id are not the min grouped by the value you need for define the duplication
delete from my_table
where id NOT in ( select min(id) from my_table
group by shop, link
)
The simplest way is to run a distinct query:
select distinct pid, price, price_old, link, shop
from t;
You can create a new table using into. That is the simplest way. Because all columns are the same, MySQL doesn't offer a simple method to delete duplicate rows (while leaving one of them).
However, it is possible that your current results are generated by a query. If so, you can just add select distinct to the query. However, it would be better to fix the query so it doesn't generate duplicates. If this is the case, then ask another question with sample data, desired results (as text, not an image), and the query you are currently using.
Test this first on a test table:
DELETE t1
FROM t t1, t t2
WHERE t1.id > t2.id AND t1.price = t2.price
AND t1.link = t2.link AND t1.shop = t2.shop
AND t1.price_old = t2.price_old;
Basically you are removing the one with the highest ID if those parameters are equal
select * from
(select pid, price, price_old, link ,
row_number() over(partition by pid, price, price_old, link, shop order by pid) as rank
from my_table) temp
where temp.rank = 1
This Query will group by all the columns first and rank them. Duplicate rows will have rank > 1. It does not matter we take first or second row as both are copy of each other. We just take rows with rank 1. Rows that are not duplicate will also be having rank 1 and hence won't be neglected.
One more way to this is by using union.
select * from my_table UNION select * from my_table
I need help with an advanced SQL-query (MSSQL 2000).
I have a table called Result that lists athletics 100 meter race-times. A runner can have several racetimes but I want to show only the best time from each runner.
The Result-table contains three columns, Result_id, athlete_id, result_time. So athlete_id must be unique when I list the values and result_time must be the fastest (lowest) value.
Any ideas?
In SQL Server 2000, you can't use windows functions. You can do this as follows:
select r.*
from result r join
(select athlete_id, min(result_time) as mintime
from result r
group by athlete_id
) rsum
on rsum.athlete_id = r.athlete_id and r.time = rsum.mintime
In more recent versions of SQL Server, you would use row_number().
If you simply need the fastest time for each athlete_id, do this:
select athelete_id, min(result_time) as FastestTime
from result
group by athelete_id
To show additional columns from the result table, you can join back to it like this:
select r.*
from result r
inner join (
select athelete_id, min(result_time) as FastestTime
from result
group by athelete_id
) rm on r.athelete_id = rm.athelete_id and r.result_time = rm.FastestTime
What you want is to use an aggregate function. in this case min() which will select the minumin data from all the rows that have the same data in the other selected columns. This means you also have to us the group by clause. The query below should give you the results you want.
Edit: If you need other columns, just bring them into the select clause, then add them to the group by clause like below:
select althlete_id, result_id, min(result_time) as result_time from result-table group by althlete_id, result_id
select althlete_id, result_id, min(result_time) as result_time, race_date from result-table group by althlete_id, race_date, result_id
Edit: You need to add all the columns into the group by that aren't part of an aggregate function. Aggregate functions are ones like min(), max(), avg() and so on.
Short answer: If you aren't putting a column in brackets, it probably has to be in the group by.
This is my query to get model information from one table and a single picture from another table. What changes do I have to make to this query in order for it to get the picture where ORDER BY sort DESC? In the table of the pictures, there is a field by the name "sort". The default value for the field for each row is 0. But one random row has the value of 1. I want to get that particular row. I don't, however, want to use WHERE sort=1 because then even in the case where no row has the sort value 1, one row should still get fetched.
$sql="SELECT tc.id,tc.alias,tc.firstname,tci.imagename
FROM ".$pre."models tc
INNER JOIN ".$pre."model_images tci ON tc.id=tci.userid
WHERE activated=1 AND sex=$sex AND city=$city AND published=1
GROUP BY tc.id ORDER BY firstname ASC";
Thank you in advance!
Solved using:
SELECT tc.id,tc.alias,tc.firstname,
(SELECT imagename FROM ".$pre."model_images WHERE userid= tc.id
ORDER BY sort DESC LIMIT 1) AS imagename
FROM ".$pre."models tc
WHERE tc.activated=1 AND tc.sex=1 AND tc.city=2 AND tc.published=1
ORDER BY tc.firstname ASC
You should place that in your WHERE clause aswell. One t hing to note though is to be carefull with the way you're using the column names. It's better to tell to which table they belong.
So this:
WHERE activated=1 AND sex=$sex AND city=$city AND published=1
Should be:
WHERE tc.activated=1 AND tc.sex=$sex AND tc.city=$city AND tc.published=1
And then simply add the 'sort' column to it:
WHERE tc.activated=1 AND tc.sex=$sex AND tc.city=$city AND tc.published=1 AND tci.sort=1
If no results are returned, then make sure that there are records that meet the required conditions. Because there's nothing wrong with the query. Try to print your query to the screen etc. to see if every variables has a value.
edit:
You should lose the GROUP BY.
SELECT tc.id,tc.alias,tc.firstname,tci.imagename
FROM ".$pre."models tc
INNER JOIN ".$pre."model_images tci ON tc.id=tci.userid
WHERE tc.activated=1 AND tc.sex=$sex AND tc.city=$city AND tc.published=1 AND tci.sort=1
I have the following results for my database table:
The Query:
SELECT
service_titles.user_id, service_titles.slide_id, service_titles.name as title_name ,service_names.name as service_name
FROM service_names
INNER JOIN service_titles ON service_names.title_id = service_titles.id
So what needs to happen is:
If the user has 2 unique service titles, then the max number of service_names for that title will be 6
If the user has 1 service title, the the max number of service_names for that title will be 16
I will be using PHP for all of the coding, but I am wondering how I would go about this. I need a way to count how many unique service_titles there are for that user and slide, and then count how many service items there are for each title.
Thanks for any help!
SELECT COUNT(DISTINCT service_titles.name)
FROM service_names
INNER JOIN service_titles ON service_names.title_id = service_titles.id
GROUP BY service_titles.user_id, service_titles.slide_id
That'll get you the number of distinct title_names for each user_id/slide_id combo.
SELECT COUNT(DISTINCT service_names.name)
FROM service_names
INNER JOIN service_titles ON service_names.title_id = service_titles.id
GROUP BY service_titles.user_id, service_titles.slide_id
... and that's the number of distinct service_names for same. If you want both in one query, you can put both COUNTs together, since you're using the same GROUP BY regardless.
You could use a CASE statement within your query to change the max number of service_names.
See MySQL CASE statement reference
To do this in the SQL itself would be quicker than evaluating it in PHP.
To count how many distinct titles you can try:
SELECT user_id, COUNT(DISTINCT name)
FROM service_titles
GROUP BY user_id
I'm using a database to store results of an election with the columns id, candidate, post_time and result. Results are put in the database during 'counting the votes'. When a new update is available, a new entry will be inserted.
From this database, I would like to create a table with the most recent results (MAX post_time) per candidate (GROUP BY candidate), ordered by result (ORDER BY result).
How can I translate this to a working SQL-statement?
(I've tried mysql order and groupby without success)
I've tried:
SELECT *, MAX(time_post)
FROM [database]
GROUP BY candidate
HAVING MAX(time_post) = time_post
ORDER BY result
Assuming that you don't have multiple results per candidate at same time, next should work:
select r.candiate, r.result
from results r
inner join (
select candidate, max(post_time) as ptime
from results
group by candidate
) r2 on r2.candiate=r.candidate and r2.ptime=r.post_time
order by r.result
Note that MAX will not select the record with the maximum time, but it will select the maximum value from any record. So
SELECT MAX(a), MAX(b) FROM example
where exmple contains the two records a=1, b=2 and a=4, b=0, will result in a=4, b=2, which wasn't in the data. You should probably create a view with the latest votes only from each candidate, then query that. For performance, it may be sensible to use a materialized view.
Is the post_time likely to be the same for all the most recent results? Also does each candidate only appear once per post_time?
This could be achieved by just using a SELECT statement. Is there a reason you need the results in a new table?
If each candidate only appears once per post_time:
SELECT candidate, result
FROM table
WHERE post_time = (SELECT MAX(post_time) FROM table)
If you want to count how many times a candidate appears in the table for the last post_time:
SELECT candidate, count(result) as ResultCount
FROM table
WHERE post_time = (SELECT MAX(post_time) FROM table)
GROUP BY candidate
By what i see from ur attempts i'd think you should use this
SELECT MAX(post_time) FROM `table` GROUP BY candidate ORDER BY result
but the MAX statment only return a single value therefore i dont see why ORDER BY would be needed.
if you want multiple results try looking up the TOP statment
One way (tied results shown):
SELECT t.*
FROM tableX AS t
JOIN
( SELECT candidate
, MAX(time_post) AS time_post
FROM tableX
GROUP BY candidate
) AS m
ON (m.candidate, m.time_post) = (t.candidate, t.time_post)
ORDER BY t.result
and another one (no ties, only one row per candidate shown):
SELECT t.*
FROM
( SELECT DICTINCT candidate
FROM tableX
) AS d
JOIN
tableX AS t
ON t.PK = --- the Primary Key of the table, here
( SELECT ti.PK --- and here
FROM tableX AS ti
WHERE ti.candidate = d.candidate
ORDER ti.time_post DESC
LIMIT 1
)
ORDER BY t.result