How to remove the Square Bracket in JSON using PHP - php

Question

Below code is the returned JSON
[{"one":"id","two":"id","three":"id"},{"one":"id","two":"id","three":"id"}]
Below code is the desired result of the returned JSON (without the array bracket)
{"one":"id","two":"id","three":"id"},{"one":"id","two":"id","three":"id"}
Below code is to convert the array to the JSON format
include('connect-db.php');
$result = mysql_query("SELECT * FROM patientvaccinedetail");
$specific = [];
while($row = mysql_fetch_array( $result ,MYSQL_ASSOC)) {
echo "<tr>";
echo '<td width="100px">' . $row['id'] . '</td>';
echo '<td width="200px">' . $row['patientid'] . '</td>';
echo '<td width="200px">' . $row['vaccineid'] . '</td>';
//**********Convert the array into json*******************
$specific[] = ["one" => $row["id"],
"two" => $row["patientid"],
"three" => $row["vaccineid"]];
$result = json_encode($specific,JSON_UNESCAPED_UNICODE);
echo $result;
echo "</tr>";
echo "</table>";
?>
To send the request to the API, iam using Guzzle
And the format the API require is {xx:xx},{xx:xx}
without the square bracket, any idea how to remove it using PHP.
Thanks in advance
$client = new Client([
'headers' => ['Content-Type' => 'application/json',
'Token' => $token]
]);
$response = $client->post('http://localhost:91/Religious',
['body' => ***Where the json will be place***]
);

Answer 1

I read a nice solution in the comments of the first post by deceze ♦ with trim().
$yourJson = trim($yourJson, '[]');
You can also use regular expression:
// if nothing is found, your json has already no brackets or is invalid.
if (preg_match('/^\[(.+)\]$/', $yourJson, $new))
{
/**
* $new[0] = $yourJson
* $new[1] = what's in the parenthesis
*/
$yourJson = $new[1];
}
Or, you may use substr():
$yourJson = substr($yourJson, 1, strlen($yourJson) - 2);
EDIT:
When it says in the request body format : application/json, I do not think that you have to remove the brackets. Did you even try with them?

Answer 2

You are trying to convert a PHP array to a JSON array, so php wrap the result in brackets, it's totally normal. If you need a JSON object Then I would suggest to use JSON_FORCE_OBJECT as additional option(parameters) in json_encode.
$object = json_encode($array, JSON_FORCE_OBJECT);

Answer 3

Try this
str_replace(array('[', ']'), '', htmlspecialchars(json_encode($result), ENT_NOQUOTES));

Answer 4

You might need to use the implode function after a json decode. for example:
implode(',',json_decode($text_from_db or $array))
for example $text_from_db=["rice","beans"]
the result will be- rice,beans

Answer 5

you can trimit see example below
trim($data, '[]')

Answer 6

I've added comments as to what the OP is trying to do. But here's my solution for future visitors of this question.
class Thing implements \JsonSerializable
{
private $name;
private $description;
private $code;
/**
* Get the value of name
*/
public function getName()
{
return $this->name;
}
/**
* Set the value of name
*
* #return self
*/
public function setName($name)
{
$this->name = $name;
return $this;
}
/**
* Get the value of description
*/
public function getDescription()
{
return $this->description;
}
/**
* Set the value of description
*
* #return self
*/
public function setDescription($description)
{
$this->description = $description;
return $this;
}
/**
* Get the value of code
*/
public function getCode()
{
return $this->code;
}
/**
* Set the value of code
*
* #return self
*/
public function setCode($code)
{
$this->code = $code;
return $this;
}
public function jsonSerialize()
{
$vars = get_object_vars($this);
return $vars;
}
}
$thing = new Thing();
$thing->setName('Name');
$thing->setDescription('Description');
$thing->setCode('Code');
$results['items'] = [
'thing1' => $thing,
'thing2' => $thing
];
echo json_encode($results);
Here's the output
{
"items": {
"thing1": {
"name": "Name",
"description": "Description",
"code": "Code"
},
"thing2": {
"name": "Name",
"description": "Description",
"code": "Code"
}
}
}

Answer 7

This will remove the outer wrapper without disturbing any inner wrappers:
$wrapped = <<<EOD
[{"one":"id","two":"id","three":"id"},{"one":"id","two":"id","three":"id"}]
EOD;
$array = json_decode($wrapped, true);
$unwrapped = json_encode($array, JSON_FORCE_OBJECT);
print_r($unwrapped);
// {"0":{"one":"id","two":"id","three":"id"},"1":{"one":"id","two":"id","three":"id"}}

Answer 8

My suggestion is to use JSON string and perform String operations to remove all those not required characters.
Reason for doing this, the required output is not a valid JSON and won't be accepted by API. As you need it however, I would suggest you to convert the array into json using json_encode and then perform string operations to convert it into your desired output.