Simplifying my JSON to build a array. - php

Question

I am trying to take my JSON input and generate a easy array to search in, but it is as far as I can tell giving me some trouble.
First of, this is my JSON as is, loaded from a file:
{
"teams": [
{
"id": "1",
"boat": "Test",
"name": "Palle Test"
},
{
"id": "2",
"boat": "Test 2",
"name": "Name Test 2"
},
{
"id": "3",
"boat": "Test 3",
"name": "Name Test 3"
},
{
"id": "4",
"boat": "Test 4",
"name": "mller"
}
]
}
Is there a way to simplify this or minimise the number of arrays?
I have been using the following code to preview my array, but I am trying to get it to search for id and then print the values for id, boat and name.
$json_url = "teams.json";
$json = file_get_contents($json_url);
$data = json_decode($json, TRUE);
echo '<pre>';
print_r($data);
echo '</pre>';

Answer 1

This is really quite simple. There is no need to convert a perfectly good object into an array, it only makes life more complex.
The only array you have in your data structure is the teams array and that is easily processed like this
$json = '{
"teams": [
{
"id": "1",
"boat": "Test",
"name": "Palle Test"
},
{
"id": "2",
"boat": "Test 2",
"name": "Name Test 2"
},
{
"id": "3",
"boat": "Test 3",
"name": "Name Test 3"
},
{
"id": "4",
"boat": "Test 4",
"name": "mller"
}
]
}';
$data = json_decode($json);
//print_r($data);
foreach ($data->teams as $object) {
if ( $object->id == 2) {
echo 'boat is ' . $object->boat . ' and name is ' . $object->name . PHP_EOL;
}
}
And the result of the above example would be
boat is Test 2 and name is Name Test 2